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Nana76 [90]
2 years ago
10

Jin walked 4 km on a straight path to get to the sandwich shop. He traveled 30° south of east.

Physics
2 answers:
Molodets [167]2 years ago
3 0

Answer: -2 km

Explanation:

If we imagine Jin's movement to be the hypothenuse of a right triangle, then the southern component of Jin's movement corresponds to the side of the triangle opposite to the angle of 30 degrees. Therefore, the magnitude of this southern component is given by

However, the angle of 30 degrees is south of east: this means that the direction of this southern component is south, and since we generally take north as positive direction, we must add a negative sign, so the correct answer is

-2 km

DanielleElmas [232]2 years ago
3 0

Answer: The component is 2km

Explanation:

Jim walked 4km on a straight path, and the angle is 30° south of the east (so, looking at the east direction, he walked with 30° angle in direction to the south)

So in the rectangle triangle, the east segment is the adjacent side, and the south segment is the opposite side. And 4km is the length of the hypotenuse.

Here you can remember the rule:

soh-cah-toa

this means Sin(a)=Opposite side/hypotenuse

cos(a) = adjacent side/hypotenuse

tan(a) = opposite side/adjacent side

where a is the angle, in this case, a= 30°

Them if we want to find the southern component, we must do:

S = 4km*sin(30°) = 2km

Them the component in the southern direction is 2km

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Would presume the energy as kinetic energy.

E = (1/2)*mv²

But m = 0.05kg, velocity here = 0.70c, where c is the speed of light ≈ 3* 10⁸ m/s

Ke =  (1/2)*mv² = 0.5*0.05*(0.7*<span>3* 10⁸)</span>² = 1.1025 * 10¹⁵ Joules


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5. A nail contains trillions of electrons. Given that electrons repel from each other, why do they not then fly out of the nail?
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Answer:

Nails are made of iron. Iron consists of 26 protons and 26 electrons. protons are positively charged and electrons are negatively charged, so this force of attraction keeps the electrons together.

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1 year ago
Dźwig podniósł kontener o masie m = 80 kg na wysokość h = 10 m. Pierwsze 5 m kontener przebył z przy-
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Answer:

a)   W_total = 8240 J , b)  W₁ / W₂ = 1.1

Explanation:

In this exercise you are asked to calculate the work that is defined by

       W = F. dy

As the container is rising and the force is vertical the scalar product is reduced to the algebraic product.

       W = F dy = F Δy

let's apply this formula to our case

a) Let's use Newton's second law to calculate the force in the first y = 5 m

          F - W = m a

          W = mg

          F = m (a + g)

          F = 80 (1 + 9.8)

          F = 864 N

The work of this force we will call it W1

   We look for the force for the final 5 m, since the speed is constant the force must be equal to the weight (a = 0)

        F₂ - W = 0

        F₂ = W

        F₂ = 80 9.8

        F₂ = 784 N

The work of this fura we will call them W2

The total work is

         W_total = W₁ + W₂

         W_total = (F + F₂) y

         W_total = (864 + 784) 5

         W_total = 8240 J

b) To find the relationship between work with relate (W1) and work with constant speed (W2), let's use

        W₁ / W₂ = F y / F₂ y

        W₁ / W₂ = 864/784

        W₁ / W₂ = 1.1

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An object of mass M is dropped near the surface of Earth such that the gravitational field provides a constant downward force on
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Answer:

The answer is: c. It does not move

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