Question

If period of the pendulum in preceding sample problem were 24s how tall would the tower be ?

Answer 1

Answer:

So length of pendulum is 143.129 m

Explanation:

We have given period of simple pendulum is 2 sec

We have to find the length of simple pendulum

Let the length of pendulum is l

Acceleration due to gravity$g=9.8m/sec^2$ is

Time period is given by $T=2\pi \sqrt{\frac{l}{g}}$

So $24=2\times 3.14\times \sqrt{\frac{l}{9.8}}$

$\sqrt{\frac{l}{9.8}}=3.821$

Squaring both side

${\frac{l}{9.8}}=14.60$

l =143.129 m

So length of pendulum is 143.129 m

Answer 2

Answer:

143 m.

Explanation:

We have to use the equation for the period of a  simple pendulum, and solve for length of pendulum.

$T=2\pi\sqrt{\frac{l}{g} }$

Here l length of pendulum which is equal to height of tower because it touches the almost the floor and g is acceleration due to gravity.

Given $T=24s, g=9.8m/s^2$.

Substitute the given values, we get

$24s=2\pi\sqrt{\frac{l}{9.8m/s^2} }$

$(\frac{24s}{2\pi})^2\times9.8m/s^2 =l$

$l=143m$

Thus, the height of tower is 143 m.