A series circuit contains an 80-μF capacitor, a 0.020-H inductor, and a switch. The resistance of the circuit is negligible. Ini
tially, the switch is open, the capacitor voltage is 50 V, and the current in the inductor is zero. At time t = 0 s, the switch is closed. A) The time t at which the magnetic energy of the inductor first reaches its maximum value is?
B) The maximum current in the circuit is?
C) When the current is 1.5 A, the charge on the capacitor, in µC, is?
D) When the capacitor voltage is 30 V, the rate of change of the current is?
E) At a given instant, the magnetic energy of the inductor is twice the electrostatic energy of the capacitor. At that instant, the current is?
B) The maximum current in the circuit is?
C) When the current is 1.5 A, the charge on the capacitor, in µC, is?
D) When the capacitor voltage is 30 V, the rate of change of the current is?
E) At a given instant, the magnetic energy of the inductor is twice the electrostatic energy of the capacitor. At that instant, the current is?
1 answer:
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Answer:
-13.18°C
Explanation:
To develop the problem it is necessary to consider the concepts related to the thermal conduction rate.
Its definition is given by the function
Where,
Q = The amount of heat transferred
t = time
k = Thermal conductivity constant
A = Cross-sectional area
The difference in temperature between one side of the material and the other
d= thickness of the material
The problem says that there is a loss of heat twice that of the initial state, that is
Replacing,
Solvinf for ,
Therefore the temprature at the outside windows furface when the heat lost per second doubles is -13.18°C
Answer:
(1) En to n-1 = 0.55 ev
(2) En-1 to n-2 = 0.389 ev
(3) ninitial =4
(4) L =483.676 ×10^-11 nm
(5) λlongest= 1773.33 nm
Explanation:
Detailed explanation of answer is given in the attached files.
Answer:
31.67 in
Explanation:
Given:
Diameter of the pipe, D = 3ft = 36 in
cross-sectional area of the steel = 0.2 in²
Note: Refer to the figure attached
From the free body diagram represented in the figure, we have
ΣFx = 0
or
pressure × projected area = 2 × Force in steel
Now, the projected area = spacing (s) × diameter of the wood pipe
force in steel = stress in steel (σ) × cross-sectional area of the steel
on substituting the values we get
4 ksi × (s × 36 in) = 2 × σ × 0.2 in²
also, allowable hoop stress = 11.4 ksi
thus,
σ = 11.4 ksi = 11.4 × 10³ psi
therefore, we have
4 psi × (s × 36 in) = 2 × 11.4 × 10³ psi × 0.2 in²
thus,
s = 31.67 in
hence the maximum spacing is 31.67 in
