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dybincka [34]
1 year ago
8

A pitching machine is programmed to pitch baseballs horizontally at a speed of 87 mph . The machine is mounted on a truck and ai

med backward. As the truck drives away from a man at a speed of 65 mph, the machine shoots a ball towards him.
For each of the object pairings listed below, determine the correct relative speed.

a - The speed of the pitching machine relative to the truck

b - the speed of the pitched ball relative to the truck

c - the speed of the pitching machine relative to him

d - the speed of the pitched ball relative to him
Physics
1 answer:
Natalija [7]1 year ago
5 0

Answer:

A) The speed of the pitching machine relative to the truck is 0 m/s

B) the speed of the pitched ball relative to the truck is 87mph

C) the speed of the pitching machine relative to him is 65mph

D) the speed of the pitched ball relative to him is 87mph - 65mph = 22mph

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−5.0  

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a film of transparent material 120 nm thick and having refractive index 1.25 is placed on a glass sheet having refractive index
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Answer:

a) 600nm

b) 300nm

Explanation:

the path difference = 2t  

t = thickness of the film

L' = wavelength of light in film = L/n

L = wavength of light in air

n = refractive index of glass

(a)

for destructive interference 2t = L'/2 = L/2n

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= 4*120*10^-9*1.25  

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(b)

for constructive interference 2t = L' = L/1.25

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2 years ago
A brick and a feather fall to the earth at their respective terminal velocities. which object experiences the greater force of a
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A piece of luggage is being loaded onto an airplane by way of an inclined conveyor belt. The bag, which has a mass of 15.0 kg, t
LenKa [72]

Answer:

a) W = - 318.26 J, b)  W = 0 , c) W = 318.275 J , d) W = 318.275 J , e) W = 0

Explanation:

The work is defined by

           W = F .ds = F ds cos θ

Bold indicate vectors

We create a reference system where the x-axis is parallel to the ramp and the axis and perpendicular, in the attached we see a scheme of the forces

Let's use trigonometry to break down weight

     sin θ = Wₓ / W

     Wₓ = W sin 60

     cos θ = Wy / W

      Wy = W cos 60

X axis

How the body is going at constant speed

    fr - Wₓ = 0

    fr = mg sin 60

    fr = 15 9.8 sin 60

    fr = 127.31 N

Y Axis  

    N - Wy = 0

    N = mg cos 60

    N = 15 9.8 cos 60

    N = 73.5 N

Let's calculate the different jobs

a) The work of the force of gravity is

     W = mg L cos θ

Where the angles are between the weight and the displacement is

      θ = 60 + 90 = 150

     W = 15 9.8 2.50 cos 150

     W = - 318.26 J

b) The work of the normal force

     From Newton's equations

          N = Wy = W cos 60

          N = mg cos 60

         W = N L cos 90

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c) The work of the friction force

      W = fr L cos 0

      W = 127.31 2.50

      W = 318.275 J

d) as the body is going at constant speed the force of the tape is equal to the force of friction

      W = F L cos 0

      W = 127.31 2.50

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e) the net force

    F ’= fr - Wx = 0

    W = F ’L cos 0

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4 0
2 years ago
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Answer:

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A = πr^2 = π × (5×10^-4)^2 = 2.5×10^-7π

Eag = 1.47×10^-8I/2.5×10^-7π = 0.0588I/π

Ecu/Eag = 0.026875I/π × π/0.0588I = 0.46

7 0
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