Question

Given the indices of refraction n1 and n2 of material 1 and material 2, respectively, rank these scenarios on the basis of the phase shift in the refracted ray. Rank from largest to smallest. To rank items as equivalent, overlap them.
(a) n1,water=1.33
n2,air=1.00
(b) n1,water=1.33
n2,quartz=1.46
(c) n1,water=1.33
n2,diamond=2.42
(d) n1,air=1.00
n2,quartz=1.46
(e) n1,benzene=1.50
n2,water=1.33
(f) n1,air=1.00
n2,water=1.33

Answer 1

Answer:

$c>d>f=a>b>e$

Explanation:

When a pair of medial has greater difference between the their individual refractive indices with respect to vacuum then it has a greater deviation between the refracted ray and the incident ray.

According to the Snell's law:

$\rm refractive\ index\ (n)=\frac{speed\ of\ light\ in\ the\ incident\ medium}{speed\ of\ light\ in\ the\ refracted\ medium}$

a)

$n_1-n_2=1.33-1.00\\=0.33$

b)

$n_2-n_1=1.46-1.33$

$=0.23$

c)

$n_2-n_1=2.42-1.33\\=1.09$

d)

$n_2-n_1=1.46-1.00\\=0.46$

e)

$n_1-n_2=1.50-1.33\\=0.17$

f)

$n_2-n_1=1.33-1.00\\=0.33$

$c>d>f=a>b>e$