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Effectus [21]
2 years ago
8

An object’s velocity is measured to be vx(t) = α - βt2, where α = 4.00 m/s and β = 2.00 m/s3. At t = 0 the object is at x = 0. (

a) Calculate the object’s position and acceleration as functions of time. (b) What is the object’s maximum positive displacement from the origin?
Physics
1 answer:
Leona [35]2 years ago
7 0

Answer:

Explanation:

Given

v_x(t)=\alpha -\beta t^2

\alpha =4\ m/s

\beta =2\ m/s^3

v_x(t)=4-2t^2

v=\frac{\mathrm{d} x}{\mathrm{d} t}

\int dx=\int \left ( 4-2t^2\right )dt

x=4t-\frac{2}{3}t^3

acceleration of object

a=\frac{\mathrm{d} v}{\mathrm{d} t}

a=-4t

(b)For maximum positive displacement velocity must be zero at that instant

i.e.v=0

4-2t^2=0

t=\pm \sqrt{2}

substitute the value of t

x=4\times \sqrt{2}-\frac{2}{3}\times 2\sqrt{2}

x=3.77\ m

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Answer:

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Answer:

temperature on left side is 1.48 times the temperature on right

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let final pressure is P and temp  T_1 {f} and T_2 {f}

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P_1^{-2/3} T_1^{5/3} = P^{-2/3} T_1 {f}^{5/3} ..................2

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P_2^{-2/3} T_2^{5/3} = P^{-2/3} T_2 {f}^{5/3} .............3

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You stand on a bathroom scale in a moving elevator. what happens to the scale reading if the cable holding the elevator suddenly
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A bathroom scales works due to gravity. Under normal conditions, a reading can be obtained when your body is pushing some force on the scale. However in this case, since you and the scale are both moving downwards, so your body is no longer pushing on the scale. Therefore the answer is:

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flat block is pulled along a horizontal flat surface by a horizontal rope perpendicular to one of the sides. The block measures
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Answer:

Answered

Explanation:

v= 1 m/s

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now in x- direction F_s= F_f

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