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2 years ago

Jin walked 4 km on a straight path to get to the sandwich shop. He traveled 30° south of east.

Physics

2 answers:

Molodets [167]2 years ago

3 0

Answer: -2 km

Explanation:

If we imagine Jin's movement to be the hypothenuse of a right triangle, then the southern component of Jin's movement corresponds to the side of the triangle opposite to the angle of 30 degrees. Therefore, the magnitude of this southern component is given by

However, the angle of 30 degrees is south of east: this means that the direction of this southern component is south, and since we generally take north as positive direction, we must add a negative sign, so the correct answer is

-2 km

DanielleElmas [232]2 years ago

3 0

Answer: The component is 2km

Explanation:

Jim walked 4km on a straight path, and the angle is 30° south of the east (so, looking at the east direction, he walked with 30° angle in direction to the south)

So in the rectangle triangle, the east segment is the adjacent side, and the south segment is the opposite side. And 4km is the length of the hypotenuse.

Here you can remember the rule:

soh-cah-toa

this means Sin(a)=Opposite side/hypotenuse

cos(a) = adjacent side/hypotenuse

tan(a) = opposite side/adjacent side

where a is the angle, in this case, a= 30°

Them if we want to find the southern component, we must do:

S = 4km*sin(30°) = 2km

Them the component in the southern direction is 2km

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jasenka [17]

Weight of the carriage $=(m+M)g =142.1\ N$

Normal force $=Fsin(\theta) + W = 197.1\ N$

Frictional force $=\mu N=27.59\ N$

Acceleration $=4.66\ m\ s^{-2}$

Explanation:

We have to look into the FBD of the carriage.

Horizontal forces and Vertical forces separately.

To calculate Weight we know that both the mass of the baby and the carriage will be added.

So Weight(W) $=(m+M)\times g =(9.5+5)\ kg \times 9.8 =142.1\ Newton\ (N)$

To calculate normal force we have to look upon the vertical component of forces, as Normal force is acting vertically.We have weight which is a downward force along with $F_x$ , force of $110\ N$ acting vertically downward.Both are downward and Normal is upward so Normal force $=Summation\ of\ both\ forces$

Normal force (N) $= Fsin(\theta)+W=110sin(30) + 142.1 =197.1\ N$

Frictional force (f) $=\mu N=0.14\times 197.1 =27.59\ N$

To calculate acceleration we will use Newtons second law.

That is Force is product of mass and acceleration.

We can see in the diagram that $F_y=Horizontal$ and $F_x=Vertical$ component of forces.

So Fnet = Fy(Horizontal) - f(friction) $= m\times a$

Acceleration (a) = $\frac{Fcos(\theta)-\mu N}{mass(m)} =\frac{(95.26-27.59)}{14.5}= 4.66\ m\ s{^2 }$

So we have the weight of the carriage, normal force,frictional force and acceleration.

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2 years ago

If a force of 65 N is exerted on a 45 kg sofa and the sofa is moved 6.0 meters, how much work is done in moving the sofa? 17,550

abruzzese [7]

Answer:

The answer to your question is: W = 390 J

Explanation:

Work is the transfer of energy when a body is moved from one place to another.

Data

Force = 65 N

mass = 45 kg

distance = 6 meters

work = ? J

Formula

W = F x d

Process

W = 65 N x 6 m

W = 390 J

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2 years ago

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NemiM [27]

Answer:

f3 = 102 Hz

Explanation:

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L: length of the pipe = 2.5 m

You replace the values of n, L and vs in order to calculate the frequency:

$f_{3}=\frac{(3)(340m/s)}{4(2.5m)}=102\ Hz$

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vodomira [7]

Answer:

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