m = mass = 5 kg
= initial velocity = 100 m/s
= final velocity = ?
I = impulse = 30 Ns
Using the impulse-change in momentum equation
I = m( -
)
30 = 5 ( - 100)
= 106 m/s
Determine the maximum weight of the bucket that the wire system can support so that no single wire develops a tension exceeding
1 answer:
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Answer:
The flux through the surface of the cube is
Solution:
As per the question:
Edge of the cube, a = 8.0 cm =
Volume Charge density,
Now,
To calculate the electric flux:
(1)
where
= electric flux
= permittivity of free space
Volume Charge density for the given case is given by the formula:
(2)
Volume of cube,
Thus
Thus from eqn (2), the total charge is given by:
Now, substitute the value of 'q' in eqn (1):
When air is blown into the open pipe,
L =
where nis any integral number 1,2,3,4 etc. and λ is the wavelength of the oscillation
⇒λ=
Note here that n=1 is for fundamental, n=2 is first harmonic and so on..
⇒ third harmonic will be n=4
Given L=6m, n=4, solving for λ we get:
λ= =3m
Relationship of frequency(f), velocity of sound (c) and wavelength(λ) is:
c=f.λ Or f=
⇒f=
≈115 Hz