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patriot [66]
1 year ago
15

In an experiment, Mary compares a collision of two 1-kilogram steel balls with a collision of two 1-kilogram foam rubber balls.

She makes sure that, except for the material, the two collisions are the same. Mary finds that the force of impact of the steel ball collision is greater than the force of impact of the foam rubber ball collision.
From her force measurements, Mary concludes that the foam rubber balls’ acceleration during the collision was (BLANK) the steel balls’ acceleration. She concludes that the collision between the foam rubber balls is an collision.

BLANK 1
Greater than
Less than
The same as
Physics
2 answers:
IgorC [24]1 year ago
8 0
1. Greater then
<span>2. Inelastic</span>
Lynna [10]1 year ago
4 0

Complete sentence:

Mary concludes that the foam rubber balls’ acceleration during the collision was less than the steel balls’ acceleration. She concludes that the collision between the foam rubber balls is an inelastic collision.

Explanation:

Mary find that the force of impact on the steel ball is greater than the force on the foam rubber ball. According to Newton's second law, the acceleration of each ball is proportional to the force applied:

a=\frac{F}{m}

where F is the force applied and m is the mass of the ball. The two balls have same mass (1 kg), so since the force on the steel ball is greater, the acceleration of the steel ball is also greater.

The collision between the foam rubber balls is inelastic: it means that only the total momentum is conserved, while the total kinetic energy is not conserved.

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A is the acceleration

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From the graph a = 4/3 m/s2

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D = 6 m

3 0
1 year ago
Does the surrounding air become warm or cool when vapour phase of H2O condenses? Explain
mel-nik [20]
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8 0
2 years ago
Suppose that a rectangular toroid has 2,000 windings and a self-inductance of 0.060 H. If the height of the rectangular toroid i
andrey2020 [161]

Answer:

0.01154 A

Explanation:

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3 0
2 years ago
(a) when rebuilding her car's engine, a physics major must exert 300 n of force to insert a dry steel piston into a steel cylind
Vilka [71]
There are some missing data in the text of the problem. I've found them online:
a) coefficient of friction dry steel piston - steel cilinder: 0.3
b) coefficient of friction with oil in between the surfaces: 0.03

Solution:
a) The force F applied by the person (300 N) must be at least equal to the frictional force, given by:
F_f = \mu N
where \mu is the coefficient of friction, while N is the normal force. So we have:
F=\mu N
since we know that F=300 N and \mu=0.3, we can find N, the magnitude of the normal force:
N= \frac{F}{\mu}= \frac{300 N}{0.3}=1000 N

b) The problem is identical to that of the first part; however, this time the coefficienct of friction is \mu=0.03 due to the presence of the oil. Therefore, we have:
N= \frac{F}{\mu}= \frac{300 N}{0.03}=10000 N
8 0
1 year ago
A stunt pilot weighing 0.70 kN performs a vertical circular dive of radius 0.80 km.At the bottom of the dive, the pilot has a sp
Yuliya22 [10]

Answer:

 Force plane exert on pilot  = 4270 N

Explanation:

first convert radius and speed to ms

using formula from force we know that

mass = weight/ gravity =  700 N/ 9.8N/kg=  71.4 kg

Fc=  N-mg

N= Fc+ mg                  As Fc = mv²/R

N= mv²/R + mg

taking m common

N= m( v²/R +g)

   = 71.4( (200)²/ 800 + 9.8 )

 Force  = 4270 N

3 0
2 years ago
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