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liraira [26]
2 years ago
13

Hey guys I really really need help with this question for ASAP! Explain what chart junk is and how it differs from the kind of i

tems you should include in your graphs. Provide four examples?
the second question is Explain what chart junk is and how it differs from the kind of items you should include in your graphs. Provide four examples.
Physics
2 answers:
Step2247 [10]2 years ago
4 0

Answer:

Chartjunk refers to all visual elements in charts and graphs that are not necessary to comprehend the information represented on the graph, or that distract the viewer from this information.

Explanation:

Ahat [919]2 years ago
3 0
I found a definition: Chartjunk<span> refers to all visual elements in </span>charts<span> and graphs that are not necessary to comprehend the information represented on the graph, or that distract the viewer from this information.</span>
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An object executes simple harmonic motion with an amplitude A. (Use any variable or symbol stated above as necessary.) (a) At wh
valentina_108 [34]

Answer:

(a) x=ASin(ωt+Ф₀)=±(√3)A/2

(b) x=±(√2)A/2

Explanation:

For part (a)

V=AωCos(ωt+Ф₀)⇒±0.5Aω=AωCos(ωt+Ф₀)

Cos(ωt+Ф₀)=±0.5⇒ωt+Ф₀=π/3,2π/3,4π/3,5π/3

x=ASin(ωt+Ф₀)=±(√3)A/2

For part(b)

U=0.5E and U+K=E→K=0.5E

E=K(Max)

(1/2)mv²=(0.5)(1/2)m(Vmax)²

V=±(√2)Vmax/2→ωt+Ф₀=π/4,3π/4,7π/4

x=±(√2)A/2

7 0
2 years ago
A car is travelling to the right with a speed of 42\,\dfrac{\text m}{\text s}42 s m ​ 42, space, start fraction, m, divided by,
Effectus [21]

Answer:

d = 84 m

Explanation:

As we know that when an object moves with uniform acceleration or deceleration then we can use equation of kinematics to find the distance moved by the object

here we know that

initial speed v_i = 42 m/s

final speed v_f = 0

time taken by the car to stop

t = 4s

now the distance moved by the car before it stop is given as

d = \frac{v_f + v_i}{2} \times t

now we have

d = \frac{42 + 0}{2} \times 4

d = 84 m

7 0
2 years ago
Read 2 more answers
If a metal wire is 4m long and a force of 5000n causes it to stretch by 1mm, what is the strain?
barxatty [35]

Answer:

2.5\cdot 10^{-4}

Explanation:

The strain is defined as the ratio of change of dimension of an object under a force:

S=\frac{\Delta L}{L_0}

where

\Delta L is the change in length of the object

L_0 is the original length of the object

In this problem, we have L_0 = 4 m and \Delta L=1 mm=0.001 m, therefore the strain is

S=\frac{\Delta L}{L_0}=\frac{0.001 m}{4 m}=2.5\cdot 10^{-4}


5 0
2 years ago
A submarine periscope uses two totally reflecting 45-45-90 prisms with total internal reflection on the sides adjacent to the 45
Likurg_2 [28]

Answer

Given,

Periscope uses 45-45-90 prisms with total internal reflection adjacent to 45°.

refractive index of water, n_a = 1.33

refractive index of glass, n_g = 1.52

When the light enters the water, water will act as a lens and when we see the object from the periscope the object shown is farther than the usual distance.

7 0
2 years ago
The value of specific heat for copper is 390 J/kg⋅C∘, for aluminun is 900 J/kg⋅C∘, and for water is 4186 J/kg⋅C∘.
abruzzese [7]

Answer:

The equilibrium temperature is

21.97°c

Explanation:

This problem bothers on the heat capacity of materials

Given data

specific heat capacities

copper is Cc =390 J/kg⋅C∘,

aluminun Ca = 900 J/kg⋅C∘,

water Cw = 4186 J/kg⋅C∘.

Mass of substances

Copper Mc = 235g

Aluminum Ma = 135g

Water Mw = 825g

Temperatures

Copper θc = 255°c

Water and aluminum calorimeter θ1= 16°c

Equilibrium temperature θf =?

Applying the principle of conservation of heat energy, heat loss by copper equal heat gained by aluminum calorimeter and water

McCc(θc-θf) =(MaCa+MwCw)(θf-θ1)

Substituting our data into the expression we have

235*390(255-θf)=

(135*900+825*4186)(θf-16)

91650(255-θf)=(3574950)(θf-16)

23.37*10^6-91650*θf=3.57*10^6θf- +57.2*10^6

Collecting like terms and rearranging

23.37*10^6+57.2*10^6=3.57*10^6θf+91650θf

8.2*10^6=3.66*10^6θf

θf=80.5*10^6/3.6*10^6

θf =21.97°c

5 0
2 years ago
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