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1 year ago

Unlike acceleration and velocity, speed does not need to specify

1 answer:

4 0

Unlike acceleration and velocity, speed does not need to specify the direction of motion. Speed is a scalar quality.

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A 120-kg refrigerator that is 2.0 m tall and 85 cm wide has its center of mass at its geometrical center. You are attempting to

Mademuasel [1]

To solve this problem it is necessary to apply the concepts related to Force of Friction and Torque given by the kinematic equations of motion.

The frictional force by definition is given by

$F= \mu mg$

Our values are here,

$\mu=0.3$

$m=120kg$

$g=9.8m/s^2$

Replacing,

$F=0.30*120*9.8 = 352.8N$

Consider the center of mass of the body half its distance from the floor, that is d = 0.85 / 2 = 0.425m. The torque about the lower farther corner of the refrigerator should be zero to get the maximum distance, then

$F*x = mg*d$

Re-arrange for x,

$x= \frac{mg*d}{F}$

$x= \frac{mg*d}{\mu mg}$

$x= \frac{d}{\mu}$

$x= \frac{0.425}{0.3}$

$x = 1.42m$

Then we can conclude that 1.42m is the distance traveled before turning.

6 0

2 years ago

A ball is thrown into the air and follows the parabolic path indicated by the dashed line. Use the arrows provided to indicate t

avanturin [10]

Answer:

Trajectory is the path of a projectile in air. Any tangential to the curve shows it velocity and the slope of the tangential line will be it acceleration.

Explanation:

5 0

2 years ago

During an experiment of momentum, trolley, X, of mass (2.34 ± 0.01) kg is moving away from another trolley, Y, of mass (2.561 ±

Alla [95]

Answer:

P = 1 (14,045 ± 0.03 ) k gm/s

Explanation:

In this exercise we are asked about the uncertainty of the momentum of the two carriages

Δ (Pₓ / Py) =?

Let's start by finding the momentum of each vehicle

car X

Pₓ = m vₓ

Pₓ = 2.34 2.5

Pₓ = 5.85 kg m

car Y

Py = 2,561 3.2

Py = 8,195 kgm

How do we calculate the absolute uncertainty at the two moments?

ΔPₓ = m Δv + v Δm

ΔPₓ = 2.34 0.01 + 2.561 0.01

ΔPₓ = 0.05 kg m

Δ $P_{y}$ = m Δv + v Δm

ΔP_{y} = 2,561 0.01+ 3.2 0.001

ΔP_{y} = 0.03 kg m

now we have the uncertainty of each moment

P = Pₓ / $P_{y}$

ΔP = ΔPₓ/P_{y} + Pₓ ΔP_{y} / P_{y}²

ΔP = 8,195 0.05 + 5.85 0.03 / 8,195²

ΔP = 0.006 + 0.0026

ΔP = 0.009 kg m

The result is

P = 14,045 ± 0.039 = (14,045 ± 0.03 ) k gm/s

7 0

2 years ago

Find the change in volume for a metallic dental filling due to the difference between body temperature (37.0°C) and the temperat

mihalych1998 [28]

Answer:

The change in volume for a metallic dental filling due to the temperature difference is <u>0.1143 mm</u>.

Explanation:

Given:

Temperature of the body is, $T_1=37\ \°C$

Temperature of the ice-cream is, $T_2=-6.2\ \°C$

Initial volume of the filling is, $V=21.0\ mm^3$

Coefficient of thermal expansion is, $\alpha =42.0\times 10^{-6}\ K^{-1}$

We know that the coefficient of volume expansion is related to thermal expansion as:

$\gamma=3\alpha=3\times 42.0\times 10^{-6}=126\times 10^{-6}\ K^{-1}$

Now, change in volume for a metallic dental filling is given as:

$\Delta V=V\gamma(T_1-T_2)\\\Delta V=21\times 126\times 10^{-6}(37-(-6.2))\\\Delta V=2646\times(37+6.2)\times 10^{-6}\\\Delta V=2646\times 43.2\times 10^{-6}\\\Delta V=0.1143\ mm^3$

Therefore, the change in volume for a metallic dental filling due to the temperature difference is 0.1143 mm.

5 0

2 years ago

A 34-cm-tall, 6.0-cm-diameter cylindrical beaker is filled to its brim with water.What is the downward force of the water on the

Solnce55 [7]

h = height of the beaker = 34 cm = 0.34 m

ρ = density of water in the beaker = 1000 kg/m³

g = acceleration due to gravity = 9.8 m/s²

P₀ = atmospheric pressure = 101325 pa

P = pressure at the bottom of the beaker

Pressure at the bottom of the beaker is given as

P = P₀ + ρ g h

inserting the values

P = 101325 + (1000) (9.8) (0.34)

P = 104657 Pa

d = diameter of cylindrical beaker = 6 cm = 0.06 m

A = area of the bottom of the beaker = (0.25)πd² = (0.25) (3.14) (0.06)² = 0.00283 m²

Downward force of the water on the bottom of the beaker is given as

F = PA

F = (104657) (0.00283)

F = 296.2 N

3 0

2 years ago