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makvit [3.9K]
2 years ago
7

The furnace keeps houseAat 25◦C, while thefurnace in houseBkeeps it at 20◦C. Which house requires heat to be supplied by its fur

nace at a faster rate?
1.House B requires heat at a slightly faster rate than A.
2.House A requires heat at about twice the rate of B.
3.House A requires heat at about four times the rate of B.
4.Houses A and B require heat at the same rate.
5.House A requires heat at a slightly faster rate than B.
6.House B requires heat at about twice the rate of A.
7.House B requires heat at about four times the rate of A.
8.None of the above answers is correct.
Physics
1 answer:
EleoNora [17]2 years ago
5 0

Answer:

House A requires heat at a slightest faster rate than B

Explanation:

House A requires heat at a slightest faster rate than B due to the slight high temperature the furnace A is.

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A forklift does 450 J of work to lift a 150 N hot tub. How high is the hot tub lifted? Round your answer to the nearest whole nu
vivado [14]
There are already 2 givens, hence we can do direct substitution to get the answer. To make the process simpler, derive the distance formula from the Work formula.

Work = Force x Distance

Distance = \frac{Work}{Force}


Work is 450J while the force is 150N hot tub

To get the proper units, get the equivalent of Joule to eliminate newton. A joule Is equal to 1 N-m

Distance = \frac{450N-m}{150N}
Distance = 3m

Hence, the hot tub is lifted 3 meters.
5 0
2 years ago
Read 2 more answers
Magnus has reached the finals of a strength competition. In the first round, he has to pull a city bus as far as he can. One end
iragen [17]

Answer:

The workdone is  W_d =-4400J

Explanation:

The free body diagram is shown on the first uploaded image

From the question we are given that

            The force is on the force gauge  F = 2750 N

             The distance that Magnus pulled the bus  d = 1.60m

Generally  the workdone by the tension force on Magnus is

                  Workdone = Force * displacement \ in \ the \ direction \ of \ force

                     W_d = F * (-d)

This negative sign show that is tension force  is in the opposite direction to Magnus movement (i.e the movement of the bus )

Substituting value we have

                   Workdone  =  - 2750 * 1.60

                                     =-4400 J

7 0
2 years ago
When a car is 100 meters from its starting position traveling at 60.0 m/s., it starts braking and comes to a stop 350 meters fro
NISA [10]
Remember your kinematic equations for constant acceleration. One of the equations is x_{f} =  x_{i} +  v_{i}(t) + \frac{1}{2} at^{2}, where x_{f} = final position, x_{i} = initial position, v_{i} = initial velocity, t = time, and a = acceleration. 

Your initial position is where you initially were before you braked. That means x_{i} = 100m. You final position is where you ended up after t seconds passed, so x_{f} = 350m. The time it took you to go from 100m to 350m was t = 8.3s. You initial velocity at the initial position before you braked was v_{i} = 60.0 m/s. Knowing these values, plug them into the equation and solve for a, your acceleration:
350\:m = 100\:m + (60.0\:m/s)(8.3\:s) + \frac{1}{2} a(8.3\:s)^{2}\\
250\:m = (60.0\:m/s)(8.3\:s) + \frac{1}{2} a(8.3\:s)^{2}\\
250\:m = 498\:m +34.445\:s^{2}(a)\\
-248\:m = 34.445\:s^{2}(a)\\
a \approx -7.2 \: m/s^{2}

Your acceleration is approximately -7.2 \: m/s^{2}.
4 0
2 years ago
The curved section of a horizontal highway is a circular unbanked arc of radius 740m. If the coefficient of static friction betw
fiasKO [112]
Coefficient of static friction = tan(a) = 0.4
r = 740 m
g = 9.8 m/s²
v \:  =  \:  \sqrt{gr \tan( \alpha ) }
v = √(9.8 × 740 × 0.4) m/s
v ≈ 53.85908 m/s
6 0
2 years ago
Read 2 more answers
The A-string (440 HzHz) on a piano is 38.9 cmcm long and is clamped tightly at both ends. If the string tension is 667N, what's
Mice21 [21]

Answer:

Mass, m = 2.2 kg                                

Explanation:

It is given that,

Frequency of the piano, f = 440 Hz

Length of the piano, L = 38.9 cm = 0.389 m

Tension in the spring, T = 667 N

The frequency in the spring is given by :

f=\dfrac{1}{2L}\sqrt{\dfrac{T}{\mu}}

\mu=\dfrac{m}{L} is the linear mass density

On rearranging, we get the value of m as follows :

m=\dfrac{T}{4Lf^2}

m=\dfrac{667}{4\times 0.389\times (440)^2}

m = 0.0022 kg

or

m = 2.2 grams

So, the mass of the object is 2.2 grams. Hence, this is the required solution.

3 0
2 years ago
Read 2 more answers
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