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andrew11 [14]
2 years ago
12

A table tennis ball with a mass of 0.003 kg and a soccer ball with a mass of 0.43 kg or both Serta name motion at 16 M/S calcula

te and compare the moments of both balls
Physics
2 answers:
poizon [28]2 years ago
8 0
Let us first know the given: Tennis ball has a mass of 0.003 kg, Soccer ball has a mass of 0.43 kg. Having the same velocity at 16 m/s. First the equation for momentum is P=MV P=Momentum M=Mass V=Velocity. Now let us have the solution for the momentum of tennis ball. Pt=0.003 x 16 m/s= (    kg-m/s ) I use the subscript "t" for tennis.  Momentum of Soccer ball Ps= 0.43 x 13m/s = (      km-m/s). If we going to compare the momentum of both balls, the heavier object will surely have a greater momentum because it has a larger mass, unless otherwise  the tennis ball with a lesser mass will have a greater velocity to be equal or greater than the momentum of a soccer ball.
Zepler [3.9K]2 years ago
7 0

Answer:

Momentum of tennis ball = 0.048 \frac{kg m}{s}

Momentum of soccer ball = 6.88 \frac{kg m}{s}

momentum of soccer ball is greater than that of tennis ball.

Explanation:

For table tennis ball,

Momentum of tennis the ball is given by,

Momentum = mass × volume

Momentum =  0.003 × 16

Momentum = 0.048 \frac{kg m}{s}

For table soccer ball,

Momentum of the soccer ball is given by,

Momentum = mass × volume

Momentum =  0.43 × 16

Momentum = 6.88 \frac{kg m}{s}

Thus, momentum of soccer ball is greater than that of tennis ball.

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A particle with a charge of -1.24 x 10"° C is moving with instantaneous velocity (4.19 X 104 m/s)î + (-3.85 X 104 m/s)j. What is
astra-53 [7]

Answer:

(a) F= 6.68*10¹¹⁴ N (-k)

(b) F =( 6.68*10¹¹⁴ i  + 7.27*10¹¹⁴ j  ) N

Explanation

To find the magnetic force in terms of a fixed amount of charge q that moves at a constant speed v in a uniform magnetic field B we apply the following formula:

F=q* v X B Formula (1 )

q: charge (C)

v: velocity (m/s)

B: magnetic field (T)

vXB : cross product between the velocity vector and the magnetic field vector

Data

q= -1.24 * 10¹¹⁰ C

v= (4.19 * 10⁴ m/s)î + (-3.85 * 10⁴m/s)j

B  =(1.40 T)i  

B  =(1.40 T)k

Problem development

a) vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)i =

            = - (-3.85*1.4) k = 5.39* 10⁴ m/s*T (k)

1T= 1 N/ C*m/s

We apply the formula (1)

  F= 1.24 * 10¹¹⁰ C*  5.39* 10⁴ m/s* N/ C*m/s (-k)

   F= 6.68*10¹¹⁴ N (-k)

a)  vXB = (4.19 * 10⁴ m/s)î + (-3.85* 10⁴m/s)j X (1.40 T)k =

             =( - 5.39* 10⁴i - 5.87* 10⁴j)m/s*T

1T= 1 N/ C*m/s

We apply the formula (1)

F= 1.24 * 10¹¹⁰ C*  (  5.39* 10⁴i + 5.87* 10⁴j) m/s* N/ C*m/s

F =( 6.68*10¹¹⁴  i  + 7.27*10¹¹⁴  j  ) N

8 0
2 years ago
A hot piece of iron is thrown into the ocean and its temperature eventually stabilizes. Which of the following statements concer
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Answer:

E. The ocean gains more entropy than the iron loses.

Explanation:

When there is a spontaneous process , entropy of the system increases . Here hot iron is losing entropy and ocean is gaining entropy . Net effect will be gain of entropy . That means entropy gained by ocean is more than entropy lost by iron .

Hence option E is correct .

8 0
2 years ago
A rod of mass M and length L can rotate about a hinge at its left end and is initially at rest. A putty ball of mass m, moving w
klio [65]

Answer:

w_f =  m*V*cos(Q_n) / L*(m+M)

Explanation:

Given:

- mass of the putty ball m

- mass of the rod M

- Velocity of the ball V

- Length of the rod L

- Angle the ball makes before colliding with rod  Q_n

Find:

What is the angular speed ωf of the system immediately after the collision,

Solution:

- We can either use conservation of angular momentum or conservation of Energy. We will use Conservation of angular momentum of a system:

                                         L_before = L_after

- Initially the rod is at rest, and ball is moving with the velocity V at angle Q from normal to the rod. We know that the component normal to the rod causes angular momentum. Hence,

                                         L_before = L_ball = m*L*V*cos(Q_n)

- After colliding the ball sicks to the rod and both move together with angular speed w_f

                                         L_after = (m+M)*L*v_f

Where, v_f = L*w_f

                                         L_after = (m+M)*L^2 * w_f

- Now equate the two expression as per conservation of angular momentum:

                                       m*L*V*cos(Q_n) = (m+M)*L^2 * w_f

                                       w_f =  m*V*cos(Q_n) / L*(m+M)

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2 years ago
For this exercise, use the position function s(t) = −4.9t2 + 250, which gives the height (in meters) of an object that has falle
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Answer:

t=7.14s

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Explanation:

Position function

s(t)=-4.9*t^{2}+250

Velocity is the derivative of position function

V(t)=\frac{dx}{dt}\\V(t)=-2*4.9*t\\V(t)=-9.8*t

The time the object hit the ground can be find by the given function know that the position is going to be 0m

s(t)=-4.9*t^{2}+250

s(t)=0\\0=-4.9*t^{2} +250\\t=\sqrt{\frac{250}{4.9}}\\t=7.14s

Check:

s(7.14)=-4.9*(7.14s)^{2}+250\\ s(7.14)=-250+250\\s(7.14)=0m

So the velocity can be find using the time discovery before and using the same function but with the derivate

V(t)=-2*4.9*t\\V(7.14)=-2*4.9*(7.14)\\V(7.14)=-69.972 \frac{m}{s}

The velocity is negative because the object is moving downward

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Answer:

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Explanation:

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