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Fittoniya [83]
2 years ago
10

A heat engine (Power Cycle) with a thermal efficiency of 35 percent efficiency produces 750 kJ of work. Heat transfer to the eng

ine is from a reservoir at 550K, and the heat transfer from the engine is released to the surrounding air at 300K. a. Draw a schematic illustrating the heat engine and show the engineering model. (5 points) b. Determine the heat transfer to the engine and the heat transfer from the engine to the air (Actual engine). (10 points) c. If the same heat engine is replaced by a Carnot heat engine that produces the same work output, find the thermal efficiency, the heat-transfer to the heat engine, and the heat transfer from the engine to the low temperature reservoir. (10 points)

Physics
1 answer:
frosja888 [35]2 years ago
4 0

Answer:

a) The schematic illustrating is attached

b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ

c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ

Explanation:

b) The heat transfer to the engine and the heat transfer from the engine to the air is:

Q_{1} =\frac{W}{n}

Where

W = 750 kJ

n = 35% = 0.25

Replacing:

Q_{1} =\frac{750}{0.35} =2142.86kJ

Q_{2} =Q_{1} -W=2142.86-750=1392.86kJ

c) The efficiency of Carnot engine is:

n=1-\frac{300K}{550K} =0.455

The heat transfer to the heat engine is:

Q_{1c} =\frac{750}{0.455} =1648.35kJ

The heat transfer from the heat engine is:

Q_{2c} =1648.35-750=898.35kJ

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Answer:

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Given:

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Hence.                        m = 0.00085*0.0025 / 2.8*(600*10^-9)

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- We know that constructive interference would occurred at m = 1 and destructive interference @ m = 1.5. They have a phase difference of pi/2 radians.

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Answer:                  Phase difference = pi/4 radians

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Two small diameter, 10gm dielectric balls can slide freely on a vertical channel each carry a negative charge of 1microcoulomb.
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Answer:

The distance of separation is d = 0.092 \ m

Explanation:

The mass of the each ball is  m= 10 g  =  0.01 \ kg

 The negative charge on each ball is q_1 =q_2=q =  1 \mu C  =  1 *10^{-6} \ C

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Hence the gravitational force acting on the lower ball is equivalent to the electrostatic force i.e

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Answer:

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3 0
2 years ago
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