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2 years ago

suppose that 273 g of one of the substances listed above displaces 26 mL of water. What is the substance?

2 answers:

6 0

<span>The unknown substance is silver. I don't see a list of available substances, but let's see if there's something reasonable available that will match. First, let's calculate the density of the unknown substance. Density is mass per volume, so 273 g / 26 mL = 10.5 g/mL Looking up a list of elements sorted by density, I see the following: 10.07 Actinium 10.22 Molybdenum 10.5 Silver 11.35 Lead And silver at 10.5 g/ml is a very nice match for the unknown substances' density of 10.5 g/ml.</span>

nignag [31]2 years ago

5 0

I dont see your list anywhere, but if silver is on your list,, that would be the answer,

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2 years ago

A truck collides with a car on horizontal ground. At one moment during the collision, the magnitude of the acceleration of the t

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The magnitude of the acceleration of the car is 35.53 m/s²

Explanation:

Given;

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mass of the car, $m_c$ = 890 kg

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Magnitude of force exerted by the truck = Magnitude of force exerted by the car.

The force exerted by the car occurs in the opposite direction.

$F_c = -F_t\\\\m_ca_c = -m_t a_t\\\\a_c =- \frac{m_ta_t}{m_c} \\\\a_c = -\frac{2490 \times 12.7}{890} \\\\a_c = - 35.53 \ m/s^2$

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2 years ago

A block spring system oscillates on a frictionless surface with an amplitude of 10\text{ cm}10 cm and has an energy of 2.5 \text

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The energy of the system is 15 J.

Explanation:

Given that,

Energy E = 2.5 J

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We need to calculate the spring constant

Using formula of mechanical energy of the system

$E=\dfrac{1}{2}kA^2$

Put the value into the formula

$2.5=\dfrac{1}{2}k\times(10\times10^{-2})^2$

$k=\dfrac{2.5\times2}{(10\times10^{-2})^2}$

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2 years ago

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