answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Alexxx [7]
1 year ago
10

A fox locates rodents under the snow by the slight sounds they make. The fox then leaps straight into the air and burrows its no

se into the snow to catch its meal. If a fox jumps up to a height of 85 cm , calculate the speed at which the fox leaves the snow and the amount of time the fox is in the air. Ignore air resistance.

Physics
1 answer:
Pachacha [2.7K]1 year ago
4 0

Answer:

v = 4.08m/s₂

Explanation:

You might be interested in
An initially neutral glass rod is rubbed with silk. It becomes positively charged by_____.a) electrons are created on the rod.
Dimas [21]

Answer:

e) electrons are transferred from the rod to the silk.

Explanation:

An initially neutral glass rod contains equal number of electron and proton.

If the rod becomes positively charged  after being rubbed with silk, then the rod must have lost some its electron to the silk since electrons are more mobile than protons, leaving the rod with excess positive charge (protons), and the silk will be negatively charged (excess electron).

Thus, the rod becomes positively charged by transfer of electrons from rod to the silk.

e) electrons are transferred from the rod to the silk.

3 0
2 years ago
Suppose that air resistance cannot be ignored. For the position at which the person has jumped from the platform and the cord re
Kamila [148]

Answer:

The stretch cord stores potential energy as a result of stretching but due to kinetic energy, it will move back to its original state. Since air resistance is not being ignored in this case, it will experience a slight delay in stretching at first.

Explanation:

In case, where air resistance is being ignored the stretch cord will stretch as it normally does.              

  • Air resistance is a force that any object experiences as a result of its motion through the air.  

There are various factors that affect air resistance like speed, the density of air, area, the shape of an object etc. Meanwhile, the density of air changes with temperature or altitude. <em>Hence this force is not constant but is thought to be constant during short time frames.  </em>

6 0
1 year ago
Water flows without friction vertically downward through a pipe and enters a section where the cross sectional area is larger. T
djverab [1.8K]

Answer:

v_{2} will be less than v_{1} and P_{2} will be greater than P_{1}.

Explanation:

As we know from the conservation of mass, the rate at which any amount of fluid mass (m_{1}) is entering in a system is equal to the rate at which the same amount of fluid mass (m_{2}) is leaving the system.

Rate of mass flow can be written as,

m = \rho A v

where \rho is the density of the fluid, A is the area through which the fluid is flowing and v is the velocity of the fluid.

Now, according to the problem, as the density of the fluid does not change, we can write

&& m_{1} = m_{2}\\&or,& \rho A_{1} v_{1} = \rho A_{2} v_{2}\\&or,& \dfrac{v_{2}}{v_{1}} = \dfrac{A_{1}}{A_{2}}

where A_{1} and A_{2} are the cross-sectional areas through which the fluid is passing and v_{1} and v_{2} are the velocities of the fluid through the respective cross-sectional areas.

As according to the problem, A_{2} > A_{1}, so from the above formula v_{2} < v_{1}.

Also we know that fluid pressure is created by the motion of the fluid through any area. When the fluid gains speed, some of its energy is used to move faster in the fluid’s direction of motion. It causes in a lower pressure.

So, as in this case v_{2} < v_{1} the pressure in the large cross-sectional area P_{2} will be greater than the pressure  P_{1} in the small cross sectional area, i.e.,

P_{2} > P_{1}.

6 0
2 years ago
What do nuclear scientists call a stick of uranium?
nikitadnepr [17]
They call it "rod" or "fission rod". This is because the uranium is the element used for the nuclear fission, where the uranium nuclei disintegrate producing lighter nuclei and energy.
6 0
2 years ago
Read 2 more answers
Three balls are in water. Ball 1 floats, with half of it exposed above the water level. Ball 2, with a density less than the den
Ymorist [56]

Answer:

The magnitude of buoyancy force is equal to that of ball's weight.

Explanation:

Ball 1 is floating on water. Weight of ball 1 is Fg=m1g  is acting vertically downward

Force of buoyancy FB = ρVdisg is acting vertically upward.

Net force acting on the ball is zero, FB=Fg

Answer

The magnitude of buoyancy force is equal to that of ball's weight.

4 0
2 years ago
Read 2 more answers
Other questions:
  • Pressure and volume changes at a constant temperature can be calculated using
    8·1 answer
  • The drawing shows the top view of a door that is 1.68 m wide. two forces are applied to the door as indicated. what is the magni
    14·1 answer
  • Large-scale environmental catastrophes _______.
    13·1 answer
  • A satellite completes one revolution of a planet in almost exactly one hour. At the end of one hour, the satellite has traveled
    5·1 answer
  • A glass jug can be used to play different pitched sounds by blowing air over the opening of the jug and vibrating the air molecu
    7·1 answer
  • The measure of one of the small angles of a right triangle is 45 less than twice the measure of the other small angle. Find the
    14·1 answer
  • ANSWER BELOW QUESTIONS:
    12·2 answers
  • Which of the following statements about electric field lines associated with electric charges is false? Electric field lines can
    12·1 answer
  • An engineer wants to design an oval racetrack such that 3.20 × 10 3 lb racecars can round the exactly 1000 ft radius turns at 10
    12·1 answer
  • the initial kinetic energy of an object moving on a horizontal surface is K. Friction between the object and the surface causes
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!