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svp [43]
2 years ago
14

An astronaut takes what he measures to be a 10-min nap in a space station orbiting Earth at 8000 m/s. A signal is sent from the

station to Earth at the instant he falls asleep, and a second signal is sent to Earth the instant he wakes. Part A Does an observer on Earth measure the astronaut's nap as being shorter than, longer than, or equal to 10 min? Does an observer on Earth measure the astronaut's nap as being shorter than, longer than, or equal to 10 ? a. equal b. shorter c. longer
Physics
1 answer:
svet-max [94.6K]2 years ago
3 0

Answer:

longer than

Explanation:

given,

time of nap = 10 min

speed of orbiting earth = 8000 m/s

c is the speed of light

using the equation of time dilation

t' = \dfrac{t}{\sqrt{1-\dfrac{v^2}{c^2}}}

now inserting all the values

t' = \dfrac{10}{\sqrt{1-\dfrac{8000^2}{3\times 10^8)^2}}}

t' = \dfrac{10}{0.9999}

t' = 10.001 s

on solving the above equation we will get a value greater than 10minutes.

hence, On earth time of nap measured will be longer than 10 min

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A 1-m-long monopole car radio antenna operates in the AM frequency of 1.5 MHz. How muchcurrent is required to transmit 4 W of po
Zanzabum

Answer:

The current needed to transmit Power of 4 W is 28.47 A

Solution:

As per the question:

Length of the antenna, L_{a} = 1 m

Frequency, \vartheta = 1.5 MHz = 1.5\times 10^{6} Hz

Power transmitted, P_{t} = 4 W

Now,

For a monopole antenna:

\lambda_{a} = \frac{c}{\vartheta}

where

\lambda_{a} = wavelength transmitted by the antenna

c = speed of light in vacuum

\lambda_{a} = \frac{3\times 10^{8}}{1.5\times 10^{6}} = 200 m

Now,

Since, the value of \lambda_{a} >> L_{a} thus the monopole is a Hertian monopole.

The resistance is calculated as:

R = \frac{1}{2}(\frac{dL_{a}}{\lambda_{a}})^{2}\times 80\pi^{2}

R = \frac{1}{2}(\frac{1}{200)^{2}\times 80\pi^{2} = 9.869\times 10^{- 3} = 9.869 m\Omega

P_{radiated} = P_{t}

P_{radiated} = \frac{R}{I^{2}}

Now, the current I is given by:

I = \sqrt{\frac{2P_{t}}{R}} = \sqrt{\frac{2\times 4}{9.869\times 10^{- 3}}} = 28.47 A

5 0
2 years ago
Katie rolls a toy car off the end of a table.
hoa [83]

Answer: C.

Explanation:

i choose B and got it wrong it told me the answer after on edge.

4 0
2 years ago
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The following represents a process used to assemble a chair with an upholstered seat. stationsa, b, and c make the seat; station
Mekhanik [1.2K]

There are three questions here:


A. The possible daily output of this process if there is 8 processing time each day?


the time it takes to assemble a chair in seconds = A + B + C + J + K + L + X + Y + Z  

which is equal to = 38 + 34 + 35 + 32 + 30 + 34 + 22 + 18 + 20 =263 per chair



Processing hours = 8 hours x 60 minutes x 60 seconds

= 8 x 60 x 60


= 480 x 60 = 28,800 seconds is available in an 8 hr day.



28,800 / 263 =109.5057034220532


Therefore, It is possible to make 109 chairs in an 8 hour day.



B. Given your output rate in above, what is the efficiency of the process?


The time it takes to assemble a chair in seconds = A+ B + C + J + K + L + X + Y + Z.


= 34 + 34 + 34 + 30 + 30 + 30 + 22 + 18 + 20 = 252.6315789473684 per chair


A total of 252 per chair


Processing hours = 8 hours x 60 minutes x 60 seconds


= 8 x 60 x 60


= 480 x 60 = 28,800 seconds is available in an 8 hour day


= 28,000 / 252 = 114.2857142857143114 chairs


= 109/114 x 100 = 95.6140350877193


Therefore, the efficiency of making the chair is 95.61%


C. What is the flow time of the process?


Flow time is the period that it takes a completed chair to flow through the process from the beginning assemblage step to the last step. Take note that ABC and JKL are parallel legs in the process, and as a result both do not include to flow time to the procedure. In addition, Flow time comprises both pass time and run time at each position in the procedure.

7 0
2 years ago
Calculate the force a 70.0-kg high jumper must exert on the ground to produce an upward acceleration 4.00 times the acceleration
worty [1.4K]

Answer:

3433.5 N

Explanation:

g = Acceleration due to gravity = 9.81 m/s²

m = Mass of person = 70 kg

According to the question

a = Acceleration

4g=4\times 9.81\\\Rightarrow a=39.24\ m/s^2

Balancing the forces we have

F-w=ma\\\Rightarrow F=ma+w\\\Rightarrow F=ma+mg\\\Rightarrow F=m(a+g)\\\Rightarrow F=70(39.24+9.81)\\\Rightarrow F=3433.5\ N

The required force is 3433.5 N

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2 years ago
Slick Willy is in traffic court (again) contesting a $50.00 ticket for running a red light. "You see, your Honor, as I was appro
Masteriza [31]

Answer:

61578948 m/s

Explanation:

λ_{actual} = λ_{observed} \frac{c+v_{o}}{c}

687 = 570 (\frac{3 * 10^{8} +v_{o} }{3 * 10^{8}} )

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So Slick Willy was travelling at a speed of 61578948 m/s to observe this.

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