Answer:
Part a)
Part b)
Explanation:
Part a)
Angular speed of the pedal is changing from 60 rpm to 90 rpm in 10 s
so the angular acceleration is given as
so we will have
now the tangential acceleration of the pedal is given as
Part b)
Total angular displacement made by the sprocket in the interval of 10 s is given as
now length of the chain passing over it is given as
Answer:
The range is maximum when the angle of projection is 45 degree.
Explanation:
The formula for the horizontal range of the projectile is given by
The range should be maximum if the value of Sin2θ is maximum.
The maximum value of Sin2θ is 1.
It means 2θ = 90
θ = 45
Thus, the range is maximum when the angle of projection is 45 degree.
If the angle of projection is 0 degree
R = 0
It means the horizontal distance covered by the projectile is zero, it can move in vertical direction.
If the angle of projection is 30 degree.
R = 0.088u^2
If the angle of projection is 45 degree.
R = u^2 / g
Answer:
(a) k =
(b) τ = ∝
Explanation:
The moment of parallel pipe rotating about it's axis is given by the formula;
I = ---------------------------------1
(a) The kinetic energy of a parallel pipe is also given as;
k = --------------------------------2
Putting equation 1 into equation 2, we have;
k =
k =
(b) The angular momentum is given by the formula;
τ = Iw -----------------------3
Putting equation 1 into equation 3, we have
τ =
But
τ = dτ/dt = ------------------4
where
dw/dt = angular acceleration =∝
Equation 4 becomes;
τ = ∝
Answer:
The average rate of energy transfer to the cooker is 1.80 kW.
Explanation:
Given that,
Pressure of boiled water = 300 kPa
Mass of water = 3 kg
Time = 30 min
Dryness friction of water = 0.5
Suppose, what is the average rate of energy transfer to the cooker?
We know that,
The specific enthalpy of evaporate at 300 kPa pressure
We need to calculate the enthalpy of water at initial state
We need to calculate the enthalpy of water at final state
Using formula of enthalpy
Put the value into the formula
We need to calculate the rate of energy transfer to the cooker
Using formula of rate of energy
Put the value into the formula
Hence, The average rate of energy transfer to the cooker is 1.80 kW.