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s344n2d4d5 [400]
2 years ago
14

A lump of steel of mass 10kg at 627 degree Celsius is dropped in 100kg oil at 30 degree Celsius . the specific heat of steel And

oil are 0.5kj/kg.k and 3.5kj/kg.k calculate the entropy change in steel,oil and in the universe.​
Physics
1 answer:
Naily [24]2 years ago
8 0

Answer:

700J

Explanation:

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Consider two less-than-desirable options. In the first you are driving 30 mph and crash head-on into an identical car also going
DerKrebs [107]

Answer:

The impact force will be same for both the cases.

Explanation:

The rate of change of momentum is known as the Impulse and is given by:

I = \frac{\Delta p}{\Delta t}

where

I = Impulse

\Delta p = change in momentum

\Delta t = time interval

Now,

In first case both the cars are identical and have same velocity and in the second case, the wall is stationary.

Also, in both the cases the car does not bounces off the things it hit.

Thus

\Delta p = 0 - m\times v = - mv

Thus

Impact force, F = \frac{\Delta p}{\Delta t} = \frac{m\Delta v}{\Delta t}

Therefore, impact force is same for both the cases.

5 0
2 years ago
Read 2 more answers
A solution is oversaturated with solute. Which could be done to decrease the oversaturation?
salantis [7]
Ans: Dilute the solution

Explanation:
To decrease the over-saturation, dilute the solution. Dilution<span> is the process of decreasing the solute's concentration in the </span>solution. It is<span> usually done by mixing with more solvent. In other words, to </span>dilute<span> a </span>solution<span> means to add more solvent without the addition of more solute.</span>
3 0
2 years ago
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The potential energy of a 40 kg cannon ball is 14000 J. How high was the cannon ball to have this much potential energy?
Fynjy0 [20]
The formula for potential energy is PE=mgh
It can have that high of a potential energy if it's relative height what super high.
7 0
2 years ago
A 10-kilogram box is at static equilibrium, and the downward pull of gravity acting on the box is 98 newtons. What is the minimu
Nikolay [14]
The box is at equilibrium, so the net force on the box is zero (the force of gravity on the box is equal to the force exerted up on the box by the surface on which it rests.)
To pick up the box, our upward force must be greater than the force of gravity on the box (the weight). So, we must lift up the box with a force greater than 98 newtons. :)
4 0
2 years ago
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A sailboat starts from rest and accelerates at a rate of 0.21 m/s^2 over a distance of 280 m. find the magnitude of the boat's f
sasho [114]

We use the kinematic equations,

v=u+at                                          (A)

S= ut + \frac{1}{2} at^2                  (B)

Here, u is initial velocity, v is final velocity, a is acceleration and t is time.

Given,  u=0, a=0.21 \ m/s^2 and s= 280 m.

Substituting these values in equation (B), we get

280 \ m = 0 +\frac{1}{2} (0.21 m/s^2) t^2 \\\\ t^2 = \frac{280 \times 2}{0.21 } \\\\ t= 51.63 \ s.

Therefore from equation (A),

v = 0 + (0.21) \times (51.63 s)= 10.84 \ m/s

Thus, the magnitude of the boat's final velocity is 10.84 m/s and the time taken by boat to travel the distance 280 m is 51.63 s



8 0
2 years ago
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