r = radius of the circle of the ride = 3.00 meters
v = linear speed of the person during the ride = 17.0 m/s
m = mass of the person in angular motion in the ride
L = angular momentum of the person in the ride = 3570 kg m²/s
Angular momentum is given as
L = m v r
inserting the values
3570 kg m²/s = m (17 m/s) (3.00 m)
m = 3570 kg m²/s/(51 m²/s)
m = 7 kg
hence the mass comes out to be 7 kg
Answer:
18 times
Explanation:
According to the security purposes which is set under the rules and regulation OSHA, which describes all the rights to the worker.
In the boom hoist receiving system all the sheaves which are used should have a pitch diameter of rope not less than 18 times the diameter of the nominal rope which is used.
Answer:
the efficiency of hydralic is 79.88%
Explanation:
convert mm to m
1mm = (1/1000)m
diameter of pipe upsteam
d₁= 90mm= 0.09m
diameter of pipe downsteam
d₂= 30mm = 0.03m
finding velocity of upsteam
recall Q=A₁V₁
V₁=Q/A₁
V₁=3.14m/s
velocity of downsteam
V₂= Q/A₂
V₂= 28.29m/s
mass flow rate
m= ρQ
ρ is the density of water
m = 1000× 0.02
m= 20kg/s
the efficiency of hydralic is 79.88%
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Answer:
Explanation:
Since the roundabout is rotating with uniform velocity ,
input power = frictional power
frictional power = 2.5 kW
frictional torque x angular velocity = 2.5 kW
frictional torque x .47 = 2.5 kW
frictional torque = 2.5 / .47 kN .m
= 5.32 kN . m
= 5 kN.m
b )
When power is switched off , it will decelerate because of frictional torque .
