answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
sweet [91]
1 year ago
6

A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The uppe

r face carries +95.0 nC/m2 while the lower face carries -25.0 nC/ m2. What is the magnitude of the electric field at a point within the sheet 2.00 cm below the upper face? (ε0 = 8.85 × 10-12 C2/N · m2) A huge (essentially infinite) horizontal nonconducting sheet 10.0 cm thick has charge uniformly spread over both faces. The upper face carries +95.0 nC/m2 while the lower face carries -25.0 nC/ m2. What is the magnitude of the electric field at a point within the sheet 2.00 cm below the upper face? ( = 8.85 × 10-12 C2/N · m2) 0.00 N/C 6.78 × 103 N/C 7.91 × 103 N/C 1.36 × 104 N/C 3.95 × 103 N/C
Physics
1 answer:
Nonamiya [84]1 year ago
4 0

Answer:

6.78 X 10³ N/C

Explanation:

Electric field near a charged infinite plate

=  surface charge density / 2ε₀

Field will be perpendicular to the surface of the plate for both the charge density and direction of field will be same so they will add up.

Field due to charge density of +95.0 nC/m2

E₁ = 95 x 10⁻⁹ / 2 ε₀

Field due to charge density of -25.0 nC/m2

E₂ = 25 x 10⁻⁹ /  2ε₀

Total field

E = E₁ + E₂

= 95 x 10⁻⁹ / 2 ε₀ + 25 x 10⁻⁹ /  2ε₀

= 6.78 X 10³ N/C

You might be interested in
A pet-store supply truck moves at 25.0 m/s north along a highway. inside, a dog moves at 1.75 m/s at an angle of 35.0° east of
koban [17]

<u>Answer:</u>

 Velocity of the dog relative to the road = 26.04 m/s 3.15⁰ north of east.

<u>Explanation:</u>

  Let the east point towards positive X-axis and north point towards positive Y-axis.

  Speed of truck = 25 m/s north = 25 j m/s

  Speed of dog = 1.75 m/s at an angle of 35.0° east of north = (1.75 cos 35 i + 1.75 sin 35 j)m/s

                          = (1.43 i + 1.00 j) m/s

    Velocity of the dog relative to the road = 25 j + 1.43 i + 1.00 j = 1.43 i + 26.00 j

    Magnitude of velocity = 26.04 m/s

    Angle from positive horizontal axis = 86.85⁰

 So Velocity of the dog relative to the road = 26.04 m/s 86.85⁰ east of north = 26.04 m/s 3.15⁰ north of east.

4 0
1 year ago
Consider steady-state conditions for one-dimensional conduction in a plane wall having a thermal conductivity k = 50 W/m · K and
tatuchka [14]

Answer:

solution:

dT/dx =T2-T1/L

&

q_x = -k*(dT/dx)

<u>Case (1)  </u>

dT/dx= (-20-50)/0.35==> -280 K/m

 q_x  =-50*(-280)*10^3==>14 kW

Case (2)

dT/dx= (-10+30)/0.35==> 80 K/m

 q_x  =-50*(80)*10^3==>-4 kW

Case (2)

dT/dx= (-10+30)/0.35==> 80 K/m

 q_x  =-50*(80)*10^3==>-4 kW

Case (3)

q_x  =-50*(160)*10^3==>-8 kW

T2=T1+dT/dx*L=70+160*0.25==> 110° C

Case (4)

q_x  =-50*(-80)*10^3==>4 kW

T1=T2-dT/dx*L=40+80*0.25==> 60° C

Case (5)

q_x  =-50*(200)*10^3==>-10 kW

T1=T2-dT/dx*L=30-200*0.25==> -20° C

note:

all graph are attached

6 0
1 year ago
Listed following are locations and times at which different phases of the moon are visible from earth’s northern hemisphere. mat
Airida [17]
For the answer tot he questions above, I know this one.
The answers are
 <span>-sets 2-3 hours after the sun sets - waxing crescent 
-occurs about 3 days before the new moon - waning crescent 
-occurs 14 days after the new moon - full moon 
-rises at about the time the sun sets - full moon 
-visible due south at midnight - full moon 
-visible near eastern horizon just before sunrise waning crescent 
-visible near western horizon about an hour after sunset waxing crescent</span>
7 0
1 year ago
An astronaut on Earth notes that in her soft drink an ice cube floats with 9/10 of its volume submerged. If she were instead in
riadik2000 [5.3K]

Answer:

B) with 9/10 submerged

Explanation:

m = mass of ice cube

\rho = density of soft drink

V = Volume of soft drink displaced

ice cube floats in the soft drink when the force of buoyancy on it balances its weight. Force of buoyancy acting on the cube in upward direction is same as the weight of the soft drink displaced. hence we can write

weight of ice cube = weight of soft drink displaced

mg = \rho V g

m = \rho V

we see that the acceleration due to gravity cancel out both side and hence it does affect as astronaut is on earth on in a lunar module.

8 0
2 years ago
Read 2 more answers
Two bricks are resting on the edge of the lab table. Shirley Sheshort stands on her toes and spots the two bricks. She acquires
PSYCHO15rus [73]

Explanation:

  • since force =mass×acceleration and acceleration being g which is = 10m/s^2
  • the brick with the larger mass will reach the ground first since it has a greater force to resist resistance forces such as air resistance

4 0
2 years ago
Other questions:
  • Two extremely large nonconducting horizontal sheets each carry uniform charge density on the surfaces facing each other. The upp
    5·1 answer
  • What factors might affect how the watermill works?
    14·2 answers
  • A transverse wave on a string has an amplitude A. A tiny spot on the string is colored red. As one cycle of the wave passes by,
    7·1 answer
  • A lever has a 36cm input arm and a 6cm output arm. find MA.
    14·1 answer
  • Suppose an isolated box of volume 2V is divided into two equal compartments. An ideal gas occupies half of the container and the
    14·1 answer
  • Using energy considerations and assuming negligible air resistance, show that a rock thrown from a bridge 20.0 m above water wit
    8·1 answer
  • When Aditya pushes on Rachel and her bicycle, they accelerate at 0.22 m/s/s. If Aditya pushes on Rachel and her bicycle with twi
    12·1 answer
  • A long, thin straight wire with linear charge density λ runs down the center of a thin, hollow metal cylinder of radius R. The c
    12·1 answer
  • A boat moves through the sea.
    10·1 answer
  • A child of mass m is at the edge of a merry-go-round of diameter d. When the merry-go-round is rotating with angular acceleratio
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!