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Wittaler [7]
2 years ago
6

One game at the amusement park has you push a puck up a long, frictionless ramp. You win a stuffed animal if the puck, at its hi

ghest point, comes to within 10 cm of the end of the ramp without going off. You give the puck a push, releasing it with a speed of 5.0 m/s when it is 8.50 m from the end of the ramp. The puck's speed after traveling 3.0 m is 4.0 m/s.
Physics
1 answer:
Aneli [31]2 years ago
4 0

Answer:

Explanation:

Given

initial speed(u)=5 m/s

Final speed(v)=4 m/s

Distance traveled=3 m

using equation of motion

v^2-u^2=2as

4^2-5^2=2(a)(3)

a=\frac{-3}{2}=-1.5 m/s^2

after this its final velocity will be zero

v^2-u^2=2as

0^2-4^2=2\times (-1.5)\times s

s=5.33 m

Total distance=3+5.33=8.33 m

Thus he will not be able to win the game

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Susie walks 3 blocks north to the local CVS store, then 4 blocks east to her grandmother’s house. She then walks 2 blocks west a
Slav-nsk [51]

Answer:

Suzie is 3 blocks north of where she started

Explanation:

Displacement is the minimum distance between the initial and final point of motion.

Here, Suzie first walks 3 blocks north. From there she walks 4 blocks east. Then 2 blocks to the east then 2 blocks north and then 2 blocks east. She covered 4 blocks east toward west. This is the same distance she covered traveling east. But she is 2 blocks north. From there she traveled a block south to the pizzeria and another block to her friends house. She covered the two block she had traveled north.

Hence, Suzie is 3 blocks north of where she started.

7 0
2 years ago
An electric dipole with dipole moment p⃗ is in a uniform electric field E⃗ . A. Find all the orientation angles of the dipole me
Tasya [4]

Answer:

Explanation:

A) When a dipole is placed in an electric field , it experiences a torque equal to the following

torque = p x E = p E sinθ , where θ is angle between direction of p and E .

It will be zero if θ = 0

or if both p and E are oriented in the same direction.

It is the stable orientation of dipole.

If θ = 180° ,

Torque = 0

In this case both p and E are oriented in opposite direction .

It is the unstable orientation of the dipole because if we deflect the dipole by even small angle , it goes back to most stable orientation due to torque acting on it by electric field.

3 0
2 years ago
A split highway has a number of lanes for traffic. For traffic going in one direction, the radius for the inside of the curve is
Arte-miy333 [17]
Cuál es tu pregunta
7 0
2 years ago
A 28-kg particle exerts a gravitational force of 8.3 x 10^-9 N on a particle of mass m, which is 3.2 m away. What is m? A) 140 k
xxTIMURxx [149]

Answer:

Mass of another particle, m = 46 kg  

Explanation:

it is given that,

Mass of first particle, m₁ = 28 kg

Gravitational force, F=8.3\times 10^{-9}\ N

Distance between the particles, d = 3.2 m

We need to find the mass m of another particle. It is given by the formula as follows :

F=G\dfrac{m_1m}{d^2}

m=\dfrac{Fd^2}{Gm_1}

m=\dfrac{8.3\times 10^{-9}\ N\times (3.2\ m)^2}{6.67\times 10^{-11}\times 28\ kg}

m = 45.5 kg

or

m = 46 kg

So, the correct option is (d) "46 kg". Hence, this is the required solution.

6 0
2 years ago
A bicyclist is riding to the left with a velocity of 14 \,\dfrac{\text m}{\text s}14 s m ​ 14, start fraction, start text, m, en
Gnesinka [82]

Answer:

-2.0 m/s²

Explanation:Acceleration is the rate of change of velocity.

\begin{aligned}a&=\dfrac{\text{Change in velocity}}{\text{Change in time}}\\ \\ &=\dfrac{v_f-v_i}{\Delta t} \end{aligned}

a

​

 

=

Change in time

Change in velocity

​

=

Δt

v

f

​

−v

i

​

​

​

Hint #22 / 3

We can calculate the bicyclist's acceleration from the final velocity v_fv

f

​

v, start subscript, f, end subscript, initial velocity v_iv

i

​

v, start subscript, i, end subscript, and time interval \Delta tΔtdelta, t.

\begin{aligned}a&=\dfrac{v_f-v_i}{\Delta t}\\ \\ &=\dfrac{-21\,\dfrac{\text m}{\text s}-(-14\,\dfrac{\text m}{\text s})}{3.5\,\text s}\\ \\ &=-2.0\,\dfrac{\text m}{\text s^2}\end{aligned}

a

​

 

=

Δt

v

f

​

−v

i

​

​

=

3.5s

−21

s

m

​

−(−14

s

m

​

)

​

=−2.0

s

2

m

​

​

Hint #33 / 3

The acceleration of the bicyclist is -2.0\,\dfrac{\text m}{\text s^2}−2.0

s

2

m

​

minus, 2, point, 0, start fraction, start text, m, end text, divided by, start text, s, end text, squared, end fraction.

5 0
2 years ago
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