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Drupady [299]
2 years ago
14

Bonnie and clyde are sliding a 300 kg bank safe across the floor to their getaway car. the safe slides with a constant speed if

clyde pushes from behind with 445 n of force while bonnie pulls forward on a rope with 350 n of force. what is the safe's coefficient of kinetic friction on the bank floor?
Physics
1 answer:
alexdok [17]2 years ago
3 0
<span>We can draw a free body diagram for the safe to show all the horizontal forces acting on the safe. The three horizontal forces are Clyde's force, Bonnie's force, and friction. Since the safe slides at a constant speed (no acceleration), the net force must be zero. 0 = Clyde's force + Bonnie's force - friction friction = Clyde's force + Bonnie's force mg mu = Clyde's force + Bonnie's force mu = (Clyde's force + Bonnie's force) / (mg) mu = (445 N + 350 N) / (300 kg x 9.80~m/s^2) mu = 0.27 The coefficient of friction is 0.27</span>
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To move a suitcase up to the check-in stand at the airport a student pushes with a horizontal force through a distance of 0.95 m
hoa [83]

Answer:

33.68 N

Explanation:

Data

W= 32J

d- 0.95m

F= ?

W=Fd

They are asking for the magnitude which is the force, so you need to solve for force.

F=W/d

= 32J/ 0.95m

= 33.68 N

3 0
2 years ago
Gretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s.
KIM [24]

Answer:

The velocity is v = 4.76 \ m/s

Explanation:

From the question we are told that

   The first distance is   d_1  =  4.0 \ km  =  4000 \ m

   The  first speed  is  v_1 =  5.0 \ m/s

    The  second distance is  d_2  =  1.0 \ km  =  1000 \ m

    The  second speed  is  v_2  =  4.0 \ m/s

Generally the time taken for first distance is  

      t_1 =  \frac{d_1 }{v_1 }

        t_1 =  \frac{4000}{5}

       t_1 =  800 \ s

The time taken for second  distance is

           t_1 =  \frac{d_2 }{v_2 }

        t_1 =  \frac{1000}{4}

       t_1 =  250 \ s

The total time is mathematically represented as

     t =  t_1 + t_2

=>   t =  800 + 250

=>    t =  1050 \ s

Generally the constant velocity that would let her finish at the same time is mathematically represented as

      v =  \frac{d_1 + d_2}{t }

=>    v =  \frac{4000 + 1000}{1050 }

=>    v = 4.76 \ m/s

7 0
2 years ago
A radioactive substance decays exponentially. A scientist begins with 200 milligrams of a radioactive substance. After 17 hours,
lianna [129]

75.17 mg of the radioactive substance will remain after 24 hours.

Answer:

Explanation:

Any radioactive substance will obey the exponential decay behavior. So according to this behavior, any radioactive substance will be decaying in terms of exponential form of disintegration constant and Time.

Disintegration constant is the rate of decay of radioactive elements. It can be measured using the half life time of the radioactive element .While half life time is the time taken by any radioactive element to decay half of its concentration. Like in this case, at first the scientist took 200 mg then after 17 hours, it got reduced to 100 g. So the half life time of this element is 17 hours.

Then Disintegration constant = 0.6932/Half Life time

Disintegration constant = 0.6932/17=0.041

Then as per the law of disintegration constant:

N = N_{0}e^{-xt}

Here N is the amount of radioactive element remaining at time t and N_{0} is the initial amount of sample, x is the disintegration constant.

So here, N_{0} = 200 mg, x = 0.041 and t = 24 hrs.

N = 200 ×e^{-24*0.041} =75.17 mg.

So 75.17 mg of the radioactive substance will remain after 24 hours.

3 0
1 year ago
A uniform piece of wire, 20 cm long, is bent in a right angle in the center to give it an L-shape. How far from the bend is the
zlopas [31]

Answer:

the center of mass is 7.07 cm apart from the bend

Explanation:

the centre of mass of a wire of length L is L/2 ( assuming uniform density). Then initially the x coordinate of the centre of mass is

x₁ = L/2 = 20 cm /2 = 10 cm

when the wire is bent in a right angle the coordinates of the new centre of mass will be

x₂ = L₂/2

y₂=  L₂/2

where L₂ is the length of the horizontal piece and vertical piece . Then L₂=L/2

x₂ = L₂/2 = L/4 = 20 cm/4 = 5 cm

y₂= L₂/2 = L/4 = 20 cm/4 = 5 cm

x₂=y₂=X

locating the bend in the origin (0,0) the distance to the centre of mass is

d = √(x₂²+y₂²) = √(2X²) = √2*X=√2*5cm = 7.07 cm

d = 7.07 cm

5 0
2 years ago
Read 2 more answers
The speed of sound in seawater is 1470 m/s. A dolphin sends out a click that reflects off of an
Nitella [24]

Answer: 0.204 s

Explanation:

The speed of sound V is defined as the distance traveled d in a especific time t:  

V=\frac{d}{t}  

Where:  

V=1470 m/s is the speed of sound  in seawater

t is the time the sound wave travels from the dolphin and then returns after the reflection

d=2(150 m) is twice the distance between the dolphin and the object to which the sound waves are reflected

Finding t:

t=\frac{d}{V}  

t=\frac{2(150 m)}{1470 m/s}

<u>Finally:</u>

t=0.204 s

3 0
2 years ago
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