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Troyanec [42]
2 years ago
12

yami pours powdered cocoa mix into milk and stirs it. then she microwaves the mixture for three minutes. when she takes the cup

out, the handle is very warm. steam rises from the cup, so she blows it before taking a sip. in which part of this scenario can convection be best observed
Physics
2 answers:
MrRa [10]2 years ago
6 0
Convection can best be observed as she blows the warm steam air that rises.

As the warm steam rises,  she forces displaces it with cool air from her mouth. Because the warm steam is less dense it rises and because the cool air is more dense, it displaces the warm air.

This scenario is an example of convection.
 
MArishka [77]2 years ago
4 0

The correct answer is:

C. Rising steam from the cup of cocoa.

Rising steam from the cup of cocoa is the part of this scenario that convection can be best observed.

|Huntrw6|

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Given that average speed is distance traveled divided by time, determine the values of m and n when the time it takes a beam of
schepotkina [342]
If speed = distance/time , then time = speed/distance.

So...

Speed of light = 3*10^8(m/s)
Average distance from Earth to Sun = 149.6*10^9(m)

Therefore, t=(3*10^8(m/s))/(149.6*10^9(m))

I hope this was a helpful explanation, please reply if you have further questions about the problem.

Good luck!
5 0
1 year ago
Given a triangle with sides X = 6.35 cm and Y = 12.25 cm with an angle of 90 degrees between them, find the length of the hypote
never [62]

Answer:

the hypotenuse = 13.78 cm

Ф = 27.44°

θ = 62.56°

explanation:

4 0
2 years ago
Two identical metal spheres A and B are in contact. Both are initially neutral. 1.0× 10 12 electrons are added to sphere A, then
Vilka [71]

Answer:

8 x 10^-8 C on both the spheres.

Explanation:

Number of electrons added to A = 1 x 10^12

As the sphere A and B are identical to each other so the charge is shared equally.

Charge of one electron = 1.6 x 10^-19 C

Charge on A after wards

= number of electrons after wards x charge of one electron

qA = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

Similarly, the charge on sphere B afterwards

= number of electrons after wards x charge of one electron

qB = 0.5 x 10^12 x 1.6 x 10^-19 = 8 x 10^-8 C

8 0
2 years ago
For this exercise, use the position function s(t) = −4.9t2 + 250, which gives the height (in meters) of an object that has falle
nignag [31]

Answer:

t=7.14s

v=-69.972 m/s

Explanation:

Position function

s(t)=-4.9*t^{2}+250

Velocity is the derivative of position function

V(t)=\frac{dx}{dt}\\V(t)=-2*4.9*t\\V(t)=-9.8*t

The time the object hit the ground can be find by the given function know that the position is going to be 0m

s(t)=-4.9*t^{2}+250

s(t)=0\\0=-4.9*t^{2} +250\\t=\sqrt{\frac{250}{4.9}}\\t=7.14s

Check:

s(7.14)=-4.9*(7.14s)^{2}+250\\ s(7.14)=-250+250\\s(7.14)=0m

So the velocity can be find using the time discovery before and using the same function but with the derivate

V(t)=-2*4.9*t\\V(7.14)=-2*4.9*(7.14)\\V(7.14)=-69.972 \frac{m}{s}

The velocity is negative because the object is moving downward

6 0
2 years ago
Three solid, uniform, cylindrical flywheels, each of mass 65.0 kg and radius 1.47 m, rotate independently around a common axis t
Mkey [24]

Answer:

the angular momentum is 1015.52 kg m²/s

Explanation:

given data

mass of each flywheel, m = 65 kg

radius of flywheel, r = 1.47 m

ω1 = 8.94 rad/s

ω2 = - 3.42 rad/s

to find out

magnitude of the net angular momentum

solution

we get here Moment of inertia that is express as

I = 0.5 m r²    .................1

put here value and we get

I = 0.5 × 65 × 1.47 × 1.47

I = 70.23 kg m²

and

now we get here Angular momentum that is express as

L = I × ω    ...........................2

and Net angular momentum will be

L = 2 × I x ω1 - I × ω2

put here value and we get

L = 2 × 70.23 × 8.94 - 70.23 × 3.42

L = 1015.52 kg m²/s

so

the angular momentum is 1015.52 kg m²/s

3 0
2 years ago
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