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kow [346]
2 years ago
13

The same fluid flows through four different branching pipes. It enters each pipe from the left with the same speed, v0, and flow

s to the right. Assume that the fluid fills the pipes everywhere completely. You can also assume that all of these pipes are in the horizontal plane and that you are looking at them from above, so that there are no differences in height anywhere among the pipe branches. Finally, you can ignore viscosity. Which fluid speed is the largest?
All four speeds are the same.
a. v1
b. v4
c. v2
d. v3
Physics
1 answer:
Anvisha [2.4K]2 years ago
6 0

Answer:

The correct option is A.

Explanation:

Following the equation of continuum, AV remains constant.

Case a

(3A)(V0) = AV1 + AV1 + AV1

3AV0 = 3AV1

V1 = V0

Case b

(A)(V0) = (A/3)V2 + (A/3)V2 + (A/3)V2 + (A/3)V2​​​​​​​

AV0 = 4V2/3

V2 = 3/4V0

Case c

(A/2)(V0) = AV3 + AV3 + AV3

AV0/2 = 3AV3

V3 = V0/6

Case d

(3A)(V0) = 2AV4 + 2AV4

3AV0 = 4AV4

V4 = 3V0/4

Comparing all the flow speeds, V1 is the largest.

Thus, the correct option is A.

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An astronaut stands on the surface of an asteroid. The astronaut then jumps such that the astronaut is no longer in contact with
Anna71 [15]

(D) The gravitational force between the astronaut and the asteroid.

Reason :

All the other forces given in the options, except (D), doesn't account for the motion of the astronaut. They are the forces that act between nucleons or atoms and neither of them accounts for an objects motion.

6 0
2 years ago
A 3-cm high object is in front of a thin lens. The object distance is 4 cm and the image distance is –8 cm. (a) What is the foca
xenn [34]

Answer:

a) Focal length of the lens is 8 cm which is a convex lens

b) 6 cm

c) The lens is a convex lens and produces a virtual image which is upright and two times larger than the object.

Explanation:

u = Object distance =  4 cm

v = Image distance = -8 cm

f = Focal length

Lens Equation

\frac{1}{f}=\frac{1}{u}+\frac{1}{v}\\\Rightarrow \frac{1}{f}=\frac{1}{4}+\frac{1}{-8}\\\Rightarrow \frac{1}{f}=\frac{1}{8}\\\Rightarrow f=\frac{8}{1}=-8\ cm

a) Focal length of the lens is 8 cm which is a convex lens

Magnification

m=-\frac{v}{u}\\\Rightarrow m=-\frac{-8}{4}\\\Rightarrow m=2

b) Height of image is 2×3 = 6 cm

Since magnification is positive the image upright

c) The lens is a convex lens and produces a virtual image which is upright and two times larger than the object.

8 0
2 years ago
A girl is shown at position A on a swing when the seat is directly below the support bar. The seat is then at height A as shown
MrRa [10]

Answer:

<u></u>

  • <u>1. The potential energy of the swing is the greatest at the position B.</u>

  • <u>2. As the swing moves from point B to point A, the kinetic energy is increasing.</u>

Explanation:

Even though the syntax of the text is not completely clear, likely because it accompanies a drawing that is not included, it results clear that the posittion A is where the seat is at the lowest position, and the position B is upper.

The gravitational <em>potential energy </em>is directly proportional to the height of the objects with respect to some reference altitude. Thus, when the seat is at the position A the swing has the smallest potential energy and when the seat is at the <em>position B the swing has the greatest potential energy.</em>

Regarding the forms of energy, as the swing moves from point B to point A, it is going downward, gaining kinetic energy (speed) at the expense of the potential energy (losing altitude). When the seat passes by the position A, the kinetic energy is maximum and the potential energy is miminum. Then the seat starts to gain altitude again, losing the kinetic energy and gaining potential energy, up to it gets to the other end,

7 0
2 years ago
Read 2 more answers
A 2650-lb car is traveling at sea level at a constant speed. its engine is running at 4500 rev/min and is producing 175 ft-lb of
Zepler [3.9K]
Check the attached file for the answer.

6 0
2 years ago
Read 2 more answers
The standing vertical jump is a good test of an athlete's strength and fitness. The athlete goes into a deep crouch, then extend
SashulF [63]

Answer:

<em>The athlete will rise 1.10 meters off the ground</em>

Explanation:

<u>Vertical Motion</u>

If an object is launched vertically upwards at an initial speed vo, then it will reach a maximum height given by

\displaystyle y_m=\frac{v_o^2}{2g}

The athlete can exert a net force upwards equal to twice his weight. It makes him accelerate upwards at

\displaystyle a=\frac{F_n}{m}=\frac{2W}{m}=2g

The speed at the end of his push can be computed by

v^2=2ay

Replacing the value of a obtained above:

v^2=4gy

where y is the length of this crouch

v^2=4\cdot 9.8\cdot 0.55

v=4.64\ m/s

This is the initial speed of this vertical launch, thus

\displaystyle y_m=\frac{4.64^2}{2\cdot 9.8}

y_m=1.10\ m

5 0
2 years ago
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