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hichkok12 [17]
2 years ago
13

The energy stored in a wooden log transforms when the log is burned. Which of the following explanations BEST describes how the

chemical energy stored in the log compares to the heat and light energy produced by burning?
A. chemical energy is the same and additional energy is produced as heat and light.

B. chemical energy is more than the amount of heat and light

C. the amount of chemical energy is less than the amount of heat and light energy

D. the amount of chemical energy equals the amount of heat and light energy.
Physics
1 answer:
Makovka662 [10]2 years ago
5 0

Answer:

D. the amount of chemical energy equals the amount of heat and light energy.

Explanation:

Given that the first law of thermodynamics affirmed that energy is neither created nor destroyed however, it can be transformed from one form to another. In other words, while, during the transformation of energy, no energy is lost, the input energy is also equal to output energy.

Hence, the chemical energy stored in the log is EQUAL to the heat and light energy produced by burning.

You might be interested in
From the edge of a roof you throw a snowball downward that strikes the ground with 100J of kinetic energy. then you throw a seco
Vanyuwa [196]

Answer:

The second snowball hits the ground with a kinetic energy of 100 Joules

Explanation:

Given that,

From the edge of a roof you throw a snowball downward that strikes the ground with 100 J of kinetic energy. It is a case of conservation of energy.

At the highest point,

mgh+\dfrac{1}{2}mu^2=mgh'+0          

100=mgh'

At lowest point,

mgh'=K

From above two equation, we get :

Kinetic energy, K = 100 J

So, the second snowball hits the ground with a kinetic energy of 100 Joules. So, the correct option is (A).                                                                        

7 0
2 years ago
Neha and Suhani are playing with two identical pendulums. They leave the bob from a certain position and wait for it to return t
Anika [276]

Answer:

The correct option is C

Explanation:

The pendulum bob would return at the same time because the initial angle a pendulum bob is dropped does not affect it's period (the time it takes for the pendulum to move back and forth), however the one with a larger angle move faster but would eventually arrive at the same "starting point" due to varying displacements made.

6 0
2 years ago
A 5.00-pF, parallel-plate, air-filled capacitor with circular plates is to be used in a circuit in which it will be subjected to
Ne4ueva [31]

Answer:

a) r=4.24cm d=1 cm

b) Q=5x10^{-10} C

Explanation:

The capacitance depends only of the geometry of the capacitor so to design in this case knowing the Voltage and the electric field

V=1.00x10^{2}v\\E=1.00x10^{4} \frac{N}{C}

V=E*d\\d=\frac{V}{E}\\d=\frac{1.0x10^{2}}{1.0x10^{4}}\\d=0.01m

The distance must be the separation the r distance can be find also using

C=\frac{Q}{V_{ab}}

But now don't know the charge these plates can hold yet so

a).

d=0.01m

C=E_{o}*\frac{A}{d}\\A=\frac{C*d}{E_{o}}

A=\frac{5pF*0.01m}{8.85x10^{-12}\frac{F}{m}}\\A=5.69x10^{-3}m^{2}

A=\pi *r^{2}\\r=\sqrt{\frac{A}{r}}\\r=\sqrt{\frac{5.64x10^{-3}m^{2} }{\pi } }  \\r=42.55x^{-3}m

b).

C=\frac{Q}{V_{ab}}

Q=C*V\\Q=5x10^{-12} F*1x10^{2}\\Q=5x10^{-10}C

8 0
2 years ago
A factory robot drops a 10 kg computer onto a conveyor belt running at 3.1 m/s. The materials are such that μs = 0.50 and μk = 0
frutty [35]

Answer:

x = 1.63 m

Explanation:

mass (m) = 10 kg

μk = 0.3

velocity (v) = 3.1 m/s

Assuming that most of the computers weight is applied on the belt instantaneously, we can apply the constant acceleration equation below

x = v^{2}/2a

where a = μk.g , therefore

x = v^{2}/2μk.g

x = (3.1 x 3.1)/(2 x 0.3 x 9.8)

x = 1.63 m

8 0
2 years ago
Part A
Kruka [31]

Answer:

Part A

You have to ride 8.0 km before turning north to get to your friend’s house.

Part B

The sine of the angle  θ at the location of the friend's house is 0.8

Explanation:

The remaining part of the question which is an image is attached below

Explanation:

Part A

To determine how far you will ride ride before turning north,

From the diagram, that is the distance of your street.

Let the distance of your street be A

and the distance of your friend's street be B

and let the displacement between your friends house and your house be C

The relation in the diagram shows a right angle triangle.

The sides of the right angle triangle are represented as A,B and C.

To find A, which is the distance of your street,

From Pythagorean theorem, 'The square of hypotenuse is the sum of squares of the other two sides'

That is,

/Hypoyenuse/^{2} = /Adjacent/^{2} + /Opposite/^{2}

C is the hypotenuse, which is the displacement between your friends house and your house,

Hence, C = 10.0 km

B is adjacent, which is the distance of your friends street

then, B = 6.0 km

and A is the opposite, which is the distance of your house

From Pythagoras theorem, we can then write that,

C^{2} = B^{2} + A^{2}

Then, 10.0^{2} = 6.0^{2} + A^{2}

A^{2} = 100.0 - 36.0\\A^{2} = 64.0\\A = \sqrt{64.0}

A = 8.0km

Hence, you have to ride 8.0 km before turning north to get to your friend’s house.

Part B

To find the sine of the angle  θ at the location of the friend's house,

In the diagram, the sine of the angle  θ is given by

Sin\theta = \frac{Opposite}{Hypotenuse}

Hence, Sin\theta = \frac{A}{C}

Then,

Sin\theta = \frac{8.0}{10}

Sin\theta = 0.8

Hence, the sine of the angle  θ at the location of the friend's house is 0.8

4 0
2 years ago
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