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1 year ago

one horsepower is a unit of power equal to 746w. how much energy can a 150-horsepower engine transform in 10.0s?

1 answer:

8 0

1 watt = 1 joule/second

1 horsepower = 746 watts = 746 joule/second

(150 horsepower) x (746 watt/HP) x (1 joule/sec / watt) x (10 sec)

= (150 x 746 x 1 x 10) joule = 1,119,000 joules .
if correct plz mark brainly

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Of the three primary forms of subaerial volcanoes, ________ are large cone-shaped mountains that consist of alternating layers o

Alborosie

Answer:

Strato-volcano

Explanation:

Strato-volcanoes are usually characterized by the presence of steep-sided slopes, with distinct craters, and are frequently erupted and conical in appearance. This type of volcano is generally felsic in nature. Due to the presence of high silica content, the magma being highly viscous, moves at a relatively slower rate. These are highly explosive and produce a large number of pyroclastic materials, lava flow, volcanic ashes, and gases.

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1 year ago

A 1.00 kg ball traveling towards a soccer player at a velocity of 5.00 m/s rebounds off the soccer

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Answer:

A) F = - 8.5 10² N, B) I = 21 N s

Explanation:

A) We can solve this problem using the relationship of momentum and momentum

I = Δp

in this case they indicate that the body rebounds, therefore the exit speed is the same in modulus, but with the opposite direction

v₀ = 8.50 m / s

v_f = -8.50 m / s

F t = m v_f -m v₀

F = $m \frac{(v_f - v_o)}{t}$

let's calculate

F = $1.00 \ \frac{(-8.5-8.5)}{2 \ 10^{-2}}$

F = - 8.5 10² N

B) let's start by calculating the speed with which the ball reaches the ground, let's use the kinematic relations

v² = v₀² - 2g (y- y₀)

as the ball falls its initial velocity is zero (vo = 0) and the height upon reaching the ground is y = 0

v = $\sqrt{2g y_o}$

calculate

v = $\sqrt{2 \ 9.8 \ 10}$

v = 14 m / s

to calculate the momentum we use

I = Δp

I = m v_f - mv₀

when it hits the ground its speed drops to zero

we substitute

I = 1.50 (0-14)

I = -21 N s

the negative sign is for the momentum that the ground on the ball, the momentum of the ball on the ground is

I = 21 N s

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1 year ago

In this lab you will use a cart and a track to explore Newton's second law of motion. You will vary two different variables and

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Answer:

Newtons II law:

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Let us assume that,a string is attached to the cart, which passes over a pulley along the track. At another end of the string a weight is attached which hangs over the pulley. The hanging weight provides tension in the spring, and it helps in accelerating the cart. We assume that the string is massless and no friction between pulley and the string.

Whenever the hanging weight moves downwards, the cart will accelerate to right side.

For the hanging weight/mass

When hanging weight of mass is m₁ and accelerate due to gravitational force g.

Therefore we can write F = m₁ .g

and the tension acts in upward direction T (negetive)

Now, Fnet = m₁ .g - T

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1 year ago

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A boat is headed with a velocity of 18 meters/second toward the west with respect to the water in a river. If the river is flowi

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If the boat's velocity is 18m/sec relative to the water in the river and not the shore, it would need to be added the river speed of 2.5m/sec to get a total of 20.5m/sec. The 20.5m/sec would then be the total velocity of the boat relative to the shore. From personal experience, I know that when one runs with the tide, one is adding the tide flow speed to one's boat speed (what it would be in neutral waters) to get a sometimes much faster speed.

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1 year ago

A plane wall with constant properties is initially at a uniform temperature To. Suddenly, the surface at x = L is exposed to a c

Rzqust [24]

Answer:

The distribution is as depicted in the attached figure.

Explanation:

From the given data

The plane wall is initially with constant properties is initially at a uniform temperature, To.
Suddenly the surface x=L is exposed to convection process such that T∞>To.
The other surface x=0 is maintained at To

Uniform volumetric heating q' such that the steady state temperature exceeds T∞.

Assumptions which are valid are

There is only conduction in 1-D.
The system bears constant properties.
The volumetric heat generation is uniform

From the given data, the condition are as follows

Initial Condition

At t≤0

$T(x,0)=T_o$

This indicates that initially the temperature distribution was independent of x and is indicated as a straight line.

Boundary Conditions

At x=0

$T(0,t)=T_o$

This indicates that the temperature on the x=0 plane will be equal to To which will rise further due to the volumetric heat generation.

At x=L

$-k\frac{\partial T}{\partial x}]_{x=L}=h[T(L,t)-T_{\infty}]$

This indicates that at the time t, the rate of conduction and the rate of convection will be equal at x=L.

The temperature distribution along with the schematics are given in the attached figure.

Further the heat flux is inferred from the temperature distribution using the Fourier law and is also as in the attached figure.

It is important to note that as T(x,∞)>T∞ and T∞>To thus the heat on both the boundaries will flow away from the wall.

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2 years ago