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777dan777 [17]
1 year ago
11

Technician A says that the pressure differential switch may need to be re-centered after bleeding the brakes. Technician B says

that there are several types of pressure differential switches, and each requires a different method of re-centering. Who is correct?
a. Technician A
b. Technician B
c. Both Technician A and Technician B
d. Neither Technician A nor Technician B
Physics
1 answer:
Snezhnost [94]1 year ago
6 0

Option C

Both Technician A and Technician B is correct

<h3><u>Explanation:</u></h3>

The pressure differential valve is the equipment that warns you if you leak one of your brake circuits. After draining and refilling some brake system pressure differential switch may be actuated and an indication light may be illuminated. If the indication light sojourns sparked after draining the valve piston may demand to be re-centered. If the pressure is replaced to the brake line and your brakes appear to be running accurately over, then the reset button operated.

The common practical method to re-center the piston is to fix the failure, drain the system and then generate a pressure loss opposite what moved the piston in the first place. Each type has a unique kind of re-centering technique.

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A stone is thrown horizontally from 2.4m above the ground at 35m/s. The wall is 14m away and 1m high.At what height the stone wi
KIM [24]

The stone reaches the wall at a height of <u>1.62 m</u>.

The stone lands at a point <u>24.5 m</u> from the point of projection.

The stone is projected horizontally with a velocity u at a height <em>h</em> from the ground. The wall is located at a distance <em>x</em> from the point of projection. The stone takes a time <em>t</em> to reach the wall and in the same time the stone falls a vertical distance <em>y</em>.

The horizontal distance <em>x</em> is traveled with a constant velocity <em>u</em>.

x=ut

Calculate the time taken <em>t</em>.

t=\frac{x}{u} \\ =\frac{14m}{35 m/s} \\ =0.40s

The stone's initial vertical velocity is zero. It falls through a distance <em>y</em> in the time <em>t</em> under the action of acceleration due to gravity <em>g</em>.

y=\frac{1}{2} gt^2\\ \frac{1}{2} (9.81m/s^2)(0.40s)^2\\ =0.784m

The height  <em>h₁ </em>of the stone above the ground when it reaches the wall  is given by,

h_1=h-y\\ =(2.4m)-(0.784m)\\ =1.616m=1.62m

When the stone reaches the wall, its height from the ground is <u>1.62m.</u>

The stone thus crosses over the wall, since the height of the wall is 1 m. It reaches the ground at a distance <em>R</em> from the point of projection. If the time taken by the stone to reach the ground is <em>t₁, </em>then,

h=\frac{1}{2} gt_1^2

Calculate the time taken by the stone to reach the ground.

t_1=\sqrt{\frac{2h}{g} } \\=\sqrt{\frac{2(2.4m)}{9.81m/s^2} } \\ =0.699 s

The horizontal distance traveled by the stone is given by,

R=ut_1 \\ =(35m/s)(0.699s)\\ =24.5m

The stone lands at point 24.5 m from the point of projection and 10.5 m from the wall.

3 0
1 year ago
John runs 1.0 m/s at first, and then accelerates to 1.6 m/s during
erastova [34]

Answer: 0.13m/s^2

Explanation:

Formula: a=\frac{V_2-V_1}{t}

Where;

a = acceleration

V2 = final velocity

V1 = initial velocity

t = time

If John runs 1.0 m/s first, we assume this is V1. He accelerates to 1.6 m/s; this is V2.

a=\frac{1.6m/s-1.0m/s}{4.5s}

a=\frac{0.6m/s}{4.5s}

a=0.13m/s^2

7 0
2 years ago
Read 2 more answers
Jin walked 4 km on a straight path to get to the sandwich shop. He traveled 30° south of east.
Molodets [167]

Answer: -2 km

Explanation:

If we imagine Jin's movement to be the hypothenuse of a right triangle, then the southern component of Jin's movement corresponds to the side of the triangle opposite to the angle of 30 degrees. Therefore, the magnitude of this southern component is given by

However, the angle of 30 degrees is south of east: this means that the direction of this southern component is south, and since we generally take north as positive direction, we must add a negative sign, so the correct answer is

-2 km

3 0
2 years ago
Read 2 more answers
A dog runs 3 miles and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?
Inga [223]

Complete question:

A dog runs 3 miles east and 4 miles west in 6 hours. What’s the dogs total distance and displacement ?

Answer:

The total distance covered by the dog is  7 miles

The displacement of the dog is 1 mile west

Explanation:

Given;

initial position of the dog = 3 miles east

final position of the dog = 4 miles west

time of motion, t = 6 hours

The total distance covered by the dog is given as;

Total distance = 3 miles + 4 miles = 7 miles

The displacement of the dog is given as;

displacement = final position of the dog  - initial position of the dog

displacement =  4 miles west - 3 miles east = 1 mile west

6 0
2 years ago
A solenoid of length 18 cm consists of closely spaced coils of wire wrapped tightly around a wooden core. The magnetic field str
Kisachek [45]

Answer:

B_2 = 1.71 mT

Explanation:

As we know that the magnetic field near the center of solenoid is given as

B = \frac{\mu_0 N i}{L}

now we know that initially the length of the solenoid is L = 18 cm and N number of turns are wounded on it

So the magnetic field at the center of the solenoid is 2 mT

now we pulled the coils apart and the length of solenoid is increased as L = 21 cm

so we have

\frac{B_1}{B_2} = \frac{L_2}{L_1}

now plug in all values in it

\frac{2.0 mT}{B_2} = \frac{21}{18}

B_2 = 1.71 mT

3 0
1 year ago
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