Answer:
149.34 Giga meter is the distance d from the center of the sun at which a particle experiences equal attractions from the earth and the sun.
Explanation:
Mass of earth = m = 
Mass of Sun = M = 333,000 m
Distance between Earth and Sun = r = 149.6 gm = 1.496\times 10^{11} m[/tex]
1 giga meter = 
Let the mass of the particle be m' which x distance from Sun.
Distance of the particle from Earth = (r-x)
Force between Sun and particle:

Force between Sun and particle:

Force on particle is equal:
F = F'

= ±577.06
Case 1:

x = 
Acceptable as the particle will lie in between the straight line joining Earth and Sun.
Case 2:

x = 
Not acceptable as the particle will lie beyond on line extending straight from the Earth and Sun.
As per given conditions there are two directions along which forces are acting
1. Net force along left direction is given as

2. Net force towards right direction is given as

now since the two forces here in opposite direction so here we will have net force given as



so here net forces must be 440 N towards right
Answer:
Angular acceleration
rad/s^2
Explanation:
Given
Initial Angular velocity (w1)
rad/s
Final Angular velocity (w2)
rad/s
Time taken to change velocity from w1 to w2
seconds
Angular acceleration is equal to the change in angular velocity to the time taken for making thing change
Hence, Angular acceleration
rad/s^2
Answer:
Explanation:
My speed after the interaction will depend upon the impulse the ball will make on me . Now impulse can be expressed as follows
Impulse = change in momentum
change in momentum in the ball will be maximum when the ball bounces back with the same velocity which can be shown as follows
change in momentum = mv - ( - mv ) = 2mv
So when ball is bounced back with same velocity , it suffers greatest impulse from my hand . In return , it reacts with the same impulse on my hand pushing me with greatest impulse according to third law of motion. this maximizes my speed after the interaction.