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Anastaziya [24]
2 years ago
13

A 50-kg meteorite moving at 1000 m/s strikes Earth. Assume the velocity is along the line joining Earth's center of mass and the

meteor's center of mass.
(a) Calculate the amount of kinetic energy converted to internal energy measured Irk in., the Earth reference frame.
(b) What is the gain in Earth's kinetic energy?
(c) Why does the ground around where the meteor strikes get so hot?

Physics
1 answer:
wel2 years ago
3 0

Answer:

a)  amount of kinetic energy converted to internal energy  = 2.5 x 10 raised to power 7 Joule

b) Kinetic energy gained by the earth = 2.1 x 10-16J

c) All the kinetic energy is converted to internal energy and the energy is further converted to thermal energy hence the reason for the hotness at around where the meteorite strikes.

Explanation:

The detailed steps and appropriate application of the law of conservation of momentum is as shown in the attached file.

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Answer:

v = 4.08m/s₂

Explanation:

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1 year ago
If an otherwise empty pressure cooker is filled with air of room temperature and then placed on a hot stove, what would be the m
ehidna [41]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The force on the lid when the air inside the cooker had been heated to 120°C is =  0.34P_{a}A

The force on the lid when the air inside the cooker had been heated to 20°C is = 0.25P_{a}A

The

Explanation:

The main concept used to solve this problem is Pressure-Temperature Law.

Initially, find the pressure inside the pressure cooker by using the Pressure-Temperature Law. Then, find the force exerted by the air inside cooker on the lid of the cooker.

Fundamentals :

The Pressure-Temperature Law states that the pressure of the of a given gas held at constant volume is directly proportional to the Kelvin temperature. The increase in pressure results in an increase in the temperature and vice-versa.

The expression of the Pressure-Temperature Law is as follows:

\frac{P_{1}}{P_{2}} =\frac{P_{2}}{T_{2}}

Here, P_{1} and P_{2}

are the initial and final pressures and T_{1} and T_{2}

are the initial and final temperatures respectively.

The force in terms of pressure can be given by the following expression.  

F=(ΔP) A

Here, A is the area on which the pressure is applied and ΔP is the change in pressure

The step- step calculation is shown on the second,third,fourth, fifth image

Note: P_{a} is the pressure of atmosphere

6 0
2 years ago
What is the effect of the following change on the volume of 1 mol of an ideal gas? The initial pressure is 722 torr, the final p
Ray Of Light [21]

Answer:

A. Volume is unchanged

Explanation:

P_{i} = initial pressure of the gas = 722 torr = 96258.7 pa

P_{f} = final pressure of the gas = 0.950 atm = 96258.75 pa

T_{i} = initial temperature = 32 °F = 272.15 K

T_{f} = final temperature = 273 K

V_{i} = initial volume

V_{f} = final volume

Using the Equation

\frac{P_{i} V_{i}}{T_{i}} = \frac{P_{f} V_{f}}{T_{f}}

Inserting the values

\frac{(96958.7) V_{i}}{272.15} = \frac{(96958.75) V_{f}}{273}

V_{f} = (1.00312) V_{i}

Hence the volume is unchanged.

4 0
2 years ago
Vector A⃗ has a magnitude of 3.00 and is directed parallel to the negative y-axis and vector B⃗ has a magnitude of 3.00 and is d
tangare [24]

<u>Answer</u>

C = 6.00; θ = 270˚

<u>Explanation</u>

A vector is described by giving both its magnitude and direction.

A = 3.00; 270°

B = -3.00; 90°

C = A - B. From this expression, it can be seen that we have already reversed the direction of B. So vector C is in the direction of A.

C = A - B

C = 3.00 - (-3.00)

= 6.00


3 0
2 years ago
Read 2 more answers
ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself o
shtirl [24]

Q: ken, 0.75 kg, moves toward a wall (his path normal to the wall) at 52 m/s. 13.0 ms after he touches the wall he pushes himself off in the opposite direction at 60 m/s. What is the magnitude of the average force the wall exerts on Ken during this rapid maneuver

Answer:

-6461.54 N

Explanation:

From Newton's Fundamental equation,

F = m(v-u)/t.................... Equation 1

Where F = Force exerted in sonic, m = mass of ken, v = final velocity, u = initial velocity, t = time.

Given: m = 0.75 kg, v = - 60 m/s (opposite direction), u = 52 m/s, t = 13 ms = 0.013 s

Substitute into equation 1

F = 0.75(-60-52)/0.013

F = 0.75(-112)/0.013

F = -84/0.013

F = -6461.54 N

Note: The negative sign tells that the force act in opposite direction to the initial motion of ken.

Hence the magnitude of the average force of the wall = -6461.54 N

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