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1 year ago

What visible signs indicate a precipitation reaction when two solutions are mixed?

Physics

1 answer:

Illusion [34]1 year ago

6 0

Formation of an insoluble solid

Explanation:

One of the remarkable visible signs that indicates a precipitation reaction when two solutions are mixed is the formation of an insoluble solid. The insoluble solid formed is the precipitate.

Precipitates usually forms in single replacement reactions and double replacement or double decomposition reactions.
They form when two soluble compounds react. One of the product is an insoluble solid in the solution called the precipitate.
The solubility table helps to predict whether precipitates forms in a reaction.

Learn more:

precipitate brainly.com/question/8896163

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The PVT behavior of a certain gas is described by the equation of state: P(V − b) = RT where b is a constant. If in addition CV

alexdok [17]

Answer:

shown in the attachment

Explanation:

The detailed step by step and necessary mathematical application is as shown in the attachment.

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2 years ago

Deep-sea divers often breathe a mixture of helium and oxygen to avoid getting the "bends" from breathing high-pressure nitrogen.

kvv77 [185]

Answer:

0.69444 m, 0.08152 m, 0.32407 m, 0.03804 m

Explanation:

v = Velocity of sound

f = Frequency

Length of vocal tract is given by

$L=\dfrac{v}{4f}$

At f = 270 Hz v = 750 m/s

$L=\dfrac{750}{4\times 270}\\\Rightarrow L=0.69444\ m$

At f = 2300 Hz v = 750 m/s

$L=\dfrac{750}{4\times 2300}\\\Rightarrow L=0.08152\ m$

At f = 270 Hz v = 350 m/s

$L=\dfrac{350}{4\times 270}\\\Rightarrow L=0.32407\ m$

At f = 2300 Hz v = 350 m/s

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3 0

1 year ago

suppose that 273 g of one of the substances listed above displaces 26 mL of water. What is the substance?

guajiro [1.7K]

<span>The unknown substance is silver. I don't see a list of available substances, but let's see if there's something reasonable available that will match. First, let's calculate the density of the unknown substance. Density is mass per volume, so 273 g / 26 mL = 10.5 g/mL Looking up a list of elements sorted by density, I see the following: 10.07 Actinium 10.22 Molybdenum 10.5 Silver 11.35 Lead And silver at 10.5 g/ml is a very nice match for the unknown substances' density of 10.5 g/ml.</span>

6 0

2 years ago

Read 2 more answers

An all female guitar septet is getting ready to go on stage. The lead guitarist, Kira,who is always in tune, plucks her low E st

matrenka [14]

Answer:

Buffy > Aiko > Chandra > Freja > Evita

Explanation:

Beats occur when two waves of nearby frequencies overlap. The number of beats per second is equal to the difference in the frequency.

Let

$f=$ Frequency of Kira

$f_1=$ Frequency of Aiko

The beat frequency of Kira and Aiko is therefore,

$f_{beat}=|f_2-f_1|$

Substituting $f$ for $f_2$ and $3Hz$ for $f_{beat}$ , we get

$3Hz=|f-f_1|\\f_1=f+3Hz$

From the above equation, we see that beats increase

when

$f_2 =$ Frequency of Chandra

The beat frequency of Kira and Chandra is therefore,

$1Hz=|f-f_2|\\f_2=f-1Hz$

From the above equation, we see that beats decrease

When

$f_3=$ Frequency of Evita

The beat frequency of Kira and Evita is therefore,

$5Hz=|f-f_3|\\f_3=f-5Hz$

From the above equation, we see that beats decrease

When

$f_4=$ Frequency of Freja

The beat frequency of Kira and Freja is therefore,

$3Hz=|f-f_4|\\f_4=f-3Hz$

From the equation above, we see that beats decrease

When

$f_5=$ Frequency of Buffy

The beat frequency of Kira and Buffy becomes,

$4Hz=|f-f_5|\\f_5=f+4Hz$

From the equation above, we see that beats increase

Hence, the rank of members based on initial frequencies from largest to smallest is Buffy > Aiko > Chandra > Freja > Evita

6 0

1 year ago

A lab technician uses laser light with a wavelength of 670 nm to test a diffraction grating. When the grating is 40.0 cm from th

Juliette [100K]

Answer:

N = 221.4 lines / mm

Explanation:

Given:

- The wavelength of the source λ = 670 nm

- Distance of the grating from screen B = 40.0 cm

- The distance of first bright fringe from central order P = 6.0 cm

Find:

How many lines per millimeter does this grating have?

Solution:

- The derived results from Young's experiment that relates the order of bright fringes about the central order is given by:

sin (Q) = n*λ*N

Where,

n is the order number 0, 1 , 2, 3 , ....

λ is the wavelength of the light source

Q is the angle of sweep respective fringe from central order

N is the number of lines/mm the grating has

- We will first compute the length along which the light travels for the first bright fringe:

L^2 = P^2 + B^2

L^2 = 40^2 + 6^2

L^2 = 1636

L = 40.45 cm

- Now calculate the sin(Q) that the fringe makes with the central order:

sin (Q) = P / L

sin (Q) = 6 / 40.45

- Now we will use the derived results:

N = sin(Q) / n*λ

Where, n = 1 - First order

Plug values in N = (6 / 40.45) / (670 *10^-6)

N = 221.4 lines / mm

8 0

2 years ago