The brake pads for a bicycle tire are made of rubber. If a frictional force of 50 N is applied to each side of the tires, determ
1 answer:
Answer:
average shear strain in the rubber is 0.25rad
Explanation:
The base has a dimension of 20mm and 50mm.
frictional force is 50 N
using the expressed shear stress,
we will determine τ =
τ = 50 / 1000
= 0.05MPa
shear stress τ = γ .G
τ = shear stress
γ = shear strain
G = 0.20MPa
γ = τ / G
= 0.05 / 0.20
= 0.25rad
average shear strain in the rubber is 0.25rad
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