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Troyanec [42]
2 years ago
12

yami pours powdered cocoa mix into milk and stirs it. then she microwaves the mixture for three minutes. when she takes the cup

out, the handle is very warm. steam rises from the cup, so she blows it before taking a sip. in which part of this scenario can convection be best observed
Physics
2 answers:
MrRa [10]2 years ago
6 0
Convection can best be observed as she blows the warm steam air that rises.

As the warm steam rises,  she forces displaces it with cool air from her mouth. Because the warm steam is less dense it rises and because the cool air is more dense, it displaces the warm air.

This scenario is an example of convection.
 
MArishka [77]2 years ago
4 0

The correct answer is:

C. Rising steam from the cup of cocoa.

Rising steam from the cup of cocoa is the part of this scenario that convection can be best observed.

|Huntrw6|

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What is the threshold frequency for sodium metal if a photon with frequency 6.66 × 1014 s−1 ejects a photon with 7.74 × 10−20 J
FrozenT [24]

Answer:

5.5 × 10^14 Hz or s^-1

no orange light has less frequency so no photoelectric effect

Explanation:

hf = hf0 + K.E

HERE h is Planck 's constant having value 6.63 × 10 ^-34 J s

f is frequency of incident photon and f0 is threshold frequency

hf0 = hf- k.E

6.63 × 10 ^-34 × f0 = 6.63 × 10 ^-34× 6.66 × 10^14 - 7.74× 10^-20

6.63 × 10 ^-34 × f0 = 3.64158×10^-19

                           f0 = 3.64158×10^-19/ 6.63 × 10 ^-34

                           f0 = 5.4925 × 10^14

                            f0 =5.5 × 10^14 Hz or s^-1

frequency of orange light is 4.82 × 10^14 Hz which is less than threshold frequency hence photo electric effect will not be observed for orange light

8 0
2 years ago
Water in the lake behind hoover dam is 221 m deep. part a what is the gauge water pressure at the base of the dam?
iragen [17]
<span>Answer: Pressure is always density * gravity * depth P = 1000 kg/m^3 * 9.81 m/s^2 * 221 m P = 2168010 Pa</span>
4 0
2 years ago
Read 2 more answers
Object A with a mass of 500 kilograms hits stationary object B with a mass of 920 kilograms. If the collision is elastic, what h
Vika [28.1K]
In elastic collision, both the kinetic energy and momentum are conserved. Conservation means that both the kinetic energy and momentum will have the same values before and after elastic collision.

<span>As the object A has low mass than object B. Hence upon collision, object B moves forward, while object A will move backward. So option "C" is correct. </span>

5 0
2 years ago
If a rock is thrown upward on the planet mars with a velocity of 14 m/s, its height (in meters) after t seconds is given by h =
crimeas [40]

<u>Answer:</u>

 Velocity of rock after 2 seconds = 6.56 m/s

<u>Explanation:</u>

 We have equation of motion , s= ut+\frac{1}{2} at^2, s is the displacement, u is the initial velocity, a is the acceleration and t is the time.

Here height of rock in meters, h = 14t-1.86t^2

Comparing both the equations

    We will get initial velocity = 14 m/s(already given) and \frac{1}{2} a = -1.86

     So,  Acceleration, a = -3.72 m/s^2

 Now we have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.

 When time is 2 seconds we need to find final velocity.

     v = 14 - 3.72 * 2 = 6.56 m/s.

  So, Velocity of rock after 2 seconds = 6.56 m/s  

6 0
2 years ago
An electric drill transfers 200 J of energy into a useful kinetic energy store. It also transfers 44 J of energy by sound and 48
kramer

Answer:

Er = 108 [J]

Explanation:

To solve this problem we must understand that the total energy is 200 [J]. Of this energy 44 [J] are lost in sound and 48 [J] are lost in heat. In such a way that these energy values must be subtracted from the total of the kinetic energy.

200 - 44 - 48 = Er

Where:

Er = remaining energy [J]

Er = 108 [J]

3 0
2 years ago
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