answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Volgvan
2 years ago
12

An engineer wants to design an oval racetrack such that 3.20 × 10 3 lb racecars can round the exactly 1000 ft radius turns at 10

2 mi/h without the aid of friction. She estimates that the cars will round the turns at a maximum of 175 mi/h. Find the banking angle θ necessary for the race cars to navigate the turns at 102 mi/h without the aid of friction.
Physics
1 answer:
Reptile [31]2 years ago
4 0

Answer:

The banking angle necessary for the race cars is 34.84°

Explanation:

For normal reaction the expression is:

\\Nsin\theta = \frac{mv^{2} }{R}  =Fc\\tan\theta =\frac{v^{2} }{Rg}  \\\theta =tan^{-1} (\frac{v^{2} }{Rg} )\\\theta =tan^{-1} (\frac{(102*0.447)^{2} }{1000*0.3048*9.8} )=34.84

You might be interested in
A 3.00-kg ball swings rapidly in a complete vertical circle of radius 2.00 m by a light string that is fixed at one end. The bal
Setler [38]

Answer

given,

mass of the ball = 3 kg

swing in vertical circle with radius = 2 m

   work done by the gravity = ?          

   work done by the tension = ?            

Work done by the gravity = - m g Δh            

 Δ h = 2 + 2 = 4 m                                                                

Work done by the gravity =- 3 \times 9.8 \times 4

                                           = -117.6 J                  

work done by gravity is equal to -117.6 J            

Work done by tension will be equal to zero.        

Zero because tension is always perpendicular to velocity

work done by tension is equal to 0 J                          

7 0
2 years ago
PLEASE HELP!!!!!! WILL GIVE BRAINLIEST TO WHOEVER ANSWERS WITH THE RIGHT ANSWER !!!!!!!! 
Solnce55 [7]

It would be B and D your welcome


7 0
2 years ago
Read 2 more answers
Two 8.0 Ω lightbulbs are connected in a 12 V series circuit. What is the power of both glowing bulbs?
V125BC [204]

Answer:

18 W

Explanation:

Applying,

P = V²/R.................. Equation 1

Where P = Power of both glowing bulbs, V = Voltage, R = Combined Resistance of both bulbs

Since: It is a series circuit,

Then,

R = R1+R2............. Equation 2

Where R1= Resistance of the first bulb, R2 = Resistance of the second bulb

Given: R1 = R2 = 8 Ω

Substitute into equation 1

R = 8+8

R = 16 Ω

Also Given: V = 12 V

Substitute into equation 1

P = 12²/8

P = 144/8

P = 18 W

7 0
2 years ago
A dog travels north for 18 meters, east for 8 meters, South for 27 meters and then west for 8 meters. What is the distance the d
Afina-wow [57]
I'm really not sure if this is right but I'll try.
The distance that the dog traveled is probably all of the distances added up. I would guess that it's 67 meters in total. 
The displacement is a little more tricky but you pretty much have to put a mental map in your head. Since East and West are both 8 meters, they cancel each other out. He travels more southern and that means the displacement is 9 meters south of his original location
7 0
2 years ago
Jeremy accidently dropped his toy stuffed animal from the balcony of his apartment on the fourth floor. The toy hit the ground a
LekaFEV [45]
According to the second law of motion, force is the product of mass times acceleration. If we were to solve for the force, we would need the acceleration and the mass. 

Acceleration was not given in the problem, but we can solve for it by using the velocity and the time because by definition, acceleration is the change in velocity over time. 

a =  \frac{vf-vi}{t}

The initial velocity is 16.0m/s because it is the first recorded time. The final is 0 m/s or the last recorded velocity. The time we will use is 2.0 s because it is the time the change in velocity occurred. 

a = \frac{vf-vi}{t}
a = \frac{0m/s-16.0m/s}{2.0s}
a = \frac{-16.0m/s}{2.0s}
a=-8.0m/ s^{2}

Now that we have acceleration, we can now solve for the Force. Again Force is the product of mass and acceleration. 

F=ma
F=(0.25kg)(-8.0m/ s^{2} )
F=-2kg.m/ s^{2} ) or -2N

The force is -2N. Now if you are looking for the magnitude of the force then you can just put 2N.

The negative sign indicates the direction of the force, if it is negative this means that the force applied was in the opposite direction.  

4 0
2 years ago
Other questions:
  • A ball rolls 6.0 meters as its speed changes from 15 meters per second to 10 meters per second. What is the average speed of the
    12·1 answer
  • In the example pictured, the soda bottle would act as the?
    6·2 answers
  • A 55-kg box is being pushed a distance of 7.0 m across the floor by a force whose magnitude is 160 N. The force is parallel to t
    9·1 answer
  • For years, space travel was believed to be impossible because there was nothing there Rockets could push off in space in order t
    8·1 answer
  • A 0.60-kilogram softball initially at rest is hit with a bat. The ball is in contact with the bat for 0.20 second and leaves the
    15·1 answer
  • Seema knows the mass of basketball. What other information is needed to find the balls potential energy
    5·2 answers
  • Water flowing through a cylindrical pipe suddenly comes to a section of pipe where the diameter decreases to 86% of its previous
    12·1 answer
  • A student redid the experiment of mixing room-temperature water and warm
    11·1 answer
  • If Katie swims from one end of the pool, to the other side, and then swims back to her original spot, her average velocity is ha
    15·1 answer
  • When you are standing on Earth, orbiting the Sun, and looking at a broken cell phone on the ground, there are gravitational pull
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!