A truck is using a hook to tow a car whose mass is one quarter that of the truck. If the force exerted by the truck on the car i
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Answer:
D) The worker will accelerate at 2.17 m/s² and the box will accelerate at 1.08 m/s² , but in opposite directions.
Explanation:
Newton's third law
Newton's third law or principle of action and reaction states that when two interaction bodies appear equal forces and opposite directions. in each of them.
F₁₂= -F₂₁
F₁₂: Force of the box on the worker
F₂₁: Force of the worker on the box
Newton's second law
∑F = m*a
∑F : algebraic sum of the forces in Newton (N)
m : mass in kilograms (kg)
a : acceleration in meters over second square (m/s²)
Formula to calculate the mass (m)
m = W/g
Where:
W : Weight (N)
g : acceleration due to gravity (m/s²)
Data
W₁ =1.8 kN : box weight
W₂ = 0.900 kN : worker weight
F₂₁ = 0.200 kN
F₁₂ = - 0.200 kN
g = 9.8 m/s²
Newton's second law for the box
∑F = m*a
F₂₁ = m₁*a₁ m₁=W₁/g
0.2 kN = (1.8kN)/(9.8 m/s² ) *a₁
a₁= 1.08 m/s² : acceleration of the box
Newton's second law for the worker
∑F = m*a
F₁₂ = m₂*a₂ , m₂=W₂/g
- 0.2 kN =( (0.9 kN) /(9.8 m/s² ) )*a₂
a₂= -2.17 m/s² : acceleration of the worker
Answer:
<em>1) 1.56 m/s</em>
<em>2) 1.11 m/s</em>
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Explanation:
The bus travels 6 blocks east and 8 blocks west
Each block is 100 m long
time taken to travel through this distance = 15 min
average speed of the bus = ?
the total blocks traveled = 6 + 8 = 14 blocks
total distance traveled = 14 x 100 m = 1400 m
time taken = 15 min = 15 x 60 sec = 900 sec
average speed of the bus = distance traveled/time taken
==> 1400/900 = <em>1.56 m/s</em>
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2) velocity = displacement/time taken
displacement is the shortest distance between the starting position and the final position of the bus.
The displacement of this bus will be the hypotenuse of the triangle formed by the motion of the bus
the distance traveled east = 6 x 100 = 600 m
the distance traveled north = 8 x 100 = 800 m
displacement = = 1000 m
The velocity of the bus = 1000/900 = <em>1.11 m/s</em>