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1 year ago

14

A 6.0-Ï‰ and a 12-Ï‰ resistor are connected in parallel across an ideal 36-v battery. What power is dissipated by the 6.0-Ï‰ res

istor?

1 answer:

Elena L [17]1 year ago

8 0

Answer:

P = 216 Watts

Explanation:

Given that,

Resistance 1, $R_1=6\ \Omega$

Resistance 2, $R_2=12\ \Omega$

Voltage, V = 36 V

We need to find the power dissipated by the 6 ohms resistor. In case of parallel circuit, voltage throughout the circuit is same while the current is different.

Firstly, lets find current of the 6 ohms resistor such that,

V = IR

$I=\dfrac{V}{R}\\\\I=\dfrac{36}{6}\\\\I=6\ A$

The power dissipated by 6 ohms resistor is given by :

$P=I^2R$

$P=6^2\times 6\\\\P=216\ W$

So, the power dissipated across 6 ohm resistor is 126 watts.

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A motion sensor is used to create the graph of a student’s horizontal velocity as a function of time as the student moves toward

Marrrta [24]

Answer:

Position xf is farther away from the sensor than x0, and ax is negative

Explanation:

Area of trapezoidal are=

= $\frac{1}{2} *(1.5+0.75)+\frac{1}{2} (1+0.75)(-0.5)$

= $\frac{1}{2} *(2.25-1.75*0.5)$

=0.6875 m

As the area is positive therefore displacement from xo is positive

ax=(change in velocity)/(Time)

ax= $\frac{-0.5-0}{3} =-\frac{1}{6} ms2$

3 0

2 years ago

Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m. At the bottom of

adoni [48]

Answer:

3311N

Explanation:

r = radius = 600m

V = speed = 150m/s

Mass = weight = 70kg

The weight of pilot when calculated due to circular motion

W = tv

Fv = mv²/r

Fv = 70x150²/600

Fv = 79x22500/600

= 15750000/600

= 2625N

Real Weight of the pilot = m x g

= 70 x 9.8

= 686N

The apparent Weight is calculated by

Mv²/r + mg

= 2625N + 686N

= 3311 N

Therefore the apparent Weight is 3311N

6 0

1 year ago

Study the free body diagram above. Which scenario below can best be described with this free body diagram? A. a cup is at rest o

vekshin1

Answer: D

Explanation:

5 0

2 years ago

An object has a position given by r = [2.0 m + (2.00 m/s)t] i + [3.0 m − (1.00 m/s^2)t^2] j, where quantities are in SI units. W

lidiya [134]

Answer: 1 m/s

Explanation:

We have an object whose position $r$ is given by a vector, where the components X and Y are identified by the unit vectors $i$ and $j$ (where each unit vector is defined to have a magnitude of exactly one):

$r=[2 m + (2 m/s) t] i + [3 m - (1 m/s^{2})t^{2}] j$

On the other hand, velocity is defined as the variation of the position in time:

$V=\frac{dr}{dt}$

This means we have to derive $r$ :

$\frac{dr}{dt}=\frac{d}{dt}[2 m + (2 m/s) t] i + \frac{d}{dt}[3 m - (1 m/s^{2})t^{2}] j$

$\frac{dr}{dt}=(2 m/s) i - (\frac{1}{2} m/s^{2} t) j$ This is the velocity vector

And when $t=2s$ the velocity vector is:

$\frac{dr}{dt}=(2 m/s) i - (\frac{1}{2} m/s^{2} (2 s)) j$

$\frac{dr}{dt}=2 m/s i - 1m/s j$ This is the velocity vector at 2 seconds

However, the solution is not complete yet, we have to find the module of this velocity vector, which is the speed $S$ :

$S=\sqrt {-1 m/s j + 2 m/s i}$

$S=\sqrt {1 m/s}$

Finally:

$S=1 m/s$ This is the speed of the object at 2 seconds

6 0

1 year ago

1. A 3.0 kg mass is tied to a rope and swung in a horizontal circle. If the velocity of the mass is 4.0 ms and

saul85 [17]

10.67m/s²

32N

Explanation:

Given parameters:

Mass of the body = 3kg

velocity of the mass = 4m/s

radius of circle = 0.75m

Unknown:

centripetal acceleration = ?

centripetal force = ?

Solution:

The centripetal force is the force that keeps a radial body in its circular motion. It is directed inward:

Centripetal acceleration = $\frac{v^{2} }{r}$

v is the velocity of the body

r is the radius of the circle

putting in the parameters:

Centripetal acceleration = $\frac{4^{2} }{0.75}$

Centripetal acceleration = 10.67m/s²

Centripetal force = m $\frac{v^{2} }{r}$

m is the mass

Centripetal force = mass x centripetal acceleration

= 3 x 10.67

= 32N

learn more:

Acceleration brainly.com/question/3820012

#learnwithBrainly

4 0

2 years ago