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Jobisdone [24]
2 years ago
5

All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is

in a state known as _____.
Physics
2 answers:
Digiron [165]2 years ago
8 0
All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as constant velocity. The bullet is moving at a constant value of velocity. Acceleration is the rate of velocity so having zero acceleration would mean that there is no change in velocity per unit of time.<span />
trasher [3.6K]2 years ago
8 0

Collision


All forces on the bullets cancel so that the net force on a bullet is zero, which means the bullet has zero acceleration and is in a state known as a colision


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an ice skater, standing at rest, uses her hands to push off against a wall. she exerts an average force on the wall of 120 N and
natulia [17]

Answer:

The skater's speed after she stops pushing on the wall is 1.745 m/s.

Explanation:

Given that,

The average force exerted on the wall by an ice skater, F = 120 N

Time, t = 0.8 seconds

Mass of the skater, m = 55 kg

It is mentioned that the initial sped of the skater is 0 as it was at rest. The change in momentum of skater is :

\Delta p=m(v-u)\\\\\Delta p=mv

The change in momentum is equal to the impulse delivered. So,

J=\Delta p=F\times t\\\\mv=F\times t\\\\v=\dfrac{Ft}{m}\\\\v=\dfrac{120\times 0.8}{55}\\\\v=1.745\ m/s

So, the skater's speed after she stops pushing on the wall is 1.745 m/s.                      

4 0
2 years ago
Calculate the partial pressure of ozone at 441 ppb if the atmospheric pressure is 0.67 atm.
exis [7]

Answer:

2.95\times 10^{-7}atm

Explanation:

We are given that

Atmospheric pressure=0.67 atm

We have to calculate the partial pressure of ozone at 441 ppb .

Partial pressure of ozone=\frac{441\times atmospheric\;pressure}{10^9} atm

Substitute the value of atmospheric pressure

Then, we get

Partial pressure of ozone=\frac{441\times 0.67}{10^9}=2.95\times 10^{-7} atm

Hence, the partial pressure of ozone=2.95\times 10^{-7}atm

5 0
2 years ago
A 85-kg person stands on one leg and 90% of the weight is supported by the upper leg connecting the knee and hip joint – the fem
Maru [420]

Answer:

The bone is compressed to 4.213*10⁻⁶ m.

Explanation:

Given that ,

Mass of the person M = 85 kg,

Length of femur L =0.65 m

Radius of femur r = 0.02 m

To find,

Compression of the bone l = ?

The Young's Modulus is given by Y= \frac{FL}{lA}

Young's modulus of human femur bone is Y = 9.4 *10⁹ Pa

Rearranging formula ,

l =\frac{FL}{YA}

Weight supported by femur bone is 85 *0.9 =76.5 Kg

Area = π r² =3.14* (0.02)² = 0.001256 m

The length of compressed bone is  

l =\frac{76.5*0.65}{9.4GPa*0.001256} =  \frac{49.725}{0.0118GPa} =4213.89 *10⁻⁹

l = 4.213*10⁻⁶ m  

The bone is compressed to 4.213*10⁻⁶ m.

4 0
2 years ago
The position (in radians) of a car traveling around a curve is described by Θ (t) = t 3 - 2t 2 - 4t + 10 where t (in seconds). W
FromTheMoon [43]

Answer:\alpha =30-4=26 rad/s^2

Explanation:

Given

Position of a car is  given by

\theta =t^3-2t^2-4t+10

and angular speed is \frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

angular acceleration is

\frac{\mathrm{d^2} \theta }{\mathrm{d} t^2}=\alpha

\alpha =6t-4

at t=5 s

\alpha =30-4=26 rad/s^2

4 0
2 years ago
The diagram shows the field lines near the poles, X and Y, of two magnets.
Basile [38]

<em>Answer:  I think it is C</em>

Explanation: sorry if it wrong

3 0
2 years ago
Read 2 more answers
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