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TEA [102]
2 years ago
7

A wave with an amplitude of 9.3 mm is traveling along a string whose linear mass density is 230 g/m and whose tension is 65 N. I

f the frequency of the wave is 60 Hz, at what rate does it transfer energy?

Physics
1 answer:
dsp732 years ago
3 0

Answer:

The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )

Explanation:

The required quantity is the average power or average rate of energy transfer which differs from the maximum or instantaneous rate of energy transfer. The calculation steps to the answer above can be found in the attachment below. Should the requested quantity be the instantaneous quantity the answer will be 2 x Pav which equals 47.52W or 47.52J/s.

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A. The horizontal velocity is 
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c. m = sin(4πt + π/2) / [<span>πt + cos(4πt + π/2)]

d. m = </span>sin(4π/6 + π/2) / [π/6 + cos(4π/6 + π/2)]

e. t = -1.0

f. t = -0.35

g. Solve for t 
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vy = 4π cos (4πt + π/2) = 0
The substitute back to solve for vymax

i. s(t) = [<span>x(t)^2 + y</span>(t)^2]^(1/2)

h. s'(t) = d [x(t)^2 + y(t)^2]^(1/2) / dt

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d [x(t)^2 + y(t)^2]^(1/2) / dt = 0
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5 0
2 years ago
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What is the Physics Primer?
Elza [17]

Answer:

A. a set of mathematically topics that are relevant to introductory physics.

Explanation:

The physics primer is not defined as the online comprehensive mathematics textbooks. It is the set of topics of mathematics which gives students trouble and remember.

Therefore, it is defined as the process of physics problem solving. So, mathematically skills are covered in physics course as a primer related success.

Therefore, it is a set of topics of mathematics that are relevent to introductory physics.

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2 years ago
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Select examples of simple harmonic motion that can be observed in everyday life.
liberstina [14]
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2 years ago
A 2200 kg truck has put its front bumper against the rear bumper of a 2400 kg SUV to give it a push. With the engine at full pow
leonid [27]

Answer:

a) The maximum possible acceleration the truck can give the SUV is 7.5 meters per second squared

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Explanation:

a) By Newton's second law we can find the relation between force and acceleration of the SUV:

F=ma

With F the maximum force the truck applies to the SUV, m the mass of the SUV and a the acceleration of the SUV; solving for a:

a=\frac{F}{m}=\frac{18000}{2400}\approx7.5\,\frac{m}{s^{2}}

b) Because at this acceleration the truck's bumper makes a force of 18000 N on the SUV’s bumper by Third Newton’s law the force of the SUV’s bumper on the truck’s bumper is 18000 N too because they are action-reaction force pairs.

7 0
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Answer:

The answer is not correct.

Explanation:

Stu's answer is not correct, the equation to use is known as the law of ohm. In which the voltage is defined as the product of the current by the resistance, then we will see this equation.

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In order to find resistance, this term is found multiplying the current on the right side of the equation, therefore the current will be divided on the left side of the equation.

R=\frac{V}{I} \\replacing:\\R=\frac{4}{0.5} \\R=8[ohms]

That is the reason that the result found by Stu is not correct.

6 0
2 years ago
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