Answer:
<em>The glider's new speed is 68.90 m/s</em>
Explanation:
<u>Principle Of Conservation Of Mechanical Energy</u>
The mechanical energy of a system is the sum of its kinetic and potential energy. When the only potential energy considered in the system is related to the height of an object, then it's called the gravitational potential energy. The kinetic energy of an object of mass m and speed v is

The gravitational potential energy when it's at a height h from the zero reference is

The total mechanical energy is


The principle of conservation of mechanical energy states the total energy is constant while no external force is applied to the system. One example of a non-conservative system happens when friction is considered since part of the energy is lost in its thermal manifestation.
The initial conditions of the problem state that our glider is glides at 416 meters with a speed of 45.2 m/s. The initial mechanical energy is

Operating in terms of m


Then we know the glider dives to 278 meters and we need to know their final speed, let's call it
. The final mechanical energy is

Operating and factoring

Both mechanical energies must be the same, so

Simplifying by m and rearranging

Computing

The glider's new speed is 68.90 m/s
12.5 times 14 and convert to meters its 1.75 meters per second
Answer:
The temperature change in Celsius is 46°C.
The temperature change in Fahrenheit is 82.8°F.
Explanation:
A degree of Celsius scale is equal to that of kelvin scale; therefore,

A degree in Fahrenheit is 1.8 times the Celsius degree; therefore


Hence, the temperature change in Celsius is 46°C, and the temperature change in Fahrenheit is 82.8°F.
Would presume the energy as kinetic energy.
E = (1/2)*mv²
But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3* 10⁸ m/s
Ke = (1/2)*mv² = 0.5*0.05*(0.7*<span>3* 10⁸)</span>² = 1.1025 * 10¹⁵ Joules
There is no exact match from the options.
<em>If the distance between the two objects is the same, then;</em>
Both the magnet and the coil moving toward each other at 10 cm/s each
A reversed polarity magnet moving away from the coil at 20 cm/s
<u>Calculate current that produces a magnetic field, and use the right hand rule 2, to determine the direction of current or the direction of magnetic field loops. </u>