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Troyanec [42]
2 years ago
12

yami pours powdered cocoa mix into milk and stirs it. then she microwaves the mixture for three minutes. when she takes the cup

out, the handle is very warm. steam rises from the cup, so she blows it before taking a sip. in which part of this scenario can convection be best observed
Physics
2 answers:
MrRa [10]2 years ago
6 0
Convection can best be observed as she blows the warm steam air that rises.

As the warm steam rises,  she forces displaces it with cool air from her mouth. Because the warm steam is less dense it rises and because the cool air is more dense, it displaces the warm air.

This scenario is an example of convection.
 
MArishka [77]2 years ago
4 0

The correct answer is:

C. Rising steam from the cup of cocoa.

Rising steam from the cup of cocoa is the part of this scenario that convection can be best observed.

|Huntrw6|

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Tech A says that some electric actuators are positioned by an A/C ECU which checks the air flow with sensors. Tech B says that e
Sedbober [7]

Answer:

Tech B

Explanation:

The control of electric actuators may be through through a two-wire or a five-wire circuit through the driver circuit by bidirectionally controlling via the motor wire polarity. The door position is determined by counting the actuator commutator pulses by the control module in the actuator with 2-wire, while the actuator with 5-wire uses potentiometer feedback.

The A/C ECU is the Air Condition Engine Control Unit.

7 0
2 years ago
Modern wind turbines generate electricity from wind power. The large, massive blades have a large moment of inertia and carry a
horsena [70]

Answer:

a)106.48 x 10⁵ kg.m²

b)144.97 x 10⁵  kgm² s⁻¹  

Explanation:

a)Given

m = 5500 kg

l = 44 m

Moment of inertia of one blade

I= 1/3 x m l²

where m is mass of the blade

l is length of each blade.

Putting all the required values, moment of inertia of one blade will be

I= 1/3 x 5500 x 44²  

I= 35.49 x 10⁵ kg.m²

Moment of inertia of 3 blades

I= 3 x 35.49 x 10⁵ kg.m²

I= 106.48 x 10⁵ kg.m²

b) Angular momentum 'L' is given by

L =I x ω

where,

I= moment of inertia of turbine i.e  106.48 x 10⁵ kg.m²

ω=angular velocity =2π f

f is frequency of rotation of blade i.e  13 rpm

f = 13 rpm=>= 13 / 60 revolution per second

ω = 2π f =>  2π  x  13 / 60 rad / s

L=I x ω =>106.48 x 10⁵ x   2π  x  13 / 60

  = 144.97 x 10⁵  kgm² s⁻¹    

7 0
2 years ago
A skateboarder travels on a horizontal surface with an initial velocity of 3.2 m/s toward the south and a constant acceleration
Naddika [18.5K]

Answer:

A. 0.432

B. -1.92

C. 1.44 units/second

D. -3.2 units/second

Explanation:

A. To calculate her x position, we just use the following equation of motion to find the distance traveled:

    s=u*t+\frac{1}{2} (a*t^2)

here s = displacement

t = time (in seconds)

a = acceleration

Solving for the distance, we get:

s = 0 * 0.6 + \frac{1}{2}(2.4 * 0.6^2)

s = 0.432 m

Since 0.432 meters east is equals to 0.432 meter in the positive x-direction, the x position is also 0.432.

B. Since the skater has a constant v - velocity of -3.2 m/s, (south means negative y axis), the total distance traveled is:

Distance = speed * time = -3.2 * 0.6 = -1.92 m

The answer is -1.92 units in the y-axis.

C. The x velocity component is the final speed in the east direction, which is going to be:

v^2 - u^2=2*a*s

v^2 = 2*2.4*0.432

v = 1.44 units/second (in positive x direction)

D. Her y velocity component does not change, since the velocity towards the south is a constant 3.2 m/s

Thus the answer is -3.2 units/second in the y-axis.

8 0
2 years ago
An airliner of mass 1.70×105kg1.70×105kg lands at a speed of 75.0 m/sm/s. As it travels along the runway, the combined effects o
Karo-lina-s [1.5K]

Answer:

The airliner travels 1.65 km along the runway before coming to a halt.

Explanation:

Given

Resistive forces = (2.90 × 10⁵) N = 290000 N

Mass of the airliner = (1.70 × 10⁵) kg = 170000 kg

Velocity of airliner = 75 m/s

Let the distance over moved by the airliner be equal to d

According to the work-energy theorem, the work done by the resistive forces in stopping the airliner is equal to the travelling kinetic energy of the airliner.

Work done by the resistive forces = (290000) × d = (290,000d) J

Kinetic energy of the airliner = (1/2)(170000)(75²) = 478,125,000 J

290000d = 478,125,000

d = (478,125,000/290,000)

d = 1648.7 m = 1.65 km

Hope this helps!!!

4 0
2 years ago
A body covers a semicircle of radius 7cm in 5s .find its linear speed
choli [55]

Ok so we are given the radius of 7cm and time of 5 seconds.

From the data we got we can calculate speed, frequency, perimeter and area of the semicircle.

Let's start with perimeter.

We know that perimeter of circle is 2\pi r so the perimeter of semicircle is \dfrac{2\pi r}{2} or simply \pi r

So the perimeter is equal to:

\pi r=\pi\cdot7\approx\boxed{22cm}

So this is the length of a curve or let's say the distance.

Now let's look at the linear speed s=\dfrac{d}{t} where d is distance and t time.

We know the distance and we know the time.

So let's calculate it.

s=\dfrac{d}{t}=\dfrac{22}{5}=\boxed{4.4\dfrac{cm}{s}}

Hope this helps.

r3t40

8 0
2 years ago
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