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Aleonysh [2.5K]

1 year ago

6

An object with a heat capacity of 345J∘C experiences a temperature change from 88.0∘C to 45.0∘C. How much heat is released in th

is process, in joules?

1 answer:

pogonyaev1 year ago

5 0

Answer:

There is 148.35 Joules of heat is released in the process.

Explanation:

Given that,

Heat capacity of the object, $c=345J/^oC$

Initial temperature, $T_i=88^{\circ}C$

Final temperature, $T_f=45^{\circ}C$

We need to find the amount of heat released in the process. It is a concept of heat capacity. The heat released in the process is given by :

$Q=mc\Delta T$

Let the mass of the object is 10 g or 0.01 kg

So,

$Q=0.01\times 345\times (88-45)$

Q = 148.35 Joules

So, there is 148.35 Joules of heat is released in the process. Hence, this is the required solution.

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The correct answer to the question is : 29.88 m.

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Kinetic energy at the bottom of the cliff = potential energy at a height h

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Answer:

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$c_{m}$ = specific heat of lump of metal = 0.25 cal/g°C

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$c_{w}$ = specific heat of water = 1 cal/g°C

$T_{wi}$ = Initial temperature of water = 20 °C

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$c_{c}$ = specific heat of calorimeter = 0.10 cal/g°C

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Using conservation of heat

Heat lost by lump of metal = heat gained by water + heat gained by calorimeter

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