Answer:
6.32 m/s 18.43° northeast
Explanation:
We express the velocity of hawk as:
We consider positive x towards east and positive y due north. So the magnitude is simply the square root of the square components:
![|v_{hawk}|=\sqrt[]{6^2+2^2}=\sqrt{40}](https://tex.z-dn.net/?f=%7Cv_%7Bhawk%7D%7C%3D%5Csqrt%5B%5D%7B6%5E2%2B2%5E2%7D%3D%5Csqrt%7B40%7D)
≈
And the angle with respect to the east should be with:
Answer:
V is approximately = 23m/s
Explanation:
Kinetic energy = ½ mv²
Where m= mass = 0.450kg
V= velocity =?
K. E = 119J
Therefore
K. E = ½ mv²
Input values given
119= ½ × 0.450 × v²
Multiply both sides by 2
119 ×2 = 2 × 1/2 × 0.450 × v²
238= 0.450v²
Divide both sides by 0.450
238/0.450 = 0.450v²/0.450
v² = 528.89
Square root both sides
Sq rt v² = sq rt 528.89
V = 22.998m/s
V is approximately = 23m/s
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Answer:
Answer:
Explanation:
It means that out of 20 students, 3 males and 1 female were digital screen addicts because they were getting dangerous amount of blue light. Thus couldn't feel calming sensation that a human feels while seeing blue light. The rest students were getting balanced blue light. So they were getting relaxed feeling while being exposed to blue light.
Answer:
t=7.14s
v=-69.972 m/s
Explanation:
Position function
Velocity is the derivative of position function
The time the object hit the ground can be find by the given function know that the position is going to be 0m
Check:
So the velocity can be find using the time discovery before and using the same function but with the derivate
The velocity is negative because the object is moving downward
