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Ipatiy [6.2K]
2 years ago
10

26. An ice-skater who weighs 200 N is gliding across the ice. If the force of friction is 4 N. what is the

Physics
1 answer:
Scrat [10]2 years ago
7 0

Answer:

0.02

Explanation:

coefficient of kinetic friction = μ

force of friction = Ff

Normal Force = FN, but

FN = -W

Ff = -μFN

so μ = Ff/FN

= 4N/200N

= 0.02.

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The length of a 60 W, 240 Ω light bulb filament is 60 cm Remembering that the current in the filament is proportional to the ele
faust18 [17]

Answer:

Finally current will be

i = 0.35 A

Explanation:

As we know that power of the bulb is given by the formula

P = \frac{V^2}{R}

now we have

P = 60 W

R = 240 ohm

so we have

60 = \frac{V^2}{240}

V = 120 Volts

now the current in the bulb is given as

i = \frac{V}{R}

i = \frac{120}{240} = 0.5 A

now when length of the filament is double

so the resistance of the wire also gets double

so we have

P = \frac{V^2}{R}

60 = \frac{V^2}{480}

V = 169.7 volts

now the current in the bulb is given as

V = i R

169.7 = i(480)

i = 0.35 A

8 0
2 years ago
The inventor of the photographic process in which a photograph produced without a negative by exposing objects to light on light
Nikolay [14]
<span>A. Man Ray --------------------</span>
7 0
1 year ago
Read 2 more answers
A very long, straight wire has charge per unit length 3.50×10^−10 C/m . At what distance from the wire is the electricfield magn
Dafna11 [192]

Answer:

r= 2.17 m

Explanation:

Conceptual Analysis:

The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:

E= 2k*(λ/r) Formula (1)

Where:

E: electric field .( N/C)

k: Coulomb electric constant. (N*m²/C²)

λ: linear charge density. (C/m)

r : distance from the charge line to the surface where E calculates (m)

Known data

E= 2.9  N/C

λ = 3.5*10⁻¹⁰ C/m

k= 8.99 *10⁹ N*m²/C²

Problem development

We replace data in the formula (1):

E= 2*k*(λ/r)

2.9= 2*8.99 *10⁹*(3.5*10⁻¹⁰/r)

r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)

r= 2.17 m

5 0
2 years ago
A device used to increase or decrease the emf in the second of two unconnected coils is a
grigory [225]
<span>The answer is transformer. They utilize electromagnetic induction to generate current. This is only possible in alternating current due to the differential increase and decrease of electrical current that induces changes in magnetic flux in the coil. This varies the magnetic flux of the primary coil that generates current in the secondary coil.</span>
4 0
2 years ago
Two workhorses tow a barge along a straight canal. Each horse exerts a constant force of magnitude F, and the tow ropes make an
morpeh [17]

Answer:

<em>a) Fvt cosθ</em>

<em>b) Fv cosθ</em>

<em></em>

Explanation:

Each horse exerts a force = F

the rope is inclined at an angle = θ

speed of each horse = v

a) In time t, the distance traveled d = speed x time

i.e d = v x t = vt

also, the resultant force = F cosθ

Work done W = force x distance

W = F cosθ x vt = <em>Fvt cosθ</em>

<em></em>

b) Power provided by the horse P = force x speed

P = F cosθ x v

P = <em>Fv cosθ</em>

8 0
1 year ago
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