Answer:
torque is 1.7 *
Nm
Explanation:
Given data
turns n = 1000 turns
radius r = 12 cm
current I = 15A
magnitude B = 5.8 x 10^-5 T
angle θ = 25°
to find out
the torque on the loop
solution
we know that torque on the loop is
torque = N* I* A*B* sinθ
here area A = πr² = π(0.12)²
put all value
torque = N* I* A*B* sinθ
torque = 1000* 15* π(0.12)² *5.8 x 10-5 * sin25
torque = 0.0166 N m
torque is 1.7 *
Nm
Answer:
The cross-sectional area of the larger piston is 392cm ^{2}[/tex]
Explanation:
To solve this problem we apply the following formula:
Pascal principle: F=P*A Formula (1)
F=Force applied to the piston
P: Pressure
A= Piston area
Nomenclature:
Fp= Force on the primary piston= 500N
W= car weight =m*g=2000kg*9.8m/s2= 19600N
Fs= Force on the secondary piston= W = 19600N

As= Secondary piston area=?
The pressure acting on one side is transmitted to all the molecules of the liquid because the liquid is incompressible.
In the equation (1)
P=F/A
Pp=Ps





Answer:
0.106
Explanation:
For 1 liter of diesel the car can get 19 km, if it takes 0.2 MJ for each km then it would take the total energy of 19*0.2 = 3.8 MJ to move an aerodynamic car 19 km. Since 1 liter of of diesel also contains 36 MJ in internal energy, then the efficiency of the diesel engine is the ratio of its output energy over its input energy:

Answer:
1) 50 seconds 2) 100°C
Explanation:
(Follows formula of Power=Energy/Time)
1) 500W x X = 2000J/kg°C x .25kg x 50°C
X = 50 seconds.
2) 2000W x 300s = 1000J/kg°C x 2kg x X
X = 300
Initial temperature => 400°C-300°C = 100°C