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Vlada [557]
1 year ago
12

An electric clock is hanging on a wall. As you are watching the second hand rotate, the clock's battery stops functioning, and t

he second hand comes to a halt over a brief period of time. Which one of the following statements correctly describes the angular velocity w and angular acceleration of the second hand as it slows down?
A. W and a are both negative
B. W is positive and a is negative
C. W is negative and a is positive
D. w and a are both positive
Physics
1 answer:
Setler [38]1 year ago
8 0

Answer:

B. W is positive and a is negative

Explanation:

As we know that the angular speed of the second clock is in positive direction so as it comes to halt from its initial direction of motion then we have

initial angular velocity is termed as positive angular velocity

\omega = positive

now it comes to stop so angular acceleration is taken in opposite to the direction of angular speed

so we will have

\alpha = negative

so here correct answer is

B. W is positive and a is negative

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The strength of the gravitational field of a source mass can be measured by the magnitude of the acceleration due to gravity at
Svetradugi [14.3K]

Answer:

9.79211 m/s²

Explanation:

M = Mass of the Earth =  5.972 × 10²⁴ kg

G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²

r = Radius of Earth = 6378000 m

g=G\frac{M}{r^2}\\\Rightarrow g=6.67\times 10^{-11}\frac{5.972\times 10^{24}}{(6378000)^2}\\\Rightarrow g=9.79211\ m/s^2

The acceleration due to gravity is 9.79211 m/s²

For any distance above the Earth's surface h

g=6.67\times 10^{-11}\frac{5.972\times 10^{24}}{(6378000+h)^2}\\\Rightarrow g=\frac{3.983324\times 10^{14}}{6378000+h}\ m/s^2

5 0
2 years ago
In the following equations, the distance x is in meters, the time tin seconds. and the velocity v is in meters per second. whata
lyudmila [28]

Answer:

A) c₁ = m, c₂ = m/s

B) c₁ = m/s²

C) c₁ = m/s²

D) c₁ = m/s c₂ = °

E) c₁ = m/s , c₂ = /s

Explanation:

A) x = c₁ + c₂t

⇒m = m + (m/s)s (Only same units can be added)

⇒m = m

So, c₁ = m, c₂ = m/s

B) x = 0.5c₁t²

⇒m = 0.5 (m/s²)s²

⇒m = m

So, c₁ = m/s²

C) v² = 2c₁x

⇒m²/s² = 2 (m/s²)m

⇒m²/s² = m²/s²

So, c₁ = m/s²

D) x = c₁ cos(c₂)t

⇒m = (m/s) cos(°)s

⇒m = m

So, c₁ = m/s c₂ = °

E) v² = 2c₁v-(c₂x)²

⇒m²/s² = 2(m/s)(m/s)-(1/s²)(m²)

⇒m²/s² =m²/s²

So, c₁ = m/s , c₂ = /s

3 0
1 year ago
Read 2 more answers
A box with a mass of 12.5 kg sits on the floor. how high would you need to lift it for it to have a gpe of 355 j
grandymaker [24]
Gpe=mgh

355=12.5×10×h
h=355/125= 2.84m
3 0
2 years ago
Brad is working on a speed problem in physics class. The problem tells him that a girl runs from her house to the park 0.05 km a
Dmitriy789 [7]
It is corecct becasue it 10 s more added from 0.05
7 0
1 year ago
Read 2 more answers
A 50-kg meteorite moving at 1000 m/s strikes Earth. Assume the velocity is along the line joining Earth's center of mass and the
wel

Answer:

a)  amount of kinetic energy converted to internal energy  = 2.5 x 10 raised to power 7 Joule

b) Kinetic energy gained by the earth = 2.1 x 10-16J

c) All the kinetic energy is converted to internal energy and the energy is further converted to thermal energy hence the reason for the hotness at around where the meteorite strikes.

Explanation:

The detailed steps and appropriate application of the law of conservation of momentum is as shown in the attached file.

3 0
2 years ago
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