answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Leona [35]
2 years ago
8

in a hydraulic press the small cylinder has a diameter 10.0cm while the large has 25cm if the force of 600N is applied to the sm

all cylinder. find the force exacted on the large cylinder
Physics
2 answers:
Butoxors [25]2 years ago
8 0

Answer:

3750 N

Explanation:

Pressure on the small cylinder = pressure on the large cylinder

P₁ = P₂

F₁ / A₁ = F₂ / A₂

F₁ / (π d₁² / 4) = F₂ / (π d₂² / 4)

F₁ / d₁² = F₂ / d₂²

600 N / (10.0 cm)² = F / (25.0 cm)²

F = 3750 N

oee [108]2 years ago
8 0

Answer:

3751.34N

Explanation:

Pressure in large piston = pressure in smaller piston

P2 = P1

Pressure = Force / Area

Area = pi * r²

r1= d1/2 = 10/ 2 = 5cm = 0.05m

Area(A1) = 22/7 * (0.05)² = 0.00785m²

r2 = d2 / 2 = 25/2 = 12.5cm = 0.125m

Area(A2) = 22/7 * (0.125)² = 0.04908m²

Pressure = Force / Area

F1/A1 = F2/A2

600 / 0.00785 = F2 / 0.04908

F2 = (600 * 0.04908) / 0.00785

F2 = 3751.34N

You might be interested in
The cockroach Periplaneta americana can detect a static electric field of magnitude 8.50 kN/C using their long antennae. If the
otez555 [7]

Answer:

0.647 nC

Explanation:

The force experienced by a charge due to the presence of an electric field is given by

F=qE

where

q is the charge

E is the magnitude of the electric field

In this problem, each antenna is modelled as it was a single point charge, experiencing a force of

F=5.50\mu N = 5.50\cdot 10^{-6} N

Therefore, if the electric field magnitude is

E=8.50 kN/C = 8500 N/C

Then the charge on each antenna would be

q=\frac{F}{E}=\frac{5.50\cdot 10^{-6} N}{8500 N/C}=6.47\cdot 10^{-10} C = 0.647 nC

8 0
2 years ago
A hockey stick strikes a hockey puck of mass 0.17 kg. If the force exterted on the hockey puck is 35.0 N and there is a force of
GREYUIT [131]

Answer:

a=190\ m/s^2

Explanation:

Mass of a hockey puck, m = 0.17 kg

Force exerted by the hockey puck, F' = 35 N

The force of friction, f = 2.7 N

We need to find the acceleration of the hockey puck.

Net force, F=F'-f

F=35-2.7

F=32.3 N

Now, using second law of motion,

F = ma

a is the acceleration of the hockey puck

a=\dfrac{F}{m}\\\\a=\dfrac{32.3}{0.17}\\\\a=190\ m/s^2

So, the acceleration of the hockey puck is 190\ m/s^2.

5 0
2 years ago
Raphael refers to a wave by noting its wavelength. lucinda refers to a wave by noting its frequency. which student is correct an
blsea [12.9K]
They are both right because you can note both things, I mean Raphael and Lucinda, both has a right statement or explanation about the wave. Wave by nothing is both for its wavelength and for its frequency. So Raphael and Lucinda are both correct because you can note both wavelength and frequency.
7 0
2 years ago
a film of transparent material 120 nm thick and having refractive index 1.25 is placed on a glass sheet having refractive index
Eva8 [605]

Answer:

a) 600nm

b) 300nm

Explanation:

the path difference = 2t  

t = thickness of the film

L' = wavelength of light in film = L/n

L = wavength of light in air

n = refractive index of glass

(a)

for destructive interference 2t = L'/2 = L/2n

L = 4*t*n

= 4*120*10^-9*1.25  

L = 600 nm

(b)

for constructive interference 2t = L' = L/1.25

L = 2tn

= 2 × 1.25 ×  120nm

= 300 nm

4 0
2 years ago
Two hockey players skating on essentially frictionless ice collide head-on. Madeleine, of mass 65.0 kg, is moving at 6.00 m/s to
xeze [42]

Explanation:

It is given that,

Mass of Madeleine, m_1=65\ kg

Initial speed of Madeleine, u_1=6\ m/s (due east)

Final speed of Madeleine, v_1=-3\ m/s (due west)

Mass of Buffy, m_2=55\ kg

Final speed of Buffy, v_2=3.5\ m/s (due east)

Let u_1 is the Buffy's velocity just before the collision. Using the conservation of linear momentum as :

m_1u_1+m_2u_2=m_1v_1+m_2v_2

65\times 6+55\times u_2=65\times (-3)+55\times 3.5

u_2=-7.13\ m/s

So, the initial speed of the Buffy just before the collision is 7.13 m/s and it is moving due west. Hence, this is the required solution.

5 0
2 years ago
Other questions:
  • The wavelength of some red light is 700.5 nm. what is the frequency of this red light?
    15·1 answer
  • The image shows an example of white light entering a prism and coming out as colors of the rainbow. How does a prism a produce t
    11·2 answers
  • If a 1.50 kg mass revolves at the end of a string 0.50 m long, and its tangential speed is 6.0 m/s, calculate the centripetal fo
    11·2 answers
  • Ba-11 when passing through a lock, which light means "approach the lock under full control?"
    9·2 answers
  • Two roads intersect at right angles, one going north-south, the other east-west. an observer stands on the road 60 meters south
    15·2 answers
  • A block moves at 5 m/s in the positive x direction and hits an identical block, initially at rest. A small amount of gunpowder h
    10·1 answer
  • A piece of copper of mass 100 g is being drilled through with a 1/2" electric drill. The drill operates at 40.0 W and takes 30.0
    15·1 answer
  • Would an oil ship moving at a speed of 10km/h have more or less momentum than a car moving at a speed of 100km/h? Explain your a
    15·2 answers
  • You are attending a county fair with your friend from your physics class. While walking around the fairgrounds, you discover a n
    12·1 answer
  • A ping-pong ball weighs 0.025 N. The ball is placed inside a cup that sits on top of a vertical spring. If the spring is compres
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!