Question

A 6.0-ω and a 12-ω resistor are connected in parallel across an ideal 36-v battery. What power is dissipated by the 6.0-ω resistor?

Answer 1

Answer:

P = 216 Watts  

Explanation:

Given that,

Resistance 1, $R_1=6\ \Omega$

Resistance 2, $R_2=12\ \Omega$

Voltage, V = 36 V

We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.      

Firstly, lets find current of the 6 ohms resistor such that,

V = IR

$I=\dfrac{V}{R}\\\\I=\dfrac{36}{6}\\\\I=6\ A$

The power dissipated by 6 ohms resistor is given by :

$P=I^2R$

$P=6^2\times 6\\\\P=216\ W$

So, the power dissipated across 6 ohm resistor is 126 watts.