Answer:
2 x 10⁻³ volts
Explanation:
B = magnetic of magnetic field parallel to the axis of loop = 1 T
= rate of change of area of the loop = 20 cm²/s = 20 x 10⁻⁴ m²
θ = Angle of the magnetic field with the area vector = 0
E = emf induced in the loop
Induced emf is given as
E = B
E = (1) (20 x 10⁻⁴ )
E = 2 x 10⁻³ volts
E = 2 mV
The angular velocity of the orbit about the sun is:
w = 1 rev / year = 1 rev / 3.15 × 10^7 s
Now in 1 rev there is 360° or 2π rad, therefore:
w = 2π rad / 3.15 × 10^7 s
To convert in linear velocity, multiply the rad /s by the
radius:
v = (2π rad / 3.15 × 10^7 s) * 93,000,000 miles
<span>v = 18.55 miles / s = 29.85 km / s</span>
gravitational potential energy is given by formula

here we need to compare the gravitational potential energy of stone 2 with respect to stone 1
so we will say


given that

now we have
