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iragen [17]
2 years ago
6

A fish is 80 cm below the surface of a pond. What is the apparent depth (in cm) when viewed from a position almost directly abov

e the fish
Physics
1 answer:
Rudik [331]2 years ago
5 0

Answer:

Apparent depth (Da) = 60.15 cm (Approx)

Explanation:

Given:

Distance from fish (D) = 80 cm

Find:

Apparent depth (Da)

Computation:

We know that,

Refractive index of water (n2) = 1.33

So,

Apparent depth (Da) = D(n1/n2)

Apparent depth (Da) = 80 (1/1.33)

Apparent depth (Da) = 60.15 cm (Approx)

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Ram has power of 550 watt. What does it mean?
WARRIOR [948]
It means you can do 550 Newton Meters of work every second. Power is the rate of doing work, I hope this helps
4 0
2 years ago
Conductance is directly proportional to the length of a conductor. true false user: resistance is inversely proportional to the
zlopas [31]
1) false

2) area of the conductor
7 0
2 years ago
Read 2 more answers
Jenny puts a book on her desk. she lifts the book up with her finger, using a force of 0.5N .The cover is 10cm wide .
zepelin [54]

The turning moment on the cover of the book is 0.05 Nm.

Explanation:

Given:

Force applied (F) = 0.5 N

Distance covered (d) = 10 cm

Converting Distance covered from cm to meter we get (d)= 0.1 m

To find:

Turning Moment (M) on the cover of the book = ?

Formula to be used:                                    

Turning Moment (M) = F × d

                                  = 0.5 × 0.1

                                   = 0.05 Nm

Thus the turning moment on the cover of the book is found to be 0.05 Nm

6 0
2 years ago
In the context of energy transfers with hot and cold reservoirs, the sign convention is that _______________.
Likurg_2 [28]

Answer:

B. QC > 0; QH < 0

Explanation:

Given that there are two reservoir of energy.

Sign convention for heat and work :

1.If the heat is adding to the system then it is taken as positive and if heat is going out from the system then it is taken as negative.

2. If the work is done on the system then it is taken as negative and if the work is done by the system then it is taken as positive.

From hot reservoir heat is going out that is why it is taken as negative

Q_H

From cold reservoir heat is coming inside the reservoir that is why it is taken as positive

Q_C>0

That is why the answer will be

Q_H ,Q_C>0

8 0
2 years ago
When a 75.0-kg man slowly adds his weight to a vertical spring attached to the ceiling, he reaches equilibrium when the spring i
Sergio039 [100]

Answer:

1)k=11.319kN/m

2)displacement=13.02cm

3)k_{eq}=5.65kN/m

Explanation:

At equilibrium position the weight of the man should be balanced by force in the spring

thus we have at equilibrium

kx=mg\\\\k=\frac{mg}{x}

Applying values we get

k=\frac{75\times 9.81}{0.065}\\\\k=11.319kN/m

2)

When we add another identical spring we get an equivalent spring with spring constant as  

\frac{1}{k_{eq}}=\frac{1}{k_1}+\frac{1}{k_2}

Applying values we get

\frac{1}{k_{eq}}=\frac{1}{11.319}+\frac{1}{11.319}\\\\k_{eq}=5.65kN/m

Thus at equilibrium we have

x_{2}k_{eq}=mg\\\\x_{2}=\frac{mg}{k_{eq}}\\\\x_{2}=\frac{75\times 9.81}{5.65}\times 10^{-3}=13.02cm

3) Equivalent spring constant will be as calculated earlier k_{eq}=5.65kN/m

3 0
2 years ago
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