Answer:
The charge is moving with the velocity of
.
Explanation:
Given that,
Charge 
Angle = 35°
Magnetic field strength 
Magnetic force 
We need to calculate the velocity.
The Lorentz force exerted by the magnetic field on a moving charge.
The magnetic force is defined as:


Where,
F = Magnetic force
q = charge
B = Magnetic field strength
v = velocity
Put the value into the formula




Hence, The charge is moving with the velocity of
.
Answer:
-5.1 kg m/s
Explanation:
Impulse is the change in momentum.
Change in momentum= final momentum - initial momentum=m
+m
Plugging in the values= -0.15*24 - (0.15*10) (The motion towards the pitcher is negative as the initial motion is considered to be positive)
Impulse=-5.1 kg m/s (-ve means that it is the impulse towards the pitcher)
The amplitude of a wave corresponds to its maximum oscillation of the wave itself.
In our problem, the equation of the wave is
![y(x,t)= (0.750cm)cos(\pi [(0.400cm-1)x+(250s-1)t])](https://tex.z-dn.net/?f=y%28x%2Ct%29%3D%20%280.750cm%29cos%28%5Cpi%20%5B%280.400cm-1%29x%2B%28250s-1%29t%5D%29)
We can see that the maximum value of y(x,t) is reached when the cosine is equal to 1. When this condition occurs,

and therefore this value corresponds to the amplitude of the wave.
Answer:
a) The maximum possible acceleration the truck can give the SUV is 7.5 meters per second squared
b) The force of the SUV's bumper on the truck's bumper is 18000 newtons
Explanation:
a) By Newton's second law we can find the relation between force and acceleration of the SUV:

With F the maximum force the truck applies to the SUV, m the mass of the SUV and a the acceleration of the SUV; solving for a:

b) Because at this acceleration the truck's bumper makes a force of 18000 N on the SUV’s bumper by Third Newton’s law the force of the SUV’s bumper on the truck’s bumper is 18000 N too because they are action-reaction force pairs.
Answer:
19.6 m
Explanation:
The total motion of the golf ball lasts 4.0 seconds: since the motion is symmetrical, it takes 2.0 s for the ball to reach the highest point and then another 2.0 s to land back on the tee.
Therefore, we can just analyze the second half of the motion that lasts
t = 2.0 s
During this time, the vertical distance covered by the ball is given by the equation:

where
u = 0 is the initial velocity (zero because the ball starts from its highest point, where the velocity is zero)
t = 2.0 s
g = 9.8 m/s^2 is the acceleration of gravity
Solving for d, we find:

So, the ball reaches a maximum height of 19.6 m.