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jeka94
2 years ago
10

A 25N force is applied to a bar that can pivot around its end. The force is r=0.75 m away from the end of an angle at 0= 30. wha

t is the torque on the bar?
Physics
1 answer:
Alecsey [184]2 years ago
6 0

Answer:

<h2>9.375Nm</h2>

Explanation:

The formula for calculating torque τ = Frsin∅ where;

F = applied force (in newton)

r = radius (in metres)

∅ = angle that the force made with the bar.

Given  F= 25N, r = 0.75m and ∅ = 30°

torque on the bar τ  = 25*0.75*sin30°

τ = 25*0.75*0.5

τ = 9.375Nm

The torque on the bar is 9.375Nm

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Explanation:

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The velocity after 4 s can be calculate by

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2 years ago
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2 years ago
A 4 kg box is on a frictionless 35° slope and is connected via a massless string over a massless, frictionless pulley to a hangi
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Answer:

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Explanation:

(a)  

2 Kg box  causes tension

T=mgwhere m is mass, g is gravitational force taken as 9.81T=2*9.81 =19.62 N  (b)  Block mass of 4 Kg  [tex]T'-mg sin \theta=0 hence T'=mg sin \theta where m is mass and g is gravitational force  

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7 0
2 years ago
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When 30 V is applied across a resistor it generates 600 W of heat: what is the magnitude of its resistance?
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Answer:

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magnitude of its resistance is 1.5ohms

3 0
1 year ago
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