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bogdanovich [222]
2 years ago
6

Two loudspeakers, A and B, are driven by the same amplifier and emit sinusoidal waves in phase. The frequency of the waves emitt

ed by each speaker is 172 Hz. You are 8.00 m from the speaker.
Take the speed of sound in air to be 344 m/s. What is the closest you can be to speaker B and be at a point of destructive interference?
Physics
1 answer:
geniusboy [140]2 years ago
5 0

Answer:

The distance of the speaker B would be 1 meters.

Explanation:

Given that,

Frequency of the waves emitted, f = 172 Hz

You are 8.00 m from the speaker.

The speed of sound in air to be 344 m/s.

The wavelength of the wave is given in terms of frequency and the speed of sound. It is given by :

v=f\lambda\\\\\lambda=\dfrac{v}{f}\\\\\lambda=\dfrac{344\ m/s}{172\ Hz}\\\\\lambda=2\ m

Since, the distance from the Speaker A is 8 m which is the integral multiple of the wavelength. Let the closest distance of the speaker B would be given by :

d=\dfrac{\lambda}{2}\\\\d=\dfrac{2}{2}\\\\d=1\ m

So, the distance of the speaker B would be 1 meters. Hence, this is the required solution.

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Given:

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388 cm^3

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p_1 = 75.9 kPa is the initial pressure

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Let us first know the given: Tennis ball has a mass of 0.003 kg, Soccer ball has a mass of 0.43 kg. Having the same velocity at 16 m/s. First the equation for momentum is P=MV P=Momentum M=Mass V=Velocity. Now let us have the solution for the momentum of tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ) I use the subscript "t" for tennis.  Momentum of Soccer ball Ps= 0.43 x 13m/s = (      km-m/s). If we going to compare the momentum of both balls, the heavier object will surely have a greater momentum because it has a larger mass, unless otherwise  the tennis ball with a lesser mass will have a greater velocity to be equal or greater than the momentum of a soccer ball.
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Answer:

T=1022.42 N

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