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TEA [102]
2 years ago
7

A wave with an amplitude of 9.3 mm is traveling along a string whose linear mass density is 230 g/m and whose tension is 65 N. I

f the frequency of the wave is 60 Hz, at what rate does it transfer energy?

Physics
1 answer:
dsp732 years ago
3 0

Answer:

The rate of transfer of energy is equal to 23.76W or 23.76J/s as may be required both forms are correct. The physical quantities needed to calculate the rate of energy transfer are the linear mass density or mass per unit length, tension force, amplitude, angular frequency( which is equal to 2pi •f )

Explanation:

The required quantity is the average power or average rate of energy transfer which differs from the maximum or instantaneous rate of energy transfer. The calculation steps to the answer above can be found in the attachment below. Should the requested quantity be the instantaneous quantity the answer will be 2 x Pav which equals 47.52W or 47.52J/s.

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. A lightbulb with a resistance of 2.9 ohms is operated using a 1.5-volt battery. At what rate is
Kobotan [32]

Answer:

Explanation:

Given that,

A light bulb has a resistance of 2.9ohms

R = 2.9 ohms

And a battery of 1.5V is applied

V = 1.5 V

We want to find the rate of energy transformed

First we need to know what rate of energy is

Rate of energy implies that we want to find power. Power is the rate at which work is done

P = Workdone / time

Then,

In electronic, the power dissipated by a resistor is given as

P = V² / R

P = 1.5² / 2.9

P = 0.7759 W

P ≈ 0.776 W

So, the rate at which electrical energy transformed in the lightbulb is 0.776 Watts

8 0
2 years ago
Read 2 more answers
An airplane pilot wishes to fly directly westward. According to the weather bureau, a wind of 75.0 km/hour is blowing southward.
Alex17521 [72]

Answer:

The speed of the plane relative to the ground is 300.79 km/h.

Explanation:

Given that,

Speed of wind = 75.0 km/hr

Speed of plane relative to the air = 310 km/hr

Suppose, determine the speed of the plane relative to the ground

We need to calculate the angle

Using formula of angle

\sin\theta=\dfrac{v'}{v}

Where, v'=speed of wind

v= speed of plane

Put the value into the formula

\sin\theta=\dfrac{75}{310}

\theta=\sin^{-1}(\dfrac{75}{310})

\theta=14.0^{\circ}

We need to calculate the resultant speed

Using formula of resultant speed

\cos\theta=\dfrac{v''}{v}

Put the value into the formula

\cos14=\dfrac{v''}{310}

v''=\cos14\times310

v''=300.79\ km/h

Hence, The speed of the plane relative to the ground is 300.79 km/h.

6 0
2 years ago
Two satellites revolve around the Earth. Satellite A has mass m and has an orbit of radius r. Satellite B has mass 6m and an orb
melomori [17]

Answer:

aaaaa

Explanation:

M = Mass of the Earth

m = Mass of satellite

r = Radius of satellite

G = Gravitational constant

F=G\frac{Mm}{r^2}

F=G\frac{M6m}{r_b^2}

G\frac{Mm}{r^2}=G\frac{M6m}{r_b^2}\\\Rightarrow \frac{1}{r^2}=\frac{6}{r_b^2}\\\Rightarrow \frac{r_b^2}{r^2}=6\\\Rightarrow \frac{r_b}{r}=\sqrt{6}\\\Rightarrow r_b=2.44948r

r_b=2.44948r

8 0
2 years ago
You would like to know whether silicon will float in mercury and you know that can determine this based on their densities. Unfo
dolphi86 [110]

Answer:

Explanation:

To convert gram / centimeter³ to kg / m³

gram / centimeter³

= 10⁻³ kg / centimeter³

= 10⁻³  / (10⁻²)³ kg / m³

= 10⁻³ / 10⁻⁶ kg / m³

= 10⁻³⁺⁶ kg / m³

= 10³ kg / m³

So we shall have to multiply be 10³ with amount in gm / cm³ to convert it into kg/m³

2.33 gram / cm³

= 2.33 x 10³ kg / m³ .

3 0
2 years ago
In pulling two identical carry-on bags through the airport, Mr. Myers and his 13 year old grandson, Vincent, do the same amount
Novay_Z [31]

Answer:

Mr Myers and his son use the same force to pull the bags between the gates

Explanation:

The work done by Mr. Myers in pulling the carryon bags = The work done by his 13 year old grandson in pulling the identical bag

Let F₁ represent the force used by Mr Myers, and let F₂ represent the force F₂ used by his grandson

Let d represent the distance through the gate

Therefore, given that Work done, W = Force, F × Distance, we have;

The work done by Mr Myers between the gates, W₁ = F₁ × d

The work done by his grandson between the gates, W₂ = F₂ × d

Where, the work done by both Mr Myers and his grandson are equal, we have;

W₁ = W₂ and therefore, F₁ × d = F₂ × d, which gives;

F₁ = F₂, the force used by both Mr Myers and his son between the gates are equal.

5 0
2 years ago
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