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kkurt [141]
2 years ago
13

Use the terms "force", "weight", "mass", and "inertia" to explain why it is easier to tackle a 220 lb football player than a 288

lb football player.
Physics
2 answers:
Tomtit [17]2 years ago
7 0
<span><u>Answer </u>
The mass of 220 lb football has less than 288 lb football. So, it will be easier to move it since it will require less force. The heavy football will have a bigger momentum. Since 288 lb has more weight than 220 lb, it will have bigger inertia making it difficult for the players to stop it.
This makes it easier to tackle 220 lb football than 288 lb football. 
</span>
Flura [38]2 years ago
6 0

There are several scientific aspects that require to be comprehended beforehand;

Force = mass * acceleration

Weight = mass * gravity (10m/s)

Momentum = mass * velocity

Inertia is a property of mass which is the tendency of an object to remain at constant velocity unless acted upon by an outside force.

Based on these formulae, it is evident that if the 220lb player and 288lb player are moving at the same velocity, the 288lb player has more inertia and momentum than the 22olb. Therefore, it would require more force (hence energy) to change the direction or the speed (in tackling) of the player with 288lb compared with what would be required on the 220lb player.

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Vilka [71]
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N
8 0
2 years ago
Define kinetic energy and thermal energy. Describe what happens to each as the temperature of a substances increases.
Margaret [11]

Answer:

Kinetic energy is the amount of energy a object has while it's in motion, and thermal energy is heat energy. In this case when the heat rises in substances for example a solid it will transform into a liquid causing the molecules to move faster which is a increase of kinetic energy.

Explanation:

4 0
2 years ago
Read 2 more answers
When the mass of the bottle is 0.125 kg, the KE is______ kg m2/s2.
tensa zangetsu [6.8K]
Answers are:
(1) KE = 1 kg m^2/s^2
(2) KE = 2 kg m^2/s^2
(3) KE = 3 kg m^2/s^2
(4) KE = 4 kg m^2/s^2


Explanation:

(1) Given mass = 0.125 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.125 * (16)
KE = 1 kg m^2/s^2

(2) Given mass = 0.250 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.250 * (16)
KE = 2 kg m^2/s^2

(3) Given mass = 0.375 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.375 * (16)
KE = 3 kg m^2/s^2

(4) Given mass = 0.500 kg
speed = 4 m/s

Since Kinetic energy = (1/2)*m*(v^2)

Plug in the values:
Hence:
KE = (1/2) * 0.5 * (16)
KE = 4 kg m^2/s^2
5 0
2 years ago
Honey bees can acquire a small net charge on the order of 1 pC as they fly through the air and interact with plants. Estimate th
Inessa [10]

Answer:

F = 2.01*10^-16N -^k

Explanation:

In order to calculate the magnetic force perceived by the bee, you use the following formula:

F=qv\ X\ B            (1)

q: charge of the bee = 1pC = 1*10^-12 C

The average speed of a bee and the magnetic field of the earth are:

v = 6.70m/s

B = 30*10^-6 T

The bee is flying to the west (-^i). You consider that the magnetic field direction is to the north (^j). Then, the direction of the magnetic force is:

-^i X ^j = -^k

You replace the values of the parameters in the equation (1), in order to calculate the magnitude of the force:

|F|=qvB=(1*10^{-12}C)(6.70m/s)(30*10^{-6}T)=2.01*10^{-16}N

The magnetic force perceived by the bee is 2.01*10^-16N in the -^k direction, that is, toward the ground

5 0
2 years ago
Given an electron beam whose electrons have kinetic energy of 10.0 kev , what is the minimum wavelength λmin of light radiated b
kolbaska11 [484]
To answer the problem we would be using this formula which isE = hc/L where E is the energy, h is Planck's constant, c is the speed of light and L is the wavelength 
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= 1.240x10^-10 m 

= 1.240x10^-1 nm
3 0
2 years ago
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