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kari74 [83]
2 years ago
10

The resistivity of a semiconductor can be modified by adding different amounts of impurities. A rod of semiconducting material o

f length L and cross-sectional area A lies along the x-axis between x=0 and x=L. The material obeys Ohm's law, and its resistivity varies along the rod according to ?(x)=?0exp(?x/L). The end of the rod at x=0 is at a potential V0 greater than the end at x=L.
Find the total resistance of the rod.

Express your answer in terms of the given quantities and appropriate constants.

R =
.632L?0A

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Correct

Part B

Find the current in the rod.

Express your answer in terms of the given quantities and appropriate constants.

I =
V0A?0L(1?e?1)

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Correct

Part C

Find the electric-field magnitude E(x) in the rod as a function of x.

Express your answer in terms of the given quantities and appropriate constants.

E(x) =
V0e?xLL(1?e?1)

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Correct

Part D

Find the electric potential V(x) in the rod as a function of x.

Express your answer in terms of the given quantities and appropriate constants.

V(x) =
V0e?xL?e?11?e?1

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Correct

Part E

Graph the function ?(x) for values of x between x=0 and x=L.

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Incorrect; Try Again; 2 attempts remaining

Part F

Graph the function E(x) for values of x between x=0 and x=L.

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Incorrect; Try Again; 4 attempts remaining

Part G

Graph the function V0(x) for values of x between x=0 and x=L.
Physics
1 answer:
zavuch27 [327]2 years ago
7 0

Answer:

pp

Explanation:

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An object’s velocity is measured to be vx(t) = α - βt2, where α = 4.00 m/s and β = 2.00 m/s3. At t = 0 the object is at x = 0. (
Leona [35]

Answer:

Explanation:

Given

v_x(t)=\alpha -\beta t^2

\alpha =4\ m/s

\beta =2\ m/s^3

v_x(t)=4-2t^2

v=\frac{\mathrm{d} x}{\mathrm{d} t}

\int dx=\int \left ( 4-2t^2\right )dt

x=4t-\frac{2}{3}t^3

acceleration of object

a=\frac{\mathrm{d} v}{\mathrm{d} t}

a=-4t

(b)For maximum positive displacement velocity must be zero at that instant

i.e.v=0

4-2t^2=0

t=\pm \sqrt{2}

substitute the value of t

x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}

x=3.77\ m

7 0
2 years ago
Give three factors that affected the kinetic energy of the person as she reached the bottom
soldier1979 [14.2K]

Answer:

As the person moves down the zip wire, her increase in kinetic energy is less than her decrease in gravitational potential energy.

Explanation:

Work is done against the air resistance, causing thermal energy to transfer to the surroundings

4 0
2 years ago
A 225 kg red bumper car is moving at 3.0 m/s. It hits a stationary 180 kg blue bumper car. The red and blue bumper cars combine
Alex Ar [27]

Given


m1(mass of red bumper): 225 Kg


m2 (mass of blue bumper): 180 Kg


m3(mass of green bumper):150 Kg


v1 (velocity of red bumper): 3.0 m/s


v2 (final velocity of the combined bumpers): ?




The law of conservation of momentum states that when two bodies collide with each other, the momentum of the two bodies before the collision is equal to the momentum after the collision. This can be mathemetaically represented as below:


Pa= Pb


Where Pa is the momentum before collision and Pb is the momentum after collision.


Now applying this law for the above problem we get


Momentum before collision= momentum after collision.


Momentum before collision = (m1+m2) x v1 =(225+180)x 3 = 1215 Kgm/s


Momentum after collision = (m1+m2+m3) x v2 =(225+180+150)x v2

=555v2

Now we know that Momentum before collision= momentum after collision.


Hence we get


1215 = 555 v2


v2 = 2.188 m/s


Hence the velocity of the combined bumper cars is 2.188 m/s

4 0
2 years ago
Read 2 more answers
Aaron Agin nodded off while driving home from play practice this past Sunday evening. His 1500-kg car hit a series of guardrails
Inessa [10]

Answer: 6.48m/s

Explanation:

First, we know that Impulse = change in momentum

Initial velocity, u = 19.8m/s

Let,

Velocity after first collision = x m/s

Velocity after second collision = y m/s

Also, we know that

Impulse = m(v - u). But then, the question said, the guard rail delivered a "resistive" impulse. Thus, our impulse would be m(u - v).

5700 = 1500(19.8 - x)

5700 = 29700 - 1500x

1500x = 29700 - 5700

1500x = 24000

x = 24000/1500

x = 16m/s

Also, at the second guard rail. impulse = ft, so that

Impulse = 79000 * 0.12

Impulse = 9480

This makes us have

Impulse = m(x - y)

9480 = 1500(16 -y)

9480 = 24000 - 1500y

1500y = 24000 - 9480

1500y = 14520

y = 14520 / 1500

y = 9.68

Then, the velocity decreases by 3.2, so that the final velocity of the car is

9.68 - 3.2 = 6.48m/s

5 0
2 years ago
Which term do modern psychologists prefer to use in place of short-term memory?
Vsevolod [243]

Correct answer: D). Working Memory

The short term memory is the part of the memory system in which the information is stored for 30 seconds. However, it can be increased by rehearsal. Short term memory is also called active memory or the working memory. The working memory is the part of the cognitive system that is responsible for storing information temporarily for processing. It is important for reasoning.

Hence, the correct answer would be option D.




7 0
2 years ago
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