<h2>The flux through the infinite charged wire along the central axis of a cylindrical surface of radius r and length l is ∅E = E x 2πrl </h2>
Explanation:
let us consider a thin infinitely long straight wire having a uniform charge density λ Cm⁻¹.To determine the field at a distance r from the line charge , we have cylindrical gaussian surface of radius r, length l,and with its axis along the line charge. it has curved surface S₁ , and flat circular ends S₂ and S₃. Obviously, dS₁//E, dS₂ ⊥E , and dS₃ ⊥ E , so, only the curved surface contributes towards the total flux.
∅E = ∫ E.dS = ∫E.dS₁ +∫E.dS₂ +∫E.dS₃
= ∫EdS₁ cos0⁰ +∫EdS₂ cos 90⁰ +∫Eds₃ cos 90⁰
= E∫ds₁₁ +0+0
= E x area of curved surface
∅E = E x 2πrl
A. a<span> = 1.3 m/s^2</span><span>; </span>FN<span> = 63.1 N</span>
Answer:
(a): The frequency of the waves is f= 0.16 Hz
Explanation:
T/4= 1.5 s
T= 6 sec
f= 1/T
f= 0.16 Hz (a)
Answer: t-trees?
i couldn't find anything on this topic but the only thing i could think of was trees, maybe if you go to a history website you can find a answer there :)
hope i helped a little :)
Answer:

Explanation:
Given data
Length h=2.0m
Angle α=25°
To find
Speed of bob
Solution
From conservation of energy we know that:
