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andrey2020 [161]
2 years ago
10

A swimming pool heater has to be able to raise the temperatureof the 40,000 gallons of water in the pool by 10 degress Celsius.H

ow many kilowatt-hours of energy are required? (one gallon ofwater has a mass of approximately 3.8kg and the specific heat ofwater is 4186 J/kg C)
a.) 1960 kWh
b.) 1770 kWh
c.) 330 kWh
d.) 216 kWh
Physics
1 answer:
andrew11 [14]2 years ago
3 0

Answer:b)1770 kWh

Explanation:

Given

volume of water V=40,000 gallons

Temperature rise \Delta T=10^{\circ}C

c=4186 J/kg-^{\circ} C

also 1 kg mass is approximately is 1 gallon

therefore 40,000 gallon is equivalent to 3.8\times 40000 kg

heat Required to raise temperature is

Q=mc\Delta T

Q=3.8\times 40000\times 4186\times 10

Q=63,627.2\times 10^5 J

Q=63,672.2\times 10^2 KJ

Q=1767.42 kWh\approx 1770 kWh

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Answer:

3.0.33in/min...(c)

4.40m/min....(b)

5.10m/s....(a)

6.20mph...(b)

7.4m/s...(a)

3 0
2 years ago
Changes that occur in the urinary system with aging include all of the following, EXCEPT
Sladkaya [172]

Answer: c. increased sensitivity to ADH

Explanation:

a. a decline in the number of functional nephrons: With aging the loss of nephron occurs that can be detected by the age related decrease in the glomerular filteration rate.

b. a reduction in the GFR (glomerular filtration rate): The GFR tend to decline in older age even though there is no disease. These people are required to check with the GFR in future.

d. problems with the micturition reflex: With aging people experience problem of bladder control. This leads to leakage or incontinence of urine or urinary retention that is inability to empty the bladder.

e. loss of sphincter muscle tone: With age the sphincter tone may diminish. This results in loss of control and storage capacity. The rectal muscles or sphincter muscles get loose which lead to passage of stool before reaching the washroom.

6 0
2 years ago
At room temperature what is the strength of the electric field in a 12-gauge copper wire (diameter 2.05 mm that is needed to cau
Dima020 [189]
Electric field strength = resistivity of copper x current density
where
p= 1.72 x 10^-8 <span>ohm meter
diameter = 2.05mm=.00205 m
current = 2.75 A
</span>get first the current density:
current density = current/ cross section area
find the cross section area
cross section area = pi.(d/2)^2;  
cross section = 3.3 006x10-6 m^2
substitute the values 
current density = 2.75A/3.3006x 10-6m^2
current density=35.55 x1 0^2 A/m^2
Electric field stregnth =1.72 x 10^-8 ohm meter x 35.55 x10^2 A/m^2
Electric field stregnth= 46.415 Volts/m

The electric field strength of copper is 46.415 V/m.


6 0
2 years ago
An electron is released from rest at a distance of 9.00 cm from a proton. If the proton is held in place, how fast will the elec
inna [77]

Answer:

v = 61.09m/s

Explanation:

In order to calculate the speed of the electron when it is 3.00cm from the proton, you first calculate the acceleration of the electron, produced by the electric force between the electron and the proton. By using the second Newton law you have:

F=ma=k\frac{q^2}{r^2}     (1)

m: mass of the electron = 9.1*10^-31kg

q: charge of electron and proton = 1.6*10^-19C

r: distance between electron and proton = 9.00cm = 0.09m

k: Coulomb's constant = 8.98*10^9Nm2/C^2

You solve the equation (1) for a, and replace the values of the other parameters:

a=\frac{kq^2}{mr^2}=\frac{(8.98*10^9Nm^2/C^2)(1.6*10^{-19}C)^2}{(9.1*10^{-31}kg)(0.09m)^2}=3.11*10^4\frac{m}{s^2}

Next, you use the following formula to calculate the final speed of the electron:

v^2=v_o^2+2ax       (2)

vo: initial speed of the electron = 0m/s

a: acceleration = 3.11*10^4m/s^2

x: distance traveled by the electron

When the electron is at 3.00cm from the proton the electron has traveled a distance of 9.00cm - 3.00cm = 6.00cm = 0.06m = x

You replace the values of the parameters in the equation (2):

v=\sqrt{2ax}=\sqrt{2(3.11*10^4m/s)(0.06m)}=61.09\frac{m}{s}

The speed of the electron is 61.09m/s

8 0
2 years ago
Numerous engineering and scientific applications require finding solutions to a set of equations. Ex: 8x + 7y = 38 and 3x - 5y =
mote1985 [20]
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2 years ago
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