All categories

2 years ago

A race car exerts 19,454 n while the car travels at a constant speed of 201 mph, 91.36 m/s.what is the mass of the car?

Physics

2 answers:

AleksAgata [21]2 years ago

7 0

Answer:

The mass of the car is 1985.10 kg.

Explanation:

It is given that,

Force exerted by the race car, F = 19,454 N

The constant speed of the car, v = 201 mph

We need to find the mass of the car. Let it is given by m. It can be calculated using Newton's second law of motion. It is given by :

$m=\dfrac{F}{a}$

The car is exerting this force under the action of gravity. Here, a = g

$m=\dfrac{F}{g}$

$m=\dfrac{19454\ N}{9.8\ m/s^2}$

m = 1985.10 kg

So, the mass of the car is 1985.10 kg. Hence, this is the required solution.

Kisachek [45]2 years ago

4 0

A race car exerts 19,454 n while the car travels at a constant speed of 201 mph, 91.36 m/s. the mass of the car can be solve by using the formula F= mg, where g is the acceleration due to gravity

M = 19, 454 N/ 9.81 m/s2

M = 1,983.08 kg

You might be interested in

Sara and Saba are identical twins who are the same in every way, including their weights. One day, Sara and Saba decided to go f

Sphinxa [80]

As Saba was wearing high heels they are long from the bottom so they sank however Sana was wearing snow boots which means they were flat and so she didn’t sink.

3 0

2 years ago

A 2 000-kg sailboat experiences an eastward force of 3 000 N by the ocean tide and a wind force against its sails with a magnitu

Vesnalui [34]

Answer:

The magnitude of the resultant acceleration is 2.2 $m/s^2$

Explanation:

Mass (m) of the sailboat = 2000 kg

Force acting on the sailboat due to ocean tide is $F_1$ = 3000N

Eastwards means takes place along the positive x direction

Then $F_{1x}$ = 3000N and $F_{1y}$ = 0

Wind Force acting on the Sailboat is $F_2$ = 6000N directed towards the northwest that means at an angle 45 degree above the negative x axis

Then

$F_{2x}$ = -(6000N) cos 45 degree = -4242.6 N

$F_{2y}$ = (6000N) cos 45 degree = 4242.6 N

Hence , the net force acting on the sailboat in x direction is

$F_x = F_{1x}+ F_{2x}$

= - 3000 N + 4242.6 N

= - 3000 N +4242.6 N

= 1242.6N

Net Force acting on the sailboat in y direction is

$F_y = F_{1y}+ F_{2y}$

= 0+ 4242.6N

= 4242.6N

The magnitude of the resultant force =

Using pythagorean theorm of 1243 N and 4243 N

$\sqrt{(1242.6)^2 + (4242.6)^2$

$\sqrt{(1544054.76) + (17999654.8)}$

$\sqrt{(19543709.5)^2}$

4420.8 N

F = ma

$a = \frac{F}{m}$

$a =\frac{4420.8}{ 2000}$

=2.2 $m/s^2$

4 0

2 years ago

Li is riding her bicycle at 8.0 m/s. She slows down to 4.0 m/s. Her change in velocity is m/s. If Li takes 2 seconds to make thi

forsale [732]

You will have to use this formula:
$v = vo + a \times t$

Final Velocity (V) = 4m/s
Initial Velocity (Vo) = 8m/s
Acceleration (a) = ? m/s^2
Time (t) = 2 secs

Then:

-> 4 = 8 + a x 2
-> 4 - 8 = 2a
-> -4 = 2a
-> a = -4/2
-> a = -2 m/s^2

Ps: It's value is negative because the she was in retrograde motion.

Answer: Her acceleration is -2 m/s^2.

4 0

2 years ago

Read 2 more answers

A child of mass 27 kg swings at the end of an elastic cord. At the bottom of the swing, the child's velocity is horizontal, and

snow_tiger [21]

Answer:

The magnitude of the rate of change of the child's momentum is 794.11 N.

Explanation:

Given that,

Mass of child = 27 kg

Speed of child in horizontal = 10 m/s

Length = 3.40 m