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Vlad [161]
2 years ago
7

A force of 20N changes the position of a body. If mass of the body is 2kg, find the acceleration produced in the body.2. A ball

of mass 500g is thrown upwards with a velocity of 15m/s. Calculate its momentum at the highest point.

Physics
1 answer:
shepuryov [24]2 years ago
5 0

Explanation:

<em>Hello</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em>

<em>You</em><em> </em><em>just</em><em> </em><em>need</em><em> </em><em>to</em><em> </em><em>use</em><em> </em><em>simple</em><em> </em><em>formula</em><em> </em><em>for</em><em> </em><em>force</em><em> </em><em>and</em><em> </em><em>momentum</em><em>, </em>

<em>F</em><em>=</em><em> </em><em>m.a</em>

<em>and</em><em> </em><em>momentum</em><em> </em><em>(</em><em>p</em><em>)</em><em>=</em><em> </em><em>m.v</em>

<em>where</em><em> </em><em>m</em><em>=</em><em> </em><em>mass</em>

<em>v</em><em>=</em><em> </em><em>velocity</em><em>.</em>

<em>a</em><em>=</em><em> </em><em>acceleration</em><em> </em><em>.</em>

<em>And</em><em> </em><em>the</em><em> </em><em>solutions</em><em> </em><em>are</em><em> </em><em>in</em><em> </em><em>pictures</em><em>. </em>

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

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At its lowest setting a centrifuge rotates with an angular speed of ω1 = 250 rad/s. When it is switched to the next higher setti
dalvyx [7]

Answer:

Part(a): The angular acceleration is 5.63~rad~s^{-2}.

Part(b): The angular displacement is 2629~rad.

Explanation:

Part(a):

If \omega_{1},~\omega_{2}~and~\alpha be the initial angular speed, final angular speed and angular acceleration  of the centrifuge respectively, then from rotational kinematic equation, we can write

\alpha = \dfrac{\omega_{2} - \omega_{1}}{t}......................................................(I)

where 't' is the time taken by the centrifuge to increase its angular speed.

Given, \omega_{i} = 250~rad~s^{-1}, \omega_{f} = 750~rad~s^{-1} and t = 9.5~s. From equation (I), the angular acceleration is given by

\alpha = \dfrac{750 - 250}{9.5}~rad~s^{-2} = 5.63~rad~s^{-2}

Part(b):

Also the angular displacement (\Delta \theta) can be written as

&&\Delta \theta = \omega_{1}~t + \dfrac{1}{2}\alpha~t^{2}\\&or,& \Delta \theta = (250 \times 9.5 + \dfrac{1}{2} \times 5.63 \times 9.5^{2})~rad = 2629~rad

8 0
1 year ago
Please help meee&lt;3~I have no idea what the answer is~
valina [46]
9).
In a properly conducted experiment, the experimenter controls one part
of the experiment to see what the other parts do.

Example:  Experiment to describe the effect of heat on ice.
Take two same-size ice cubes out of the same ice tray in the same fridge.
Place each one on a little temperature-controlled electric pad.
Turn one pad on, to make it warm.  Leave the other pad turned off. 
You CONTROL one part of the experiment:  the amount of heat that
       the ice cube gets.
You KNOW that the heat is the only thing different between the two
     ice cubes.  They're the same size.  They were both made from
     the same water, and froze in the same tray in the same fridge.
so
You KNOW that any difference will be the result of the heat on one of them.
You WATCH to see what happens to the one that gets the heat.


10).
An hypothesis is a prediction of what you believe may be true. 
Once you have it, it's time to do an experiment to find out whether
your hypothesis is true.

Example:
I have an hypothesis.  It predicts that when ice gets warm it melts.
Experiment:
Take two same-size ice cubes out of the same ice tray in the same fridge.
Set one ice cube down on the table.
Keep the other one in your hand.
The one in your hand melts while the one on the table is still solid.
Is the hypothesis correct ?
Maybe it is.  Maybe it isn't.
We know that there's something about your hand that melts ice.
It may be the warmth.  But it may be something else about human skin.
You'll need another experiment, slightly different, to find out if it's the warmth.

4 0
1 year ago
Calculate the acceleration due to gravity on the Moon. The Moon’s radius is 1.74 x 106 m and its mass is 7.35 x 1022 kg.
GarryVolchara [31]
G=?
m=7.35*10^22kg
r=1.74*10^6m
G=6.67*10^-11nm^2kg^-2
you can use the formula
g=Gm/r^2
5 0
1 year ago
Airplane flight recorders must be able to survive catastrophic crashes. Therefore, they are typically encased in crash-resistant
chubhunter [2.5K]

Answer:

3.2 MN

Explanation:

Given that

Mass of the box, m = 52 kg

Initial velocity of the box, u = 400 m/s

Final velocity of the box, v = 0 m/s

Time taken for the collision, t = 0.0065 s

Using the equation of motion

V = u + at, we turn around and make acceleration, a the subject of the formula. Now we have,

a = (v - u) / t

a = (0 - 400) / 0.0065

a = 61538.5 m/s²

The acceleration(which is negative acceleration or retar.dation actually) is 61538.5 m/s². We then proceed to is this acceleration in the basic Force equation, to get the magnitude of force needed.

Remember,

Force = mass * acceleration

F = ma, we already have our mass and acceleration, all we do is multiply

F = 52 * 61538.5

F = 3200002 N or 3.2 MN

Therefore, the magnitude of the force that acts on the box during collision is 3.2 MN

8 0
1 year ago
If the charge that enters each meter of the axon gets distributed uniformly along it, how many coulombs of charge enter a 0.100
SCORPION-xisa [38]

Answer:

Charge enter a 0.100 mm length of the axon is 8.98\times 10^{-12} C

Explanation:

Electric field E at a point due to a point charge is given by

E=k \frac{q}{r^2}

where k is the constant =9.0 \times 10^9  Nm^2 / C^2

q is the magnitude of point charge and r is the distance from the point charge

Charges entering one meter of axon is 5.\times 10^{11} \times (+e)

Charges entering 0.100 mm of axon is 5.\times 10^{11} \times (+e) \times (0.1 \times 10^{-3}

substituting the value of +e=1.6\times 10^{-19} C in above equation, we get charge enter a 0.100 mm length of the axon is

q=5.\times 10^{11} \times1.6\times 10^{-19}  \times (0.1 \times 10^{-3}\\q=8.98\times 10^{-12} C

3 0
1 year ago
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