Answer:
The speed of bullet and wooden bock coupled together, V = 22.22 m/s
Explanation:
Given that,
Mass of the bullet, m = 0.04 Kg
Mass of the wooden block, M = 0.5 Kg
The initial velocity of the bullet, u = 300 m/s
The initial velocity of the wooden block, U = 0 m/s
The final velocity of the bullet and wooden bock coupled together, V = 0 m/s
According to the conservation of linear momentum, the total momentum of the body after impact is equal to the total momentum before impact.
Therefore,
mV + MV = mu + MU
V(m+M) = mu
V = mu/(m+M)
Substituting the values in the above equation,
V = 0.04 Kg x 300 m/s / (0.04 Kg+ 0.5 Kg)
= 22.22 m/s
Hence, the speed of bullet and wooden bock coupled together, V = 22.22 m/s
