A ball is thrown with a velocity of 35 meters per second at an angle of 30° above the horizontal. which quantity has a magnitude
1 answer:
The quantity that has a magnitude of zero when the ball is at the highest point in its trajectory is the vertical velocity.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity
, where 
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration
directed downwards, and with initial velocity 
. Due to the presence of the acceleration g on the vertical direction (pointing in the opposite direction of the initial vertical velocity), the vertical velocity of the ball decreases as it goes higher, up to a point where it becomes zero and it reverses its direction: when the vertical velocity becomes zero, the ball has reached its maximum height.
In fact, the motion of the ball consists of two separate motions:
- the horizontal motion, on the x-axis, which is a uniform motion with constant velocity
- the vertical motion, on the y-axis, which is a uniformly accelerated motion with constant acceleration
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Answer with Explanation:
We are given that
Charge on proton,q=
a.We have to find the electric potential of the proton at the position of the electron.
We know that the electric potential
Where
B.Potential energy of electron,U=
Where
Charge on electron
=Charge on proton
Using the formula
Answer:
after shock
creating a system for the conservation of the energy of the basketball ball and creating a system for the tennis ball only, the conservation of energy should be applied to each system independently
Explanation:
When the two balls fall they acquire the same speed since they are accelerated by the same force, their weight and the acceleration of the acceleration of gravity. When reaching the floor the mechanical energy of the system is conserved.
Upon reaching the floor, the first ball (basketball) collides with the floor, this process is very fast, at the end of the process the basketball comes out with a velicad up and collides with the much lighter tennis ball that is still descending .
we assume that the shocks are elastic, when solving the momentary and kinetic energy findings, we find the velocities after each shock
In this clash the tennis ball acquires a high kinetic speed with an upward direction that makes a very high height high. Again this shock is very fast and the tennis ball almost does not move.
Here we must separate the system, creating a system for the conservation of the energy of the basketball ball and another system for the tennis ball only, the conservation of energy should be applied to each system independently
Em₀ =K = 1/2 m v²
= U = m g h
As in the elastic shock the final speed of the tennis ball is approximately 2 vo, we can calculate the maximum height
m g h = 1/2 m (2v₀)²
h = 2 v₀²/g
To reconcile this with the conservation of energy we must calculate the energy for the tennis ball at two points, the first when the crash with the tennis ball ends and at the end point at its maximum height.
Answer:
The speed of the cat when it hits the ground is approximately 7.586 meters per second.
Explanation:
By Principle of Energy Conservation and Work-Energy Theorem, we have that initial potential gravitational energy of the cat (), in joules, is equal to the sum of the final translational kinetic energy (
), in joules, and work losses due to air resistance (
), in joules:
(1)
By definition of potential gravitational energy, translational kinetic energy and work, we expand the equation presented above:
(2)
Where:
- Mass of the cat, in kilograms.
- Gravitational acceleration, in meters per square second.
- Initial height of the cat, in meters.
- Final speed of the cat, in meters per second.
If we know that ,
,
and
, then the final speed of the cat is:
The speed of the cat when it hits the ground is approximately 7.586 meters per second.